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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#288346#7007. Rikka with Data StructureszhouhuanyiWA 4360ms15740kbC++205.0kb2023-12-22 15:38:052023-12-22 15:38:06

Judging History

你现在查看的是最新测评结果

  • [2023-12-22 15:38:06]
  • 评测
  • 测评结果:WA
  • 用时:4360ms
  • 内存:15740kb
  • [2023-12-22 15:38:05]
  • 提交

answer

#include<iostream>
#include<cstdio>
#define N 100000
using namespace std;
int read()
{
	char c=0;
	int sum=0;
	while (c<'0'||c>'9') c=getchar();
	while ('0'<=c&&c<='9') sum=sum*10+c-'0',c=getchar();
	return sum;
}
int Ts,n,m,lg[N+1],A[N+1],tong[N+1],length;
struct seg
{
	struct node
	{
		int l,r,cnt,cnt2,lazych;
		long long maxn,lazy;
	};
	node tree[(N<<2)+1];
	void build(int k,int l,int r)
	{
		tree[k].l=l,tree[k].r=r,tree[k].lazy=tree[k].cnt=tree[k].cnt2=0,tree[k].lazych=-1;
		int mid=(l+r)>>1,res=0;
		for (int i=l;i<=r;++i) res=max(res,A[i]),tree[k].cnt+=(res==A[i]);
		res=0;
		for (int i=r;i>=l;--i) res=max(res,A[i]),tree[k].cnt2+=(res==A[i]);
		tree[k].maxn=res;
		if (l==r) return;
		build(k<<1,l,mid),build(k<<1|1,mid+1,r);
		return;
	}
	void push_change(int k,int d)
	{
		tree[k].maxn=tree[k].lazych=d,tree[k].lazy=0,tree[k].cnt=tree[k].cnt2=tree[k].r-tree[k].l+1;
		return;
	}
	void push_add(int k,long long d)
	{
		tree[k].maxn+=d,tree[k].lazy+=d;
		return;
	}
	void spread(int k)
	{
		if (tree[k].lazych!=-1) push_change(k<<1,tree[k].lazych),push_change(k<<1|1,tree[k].lazych),tree[k].lazych=-1;
		if (tree[k].lazy) push_add(k<<1,tree[k].lazy),push_add(k<<1|1,tree[k].lazy),tree[k].lazy=0;
		return;
	}
	int calc(int k,long long d)
	{
		if (tree[k].l==tree[k].r) return tree[k].maxn>=d;
		spread(k);
		if (d<=tree[k<<1].maxn) return calc(k<<1,d)+tree[k].cnt-tree[k<<1].cnt;
		else return calc(k<<1|1,d);
	}
	int calc2(int k,long long d)
	{
		if (tree[k].l==tree[k].r) return tree[k].maxn>=d;
		spread(k);
		if (d<=tree[k<<1|1].maxn) return calc2(k<<1|1,d)+tree[k].cnt-tree[k<<1|1].cnt;
		else return calc2(k<<1,d);
	}
	void push_up(int k)
	{
		tree[k].maxn=max(tree[k<<1].maxn,tree[k<<1|1].maxn),tree[k].cnt=tree[k<<1].cnt+calc(k<<1|1,tree[k<<1].maxn),tree[k].cnt2=tree[k<<1|1].cnt2+calc2(k<<1,tree[k<<1|1].maxn);
		return;
	}
	void add(int k,int l,int r,int d)
	{
		if (tree[k].l==l&&tree[k].r==r)
		{
			push_add(k,d);
			return;
		}
		spread(k);
		int mid=(tree[k].l+tree[k].r)>>1;
		if (r<=mid) add(k<<1,l,r,d);
		else if (l>=mid+1) add(k<<1|1,l,r,d);
		else add(k<<1,l,mid,d),add(k<<1|1,mid+1,r,d);
		push_up(k);
		return;
	}
	void change(int k,int l,int r,int d)
	{
		if (tree[k].l==l&&tree[k].r==r)
		{
			push_change(k,d);
			return;
		}
		spread(k);
		int mid=(tree[k].l+tree[k].r)>>1;
		if (r<=mid) change(k<<1,l,r,d);
		else if (l>=mid+1) change(k<<1|1,l,r,d);
		else change(k<<1,l,mid,d),change(k<<1|1,mid+1,r,d);
		push_up(k);
		return;
	}
	long long get_maxn(int k,int l,int r)
	{
		if (tree[k].l==l&&tree[k].r==r) return tree[k].maxn;
		spread(k);
		int mid=(tree[k].l+tree[k].r)>>1;
		if (r<=mid) return get_maxn(k<<1,l,r);
		else if (l>=mid+1) return get_maxn(k<<1|1,l,r);
		else return max(get_maxn(k<<1,l,mid),get_maxn(k<<1|1,mid+1,r));
	}
	void find(int k,int l,int r)
	{
		if (tree[k].l==l&&tree[k].r==r)
		{
			tong[++length]=k;
			return;
		}
		spread(k);
		int mid=(tree[k].l+tree[k].r)>>1;
		if (r<=mid) find(k<<1,l,r);
		else if (l>=mid+1) find(k<<1|1,l,r);
		else find(k<<1,l,mid),find(k<<1|1,mid+1,r);
		return;
	}
};
seg T;
int main()
{
	int op,l,r,sl,sr,x,res;
	long long d,rst;
	for (int i=2;i<=N;++i) lg[i]=lg[i>>1]+1;
	Ts=read();
	while (Ts--)
	{
		n=read(),m=read();
		for (int i=1;i<=n;++i) A[i]=read();
		T.build(1,1,n);
		for (int i=1;i<=m;++i)
		{
			op=read(),l=read(),r=read(),x=read();
			if (op==1) T.add(1,l,r,x);
			else if (op==2) T.change(1,l,r,x);
			else
			{
				if (l<=x&&x<=r)
				{
					sl=sr=x,d=T.get_maxn(1,x,x);
					for (int j=lg[r-x+1];j>=0;--j)
						if (sr+(1<<j)<=r&&T.get_maxn(1,x+1,sr+(1<<j))<d)
							sr+=(1<<j);
					for (int j=lg[x-l+1];j>=0;--j)
						if (sl-(1<<j)>=l&&T.get_maxn(1,sl-(1<<j),x-1)<d)
							sl-=(1<<j);
					res=sr-sl+1;
					if (sr+1<=r)
					{
						rst=d,length=0,T.find(1,sr+1,r);
						for (int j=1;j<=length;++j) res+=T.calc(tong[j],rst),rst=max(rst,T.tree[tong[j]].maxn);
					}
					if (l<=sl-1)
					{
						rst=d,length=0,T.find(1,l,sl-1);
						for (int j=length;j>=1;--j) res+=T.calc2(tong[j],rst),rst=max(rst,T.tree[tong[j]].maxn);
					}
					printf("%d\n",res);
				}
				else if (x<l)
				{
					d=T.get_maxn(1,x,l-1),sr=l-1;
					for (int j=lg[r-l+1];j>=0;--j)
						if (sr+(1<<j)<=r&&T.get_maxn(1,l,sr+(1<<j))<d)
							sr+=(1<<j);
					res=sr-l+1;
					if (sr+1<=r)
					{
						rst=d,length=0,T.find(1,sr+1,r);
						for (int j=1;j<=length;++j) res+=T.calc(tong[j],rst),rst=max(rst,T.tree[tong[j]].maxn);
					}
					printf("%d\n",res);
				}
				else if (x>r)
				{
					d=T.get_maxn(1,r+1,x),sl=r+1;
					for (int j=lg[r-l+1];j>=0;--j)
						if (sl-(1<<j)>=l&&T.get_maxn(1,sl-(1<<j),r)<d)
							sl-=(1<<j);
					res=r-sl+1;
					if (l<=sl-1)
					{
						rst=d,length=0,T.find(1,l,sl-1);
						for (int j=length;j>=1;--j) res+=T.calc2(tong[j],rst),rst=max(rst,T.tree[tong[j]].maxn);
					}
					printf("%d\n",res);
				}
			}
		}
	}
	return 0;
}

详细

Test #1:

score: 100
Accepted
time: 1ms
memory: 4196kb

input:

1
10 10
1 3 2 5 2 3 1 6 4 5
3 5 7 8
3 5 7 4
1 1 5 2
3 1 10 4
3 1 10 8
2 8 8 8
3 1 10 8
3 1 10 4
2 4 8 1
3 1 2 10

output:

3
3
10
7
10
8
2

result:

ok 7 lines

Test #2:

score: -100
Wrong Answer
time: 4360ms
memory: 15740kb

input:

200
321 43
168330405 102091681 86278243 227886812 609333939 211045240 332465535 212315420 510322126 700237719 102348318 320419595 409640374 582249257 245617532 643949598 748863235 405762764 358055464 585833725 429993246 60296212 632603910 229141445 696836739 297883078 545245133 44079558 92873286 347...

output:

25
57
61
190
11
1
36
5
9
139
47
194
18
247
106
103
43
327
18
87
165
13
68
114
101
5
34
152
5
138
58
43
62
112
122
41
81
40
48
47
24
42
34
167
15
98
31
112
114
17
123
35
173
167
106
120
116
63
191
210
37
104
41
48
104
68
2
114
239
29
143
167
15
54
39
42
85
77
212
7
47
96
33
80
83
18
2
57
29
65
11
74
...

result:

wrong answer 1st lines differ - expected: '1', found: '25'