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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#288018#7859. Bladestormucup-team1447#TL 0ms15728kbC++144.8kb2023-12-21 15:55:342023-12-21 15:55:34

Judging History

你现在查看的是最新测评结果

  • [2023-12-21 15:55:34]
  • 评测
  • 测评结果:TL
  • 用时:0ms
  • 内存:15728kb
  • [2023-12-21 15:55:34]
  • 提交

answer

// what is matter? never mind. 
//#pragma GCC optimize("Ofast")
//#pragma GCC optimize("unroll-loops")
//#pragma GCC target("sse,sse2,sse3,sse4,popcnt,abm,mmx,avx,avx2") 
#include<bits/stdc++.h>
#define For(i,a,b) for(int i=(a);i<=(b);++i)
#define Rep(i,a,b) for(int i=(a);i>=(b);--i)
#define ll long long
#define int long long
#define ull unsigned long long
using namespace std;
inline int read()
{
    char c=getchar();int x=0;bool f=0;
    for(;!isdigit(c);c=getchar())f^=!(c^45);
    for(;isdigit(c);c=getchar())x=(x<<1)+(x<<3)+(c^48);
    if(f)x=-x;return x;
}

#define mod 998244353
struct modint{
	int x;
	modint(int o=0){x=o;}
	modint &operator = (int o){return x=o,*this;}
	modint &operator +=(modint o){return x=x+o.x>=mod?x+o.x-mod:x+o.x,*this;}
	modint &operator -=(modint o){return x=x-o.x<0?x-o.x+mod:x-o.x,*this;}
	modint &operator *=(modint o){return x=1ll*x*o.x%mod,*this;}
	modint &operator ^=(int b){
		modint a=*this,c=1;
		for(;b;b>>=1,a*=a)if(b&1)c*=a;
		return x=c.x,*this;
	}
	modint &operator /=(modint o){return *this *=o^=mod-2;}
	friend modint operator +(modint a,modint b){return a+=b;}
	friend modint operator -(modint a,modint b){return a-=b;}
	friend modint operator *(modint a,modint b){return a*=b;}
	friend modint operator /(modint a,modint b){return a/=b;}
	friend modint operator ^(modint a,int b){return a^=b;}
	friend bool operator ==(modint a,int b){return a.x==b;}
	friend bool operator !=(modint a,int b){return a.x!=b;}
	bool operator ! () {return !x;}
	modint operator - () {return x?mod-x:0;}
	bool operator <(const modint&b)const{return x<b.x;}
};
inline modint qpow(modint x,int y){return x^y;}

vector<modint> fac,ifac,iv;
inline void initC(int n)
{
	if(iv.empty())fac=ifac=iv=vector<modint>(2,1);
	int m=iv.size(); ++n;
	if(m>=n)return;
	iv.resize(n),fac.resize(n),ifac.resize(n);
	For(i,m,n-1){
		iv[i]=iv[mod%i]*(mod-mod/i);
		fac[i]=fac[i-1]*i,ifac[i]=ifac[i-1]*iv[i];
	}
}
inline modint C(int n,int m){
	if(m<0||n<m)return 0;
	return initC(n),fac[n]*ifac[m]*ifac[n-m];
}
inline modint sign(int n){return (n&1)?(mod-1):(1);}

#define fi first
#define se second
#define pb push_back
#define mkp make_pair
typedef pair<int,int>pii;
typedef vector<int>vi;

#define fi first
#define se second
#define pb push_back
#define mkp make_pair
typedef pair<int,int>pii;
typedef vector<int>vi;

#define maxn 500005
#define inf 0x3f3f3f3f

int n,par[maxn],a[maxn],res[maxn],k;
int mx[maxn];

int val[maxn],sum[maxn];
int ch[maxn][2],fa[maxn];
#define ls(x) ch[x][0]
#define rs(x) ch[x][1]
bool nrt(int p){
	return rs(fa[p])==p||ls(fa[p])==p;
}
bool chk(int p){
	return rs(fa[p])==p;
}
void up(int p){
	sum[p]=sum[ls(p)]+sum[rs(p)]+val[p];
}
void down(int p){
//	if(rev[p]){
//		if(ls(p))pr(ls(p));
//		if(rs(p))pr(rs(p));
//		rev[p]=0;
//	}
}
void downall(int p){
//	if(nrt(p)) downall(fa[p]);
//	down(p);
}
void rot(int x){
	int y=fa[x],z=fa[y],k=chk(x),s=ch[x][!k];
	fa[x]=z; if(nrt(y)) ch[z][chk(y)]=x;
	if(s)fa[s]=y; ch[y][k]=s;
	ch[x][!k]=y; fa[y]=x;
	up(y),up(x);
}
void splay(int x){
	downall(x);
	while(nrt(x)){
		if(nrt(fa[x]))rot(chk(x)==chk(fa[x])?fa[x]:x);
		rot(x); 
	}
}

void acc(int x){
	for(int y=0;x;x=fa[y=x])
		splay(x),rs(x)=y,up(x);
}

int find(int l,int r){
	int res=l;
	while(l){
		if(l<=r)res=l,l=ch[l][0];
		else l=ch[l][1];
	}
//	cout<<"res "<<res<<"\n";
	splay(res);
	return sum[rs(res)]+val[res];
}
void dfs(int u){
	if(!u)return;
	dfs(ls(u));
	cout<<u<<" ";
	dfs(rs(u));
}
int ask(int l,int r){
//	cout<<"ask "<<l<<" "<<r<<"\n";
	acc(l),splay(l);
//	dfs(l);cout<<" dfs\n";
	return find(l,r);
}
void setfa(int x,int f,int v){
//	cout<<"setfa "<<x<<" "<<f<<" "<<v<<"\n";
	acc(x),splay(x);
	fa[ls(x)]=0,ls(x)=0;
	val[x]=v;
	up(x);
	fa[x]=f;
}

set<int>s;

void change(int l,int r,int x){
//	cout<<"mdf "<<l<<" "<<r<<" "<<x<<"\n";
	for(auto it=s.lower_bound(l);it!=s.end();it=s.erase(it)){
		if((*it)>=r)break;
		setfa(*it,*it+1,0);
	}
	setfa(r,x,1);
	s.insert(r);
}

void work()
{
	n=read(),k=read();
	For(i,1,n)a[i]=read(),mx[i]=max(mx[i-1],a[i]);
	For(i,1,n)par[i]=min(n+1,i+k); par[n+1]=0;
	
	For(i,1,n)val[i]=sum[i]=1,fa[i]=par[i];
	val[n+1]=sum[n+1]=0,par[n+1]=0;
	For(i,0,n+1) ch[i][0]=ch[i][1]=0;
	
	s.clear();
	For(i,1,n)s.insert(i);
	
	set<int>st;
	For(i,1,n)st.insert(i); st.insert(0); st.insert(n+1);
	Rep(i,n,1){
		
//		int now=1,ans=0;
//		while(now<=mx[i])now=par[now],++ans;
//		res[i]=ans;
		res[i]=ask(1,mx[i]);
		
		auto it=st.lower_bound(a[i]);
		auto itl=prev(it);
		auto itr=next(it);
		int l=(*itl)+1,r=a[i],to=(*itr)+1;
		to=min(to,n+1);
		
	//	For(j,l,r) par[j]=max(par[j],to);
		st.erase(it);
		r=min(r,to-k-1);
		
		if(l<=r) change(l,r,to);
	}
	For(i,1,n)cout<<res[i]<<" ";cout<<"\n";
}

signed main()
{
	int T=read();
	while(T--)work();
	return 0;
}
/*

*/

詳細信息

Test #1:

score: 100
Accepted
time: 0ms
memory: 15728kb

input:

3
7 2
4 7 3 6 1 2 5
11 3
10 7 4 9 6 8 5 1 3 2 11
9 2
1 2 3 7 8 9 4 5 6

output:

1 2 3 3 4 4 4 
1 2 3 3 3 3 3 4 4 4 4 
1 1 2 3 4 4 4 5 5 

result:

ok 3 lines

Test #2:

score: -100
Time Limit Exceeded

input:

40319
1 1
1
2 1
1 2
2 1
2 1
2 2
1 2
2 2
2 1
3 1
1 2 3
3 1
1 3 2
3 1
2 1 3
3 1
2 3 1
3 1
3 1 2
3 1
3 2 1
3 2
1 2 3
3 2
1 3 2
3 2
2 1 3
3 2
2 3 1
3 2
3 1 2
3 2
3 2 1
3 3
1 2 3
3 3
1 3 2
3 3
2 1 3
3 3
2 3 1
3 3
3 1 2
3 3
3 2 1
4 1
1 2 3 4
4 1
1 2 4 3
4 1
1 3 2 4
4 1
1 3 4 2
4 1
1 4 2 3
4 1
1 4 3 2
4 1
...

output:


result: