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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#300891#7967. 二进制defyers#ML 366ms144464kbC++203.0kb2024-01-08 23:30:202024-01-08 23:30:20

Judging History

你现在查看的是最新测评结果

  • [2024-01-08 23:30:20]
  • 评测
  • 测评结果:ML
  • 用时:366ms
  • 内存:144464kb
  • [2024-01-08 23:30:20]
  • 提交

answer

#include "bits/stdc++.h"
using namespace std;

#pragma GCC optimize("Ofast")
#pragma GCC target("avx2")

using ll = long long;
using LL = long long;

const int N = 1 << 20;

struct BIT{
	int bit[N];
	void add(int p, int x){ for(int i = p; i < N; i += i & -i) bit[i] += x; }
	int qry(int p){ int ret = 0; for(int i = p; i; i -= i & -i) ret += bit[i]; return ret; }
	int bs(int v){ int ret = 0, s = 0; for(int j = 19; j >= 0; j--) if(ret + (1 << j) < N && s + bit[ret + (1 << j)] < v) ret += (1 << j), s += bit[ret]; return ret + 1; }
} bit;

int n; 
bool a[N];
int l[N], r[N];
vector<int> S[N], T[N];

int L[20], R[20];
void rem(int x){
	int sl = 0, sr = 0;
	for(int y = l[x], tr = 0; y != 0 && tr < 20; tr++){
		L[tr] = y; y = l[y]; sl++;
	}
	for(int y = r[x], tr = 0; y != n + 1 && tr < 20; tr++){
		R[tr] = y; y = r[y]; sr++;
	}

	for(int i = sl - 1; i >= 0; i--){
		if(!a[L[i]]) continue;
		int v = 1;
		for(int j = i - 1; j >= 0; j--){
			v = v * 2 + a[L[j]];
		}
		// NOT choose middle
		int u = v;
		for(int j = 0; j < sr; j++){
			u = u * 2 + a[R[j]];
			if(u >= N) break;
			S[u].push_back(L[i]);
		}
		// DOES choose middle
		u = v * 2 + a[x];
		if(u < N) T[u].push_back(L[i]);
		// cout << "R " << u << ' ' << L[i] << endl;
		for(int j = 0; j < sr; j++){
			u = u * 2 + a[R[j]];
			if(u >= N) break;
			// cout << "ADD " << u << ' ' << L[i] << endl;
			T[u].push_back(L[i]);
		}
	}

	if(a[x]){
		int u = a[x];
		T[u].push_back(x);
		for(int j = 0; j < sr; j++){
			u = u * 2 + a[R[j]];
			if(u >= N) break;
			T[u].push_back(x);
		}
	}
	bit.add(x, 1);
	l[r[x]] = l[x];
	r[l[x]] = r[x];
}

int len(int l){
	int x = 0;
	while(l){
		x++;
		l /= 2;
	}
	return x;
}

void solve(int TC) {
	cin >> n;
	for(int i = 0; i <= n + 1; i++){
		l[i] = i - 1;
		r[i] = i + 1;
	}
	l[0] = 0, r[n + 1] = n + 1;
	string s; cin >> s;
	for(int i = 1; i <= n; i++){
		a[i] = s[i - 1] == '1';
	}

	for(int i = 1; i <= n; i++){
		if(a[i] == 0) continue;
		int v = 0;
		for(int j = i; j < i + 20 && j <= n; j++){
			v = v * 2 + a[j];
			S[v].push_back(i);
		}
	}

	// for(int l = 1; l <= n; l++){
	// 	for(auto u : S[l]) cout << u << ' '; cout << '\n';
	// }

	for(int l = 1; l <= n; l++){
		sort(S[l].begin(), S[l].end());
		sort(T[l].begin(), T[l].end());
		int cnt = S[l].size() - T[l].size();
		if(cnt == 0){
			cout << -1 << ' ' << 0 << '\n';
		}else{
			int idx = 0;
			assert(cnt > 0);
			// cout << "S T" << endl;
			// for(auto x : S[l]) cout << x << ' '; cout << '\n';
			// for(auto x : T[l]) cout << x << ' '; cout << '\n';
			while(idx < T[l].size() && S[l][idx] == T[l][idx]){
				++idx;
			}
			int pos = S[l][idx];
			cout << pos - bit.qry(S[l][idx] - 1) << ' ' << cnt << '\n';
			for(int j = 0; j < len(l); j++){
				rem(pos); pos = r[pos];
			}
		}

		S[l].clear(); T[l].clear();
	}
}

int32_t main() {
	cin.tie(0)->sync_with_stdio(0);
	cout << fixed << setprecision(10);

	int t = 1;
	// cin >> t;

	for (int i = 1; i <= t; i++) {
		solve(i);
	}
}

详细

Test #1:

score: 100
Accepted
time: 3ms
memory: 60164kb

input:

20
01001101101101110010

output:

2 11
5 5
4 5
11 1
4 2
7 1
-1 0
-1 0
-1 0
-1 0
-1 0
-1 0
-1 0
-1 0
-1 0
-1 0
-1 0
-1 0
-1 0
-1 0

result:

ok 20 lines

Test #2:

score: 0
Accepted
time: 366ms
memory: 144464kb

input:

1000000
1111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111111...

output:

1 1000000
-1 0
1 999998
-1 0
-1 0
-1 0
1 999995
-1 0
-1 0
-1 0
-1 0
-1 0
-1 0
-1 0
1 999991
-1 0
-1 0
-1 0
-1 0
-1 0
-1 0
-1 0
-1 0
-1 0
-1 0
-1 0
-1 0
-1 0
-1 0
-1 0
1 999986
-1 0
-1 0
-1 0
-1 0
-1 0
-1 0
-1 0
-1 0
-1 0
-1 0
-1 0
-1 0
-1 0
-1 0
-1 0
-1 0
-1 0
-1 0
-1 0
-1 0
-1 0
-1 0
-1 0
-1 0
-1 0...

result:

ok 1000000 lines

Test #3:

score: -100
Memory Limit Exceeded

input:

1000000
1111111101011101110011011111111111111110110011110111011100111001011011011110101110111111111111111111111111011111101111110110111111111110111010111111100110011101101110011111111101111110111111111110111111111111011011110110111101101101110101100111111111001010111111111111010111011111111011110111...

output:

1 800681
7 159535
1 641144
13 31730
5 127804
5 127761
1 513379
542 6405
25 25324
54 25337
5 102464
30 25561
17 102196
17 102484
1 410890
2647 1324
618 5080
20 5103
99 20219
304 4894
89 20442
21 20308
15 82150
810 5135
82 20422
158 20309
20 81880
83 20567
39 81909
40 82119
1 328769
4222 267
2829 1056...

result: