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ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#288228 | #6309. Aqre | willy108 | WA | 1ms | 3668kb | C++20 | 2.7kb | 2023-12-22 11:29:10 | 2023-12-22 11:29:10 |
Judging History
answer
//misaka, hitori, and elaina will carry me to red
#pragma GCC optimize("O3,unroll-loops")
#pragma GCC target("avx2,bmi,bmi2,lzcnt,popcnt")
#include <iostream>
#include <cmath>
#include <utility>
#include <cassert>
#include <algorithm>
#include <vector>
#include <array>
#include <cstdio>
#include <cstring>
#include <functional>
#include <numeric>
#include <set>
#include <queue>
#include <map>
#include <chrono>
#include <random>
#define sz(x) ((int)(x.size()))
#define all(x) x.begin(), x.end()
#define pb push_back
#define eb emplace_back
#define kill(x, s) {if(x){ cout << s << "\n"; return ; }}
#ifndef LOCAL
#define cerr while(0) cerr
#endif
using ll = long long;
using lb = long double;
const lb eps = 1e-9;
const ll mod = 1e9 + 7, ll_max = 1e18;
//const ll mod = (1 << (23)) * 119 +1, ll_max = 1e18;
const int MX = 2e5 +10, int_max = 0x3f3f3f3f;
struct {
template<class T>
operator T() {
T x; std::cin >> x; return x;
}
} in;
using namespace std;
string pattern[] = {"1110", "0111", "1101", "1011"};
string pattern2[] = {"111", "101", "111", "010"};
string pattern3[] = {"111011", "110111", "011101", "101110"};
void solve(){
int n = in, m = in;
vector<string> ans(n);
if(n<4 && m<4){
for(int i = 0; i<n; i++){
for(int j = 0; j<m; j++){
ans[i].pb('1');
}
}
}else if(n == 3){
for(int i = 0; i<m; i++){
for(int j = 0; j<3; j++){
ans[j].pb(pattern2[i%4][j]);
}
}
}else if (m == 3){
for(int i = 0; i<n; i++){
for(int j = 0; j<3; j++){
ans[i].pb(pattern2[i%4][j]);
}
}
}else if(n%4 == 1 && m%4 == 1){
for(int i = 0; i<n; i++){
for(int j = 0; j<m; j++){
ans[i].pb(pattern[(n+2-i)%4][(m+2-j)%4]);
}
}
}else if(min(n, m) > 2 && (n == 6 || m == 6)){
if(n == 6){
for(int i = 0; i<n; i++){
for(int j = 0; j<m; j++){
ans[i].pb(pattern3[j%4][i]);
}
}
}else{
for(int i = 0; i<n; i++){
for(int j = 0; j<m; j++){
ans[i].pb(pattern3[i%4][j]);
}
}
}
}else if(m != 2 && (n%4 == 2 || (n%4 == 3 && (m%4 == 1)) || (n%4 == 0 && m%2 == 1))){
for(int i = 0; i<n; i++){
for(int j = 0; j<m; j++){
ans[i].pb(pattern[j%4][i%4]);
}
}
}else{
for(int i = 0; i<n; i++){
for(int j = 0; j<m; j++){
ans[i].pb(pattern[i%4][j%4]);
}
}
}
int oup = 0;
for(int i = 0; i<n; i++){
for(int j = 0; j<m; j++){
oup += ans[i][j] == '1';
}
}
cout << oup << "\n";
for(string s : ans) cout << s << "\n";
}
signed main(){
cin.tie(0) -> sync_with_stdio(0);
int T = 1;
cin >> T;
for(int i = 1; i<=T; i++){
//cout << "Case #" << i << ": ";
solve();
}
return 0;
}
詳細信息
Test #1:
score: 100
Accepted
time: 0ms
memory: 3616kb
input:
3 2 2 3 4 3 8
output:
4 11 11 9 1110 1011 1110 18 11101110 10111011 11101110
result:
ok ok (3 test cases)
Test #2:
score: -100
Wrong Answer
time: 1ms
memory: 3668kb
input:
361 2 2 2 3 2 4 2 5 2 6 2 7 2 8 2 9 2 10 2 11 2 12 2 13 2 14 2 15 2 16 2 17 2 18 2 19 2 20 3 2 3 3 3 4 3 5 3 6 3 7 3 8 3 9 3 10 3 11 3 12 3 13 3 14 3 15 3 16 3 17 3 18 3 19 3 20 4 2 4 3 4 4 4 5 4 6 4 7 4 8 4 9 4 10 4 11 4 12 4 13 4 14 4 15 4 16 4 17 4 18 4 19 4 20 5 2 5 3 5 4 5 5 5 6 5 7 5 8 5 9 5 1...
output:
4 11 11 6 111 111 6 1011 1110 8 10111 11101 9 101110 111011 11 1011101 1110111 12 10111011 11101110 14 101110111 111011101 15 1011101110 1110111011 17 10111011101 11101110111 18 101110111011 111011101110 20 1011101110111 1110111011101 21 10111011101110 11101110111011 23 101110111011101 1110111011101...
result:
wrong answer 1s are not connected. (test case 43)