#include <bits/stdc++.h>
#define PII pair<int, int>
using namespace std;
const int N = 1e5 + 3;
const int mod = 998244353;

inline int add(int x, int y) {x += y; return x >= mod ? x - mod : x;}
inline int del(int x, int y) {x -= y; return x < 0 ? x + mod : x;}
inline void Add(int &x, int y) {x = add(x, y);}
inline void Del(int &x, int y) {x = del(x, y);}
inline int read() {
    char ch = getchar(); int x = 0;
    while (!isdigit(ch)) {ch = getchar();}
    while (isdigit(ch)) {x = (x << 3) + (x << 1) + ch - 48; ch = getchar();}
    return x;
}

int T, c, p, q, L, cnt, pos[10][10], pw[N][10];
PII id[10];

inline int calc(int x, int y, int k) {return 1ll * pw[x][id[k].first] * pw[y][id[k].second] % mod;}

namespace subtask1 {
    const int N1 = 1005;

    int f[N1][N1], g[N1][N1][10];
    
    bool check() {return L <= 1000;}

    void solve() {
        f[0][0] = 1;
        for (int i = 0; i < cnt; ++i) g[0][0][i] = calc(0, 0, i);
        for (int i = 0; i <= L; ++i)
            for (int j = 0; j <= L; ++j) {
                if (i == 0 && j == 0) continue;
                if (i) Add(f[i][j], f[i - 1][j]);
                if (j) Add(f[i][j], f[i][j - 1]);
                for (int k = 0; k < cnt; ++k) {
                    if (i) Add(g[i][j][k], g[i - 1][j][k]);
                    if (j) Add(g[i][j][k], g[i][j - 1][k]);
                    if (j <= i) Add(g[i][j][k], 1ll * f[i][j] * calc(i, j, k) % mod);
                }
            }
        int n, m, ans;
        while (T--) {
            n = read(); m = read(); ans = 0;
            for (int i = 0; i < cnt; ++i) Add(ans, 1ll * g[n][m][i] * read() % mod);
            printf("%d\n", ans);
        }
    }
}

int main() {
    T = read(); c = read(); p = read(); q = read(); L = read(); L = max(L, L + c);
    for (int i = 0; i <= p; ++i)
        for (int j = 0; j <= q; ++j)
            id[pos[i][j] = cnt++] = make_pair(i, j);
    for (int i = 0; i <= L; ++i) {
        pw[i][0] = 1;
        for (int j = 1; j <= max(p, q); ++j) pw[i][j] = 1ll * pw[i][j - 1] * i % mod;
    }
    if (subtask1 :: check()) subtask1 :: solve();
    return 0;
}