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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#298989 | #7904. Rainbow Subarray | ucup-team203# | RE | 887ms | 17132kb | C++20 | 3.1kb | 2024-01-06 16:26:26 | 2024-01-06 16:26:26 |
Judging History
answer
#include <bits/stdc++.h>
#include <ext/pb_ds/tree_policy.hpp>
#include <ext/pb_ds/assoc_container.hpp>
using namespace __gnu_pbds;
using i64 = long long;
using namespace std;
const int N = 1e6 + 5;
// const int B = 340;
// const int M = 5e3 + 5;
// const int base = 1753591;
// const int mod = 998244353;
const int mod = 1e9 + 7;
// const double pi = acos(-1);
int n, a[N];
i64 lim;
struct node
{
i64 sum;
int l, r, siz;
node operator+(node tmp)
{
node res;
res.sum = sum + tmp.sum;
res.siz = siz + tmp.siz;
return res;
}
} st[N << 2];
#define lc st[cur].l
#define rc st[cur].r
int tot, root;
void pushup(int cur)
{
st[cur].sum = st[lc].sum + st[rc].sum;
st[cur].siz = st[lc].siz + st[rc].siz;
}
void insert(int &cur, int l, int r, int p, int x)
{
if (!cur)
cur = ++tot;
if (l == r)
{
st[cur].sum += p * x;
st[cur].siz += x;
return;
}
int mid = l + r >> 1;
if (p <= mid)
insert(lc, l, mid, p, x);
else
insert(rc, mid + 1, r, p, x);
pushup(cur);
}
node query(int cur, int l, int r, int a, int b)
{
if (a <= l && r <= b)
return st[cur];
int mid = l + r >> 1;
node res = {0, 0, 0, 0};
if (a <= mid)
res = res + query(lc, l, mid, a, b);
if (b > mid)
res = res + query(rc, mid + 1, r, a, b);
return res;
}
const int L = -1e6, R = 1e9 + 1e6;
void solve()
{
cin >> n >> lim;
tree<pair<int, int>, null_type, less<pair<int, int>>, rb_tree_tag, tree_order_statistics_node_update> s;
for (int i = 1; i <= n; i++)
cin >> a[i], a[i] -= i;
int ans = 1;
s.insert({a[1], 1});
insert(root, L, R, a[1], 1);
int l = 0, r = 0;
for (int i = 2, pre = 1; i <= n; i++)
{
insert(root, L, R, a[i], 1);
s.insert({a[i], i});
int k = (i - pre) / 2;
auto mid = s.find_by_order(k);
i64 sum = 0;
auto t1 = query(root, L, R, L, mid->first - 1);
auto t2 = query(root, L, R, mid->first + 1, R);
sum = (i64)(mid->first) * t1.siz - t1.sum + t2.sum - (i64)(mid->first) * t2.siz;
while (1)
{
if (sum > lim)
{
insert(root, L, R, a[pre], -1);
s.erase({a[pre], pre});
k = (i - pre) / 2;
mid = s.find_by_order(k);
auto t1 = query(root, L, R, L, mid->first - 1);
auto t2 = query(root, L, R, mid->first + 1, R);
sum = (i64)(mid->first) * t1.siz - t1.sum + t2.sum - (i64)(mid->first) * t2.siz;
pre++;
}
else
break;
}
ans = max(ans, i - pre + 1);
}
cout << ans << '\n';
for (int i = 0; i <= tot; i++)
st[i] = {0, 0, 0, 0};
root = tot = 0;
}
signed main()
{
ios_base::sync_with_stdio(false);
cin.tie(nullptr);
int t = 1;
cin >> t;
cout << fixed << setprecision(10);
while (t--)
solve();
}
详细
Test #1:
score: 100
Accepted
time: 1ms
memory: 5660kb
input:
5 7 5 7 2 5 5 4 11 7 6 0 100 3 4 5 99 100 5 6 1 1 1 1 1 5 50 100 200 300 400 500 1 100 3
output:
4 3 5 1 1
result:
ok 5 lines
Test #2:
score: 0
Accepted
time: 887ms
memory: 17132kb
input:
11102 2 167959139 336470888 134074578 5 642802746 273386884 79721198 396628655 3722503 471207868 6 202647942 268792718 46761498 443917727 16843338 125908043 191952768 2 717268783 150414369 193319712 6 519096230 356168102 262263554 174936674 407246545 274667941 279198849 9 527268921 421436316 3613460...
output:
1 4 3 2 6 5 7 2 4 1 4 1 1 3 2 2 7 8 7 7 1 7 6 2 4 3 1 6 7 7 3 4 3 9 3 8 6 6 3 1 6 3 1 2 4 6 4 6 4 1 4 7 1 6 3 5 6 6 1 7 5 3 1 6 4 5 3 2 2 6 2 3 10 1 4 3 2 4 5 1 7 5 5 5 8 5 3 6 3 5 5 8 5 4 5 2 1 5 2 3 3 4 8 1 3 1 2 2 8 3 1 6 8 1 8 4 5 6 6 8 4 8 3 2 8 4 5 6 2 6 2 4 1 5 4 5 3 2 4 1 2 1 4 5 8 3 7 3 3 3...
result:
ok 11102 lines
Test #3:
score: -100
Runtime Error
input:
1 500000 17244641009859 54748096 75475634 204928248 276927808 84875072 103158867 27937890 322595515 186026685 45468307 69240390 139887597 188586447 373764525 121365644 310156469 185188306 60350786 211308832 384695957 370562147 208427221 35937909 267590963 126478310 275357775 55361535 335993561 36696...