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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#292098 | #6309. Aqre | QwertyPi# | WA | 2ms | 3444kb | C++17 | 1.7kb | 2023-12-27 18:11:52 | 2023-12-27 18:11:53 |
Judging History
answer
#include <bits/stdc++.h>
#define int long long
#define all(a) (a).begin(), (a).end()
#define sz(a) (int) (a).size()
#define forn(i, n) for(int i = 0; i < (n); i++)
using namespace std;
bool b[1000][1000];
void solve(){
int n, m; cin >> n >> m;
bool swapped = false;
if(n > m) {
swapped = true;
swap(n, m);
}
if(n <= 3 && m <= 3){
forn(i, n) forn(j, m) b[i][j] = 1;
}else if(n == 3){
forn(i, n) forn(j, m) {
int ri = i % 4, rj = j % 4;
if(ri == 0 && rj == 3 || ri == 1 && rj == 3 || ri == 2 && rj == 1){
b[i][j] = 0;
}else{
b[i][j] = 1;
}
}
}else{
vector<int> c = n == 2 || n % 4 == 0 || m % 4 == 0 ? vector<int>{1, 3, 0, 2} : vector<int>{3, 2, 0, 1};
forn(i, n) forn(j, m) {
int ri = i % 4, rj = j % 4;
if(rj == c[ri]){
b[i][j] = 0;
}else{
b[i][j] = 1;
}
}
}
int total = 0;
forn(i, n) forn(j, m) total += b[i][j];
#ifdef LOCAL
int potent = (n / 4 * 3) * (m % 4) + (n % 4) * (m / 4 * 3) + ((n / 4) * (m / 4) * 12);
cout << "DIFF = " << (n % 4) * (m % 4) - (total - potent) << endl;
#endif
cout << total << '\n';
if (swapped) {
forn(i, m) {
forn(j, n) cout << b[j][i];
cout << '\n';
}
}else{
forn(i, n) {
forn(j, m) cout << b[i][j];
cout << '\n';
}
}
}
int32_t main(){
cin.tie(0); cout.tie(0)->sync_with_stdio(false);
int t = 1;
cin >> t;
while(t--){
solve();
}
}
详细
Test #1:
score: 100
Accepted
time: 1ms
memory: 3444kb
input:
3 2 2 3 4 3 8
output:
4 11 11 9 1110 1110 1011 18 11101110 11101110 10111011
result:
ok ok (3 test cases)
Test #2:
score: -100
Wrong Answer
time: 2ms
memory: 3368kb
input:
361 2 2 2 3 2 4 2 5 2 6 2 7 2 8 2 9 2 10 2 11 2 12 2 13 2 14 2 15 2 16 2 17 2 18 2 19 2 20 3 2 3 3 3 4 3 5 3 6 3 7 3 8 3 9 3 10 3 11 3 12 3 13 3 14 3 15 3 16 3 17 3 18 3 19 3 20 4 2 4 3 4 4 4 5 4 6 4 7 4 8 4 9 4 10 4 11 4 12 4 13 4 14 4 15 4 16 4 17 4 18 4 19 4 20 5 2 5 3 5 4 5 5 5 6 5 7 5 8 5 9 5 1...
output:
4 11 11 6 111 111 6 1011 1110 8 10111 11101 9 101110 111011 11 1011101 1110111 12 10111011 11101110 14 101110111 111011101 15 1011101110 1110111011 17 10111011101 11101110111 18 101110111011 111011101110 20 1011101110111 1110111011101 21 10111011101110 11101110111011 23 101110111011101 1110111011101...
result:
wrong answer ans finds a larger answer (test case 103)