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ID	Problem	Submitter	Result	Time	Memory	Language	File size	Submit time	Judge time
#284063	#6636. Longest Strictly Increasing Sequence	Misuki	AC ✓	2ms	3560kb	C++20	2.4kb	2023-12-15 22:17:26	2023-12-15 22:17:27

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你现在查看的是最新测评结果

[2023-12-15 22:17:27]
评测

测评结果：AC
用时：2ms
内存：3560kb

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[2023-12-15 22:17:26]
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answer

#pragma GCC optimize("O2")
#include <algorithm>
#include <array>
#include <bit>
#include <bitset>
#include <cassert>
#include <cctype>
#include <cfenv>
#include <cfloat>
#include <chrono>
#include <cinttypes>
#include <climits>
#include <cmath>
#include <compare>
#include <complex>
#include <concepts>
#include <cstdarg>
#include <cstddef>
#include <cstdint>
#include <cstdio>
#include <cstdlib>
#include <cstring>
#include <deque>
#include <fstream>
#include <functional>
#include <initializer_list>
#include <iomanip>
#include <ios>
#include <iostream>
#include <istream>
#include <iterator>
#include <limits>
#include <list>
#include <map>
#include <memory>
#include <new>
#include <numbers>
#include <numeric>
#include <ostream>
#include <queue>
#include <random>
#include <ranges>
#include <set>
#include <span>
#include <sstream>
#include <stack>
#include <streambuf>
#include <string>
#include <tuple>
#include <type_traits>
#include <variant>

#define int ll
#define INT128_MAX (__int128)(((unsigned __int128) 1 << ((sizeof(__int128) * __CHAR_BIT__) - 1)) - 1)
#define INT128_MIN (-INT128_MAX - 1)

namespace R = std::ranges;
namespace V = std::views;

using namespace std;

using ll = long long;
using ull = unsigned long long;
using pii = pair<int, int>;
using pll = pair<long long, long long>;
using tiii = tuple<int, int, int>;
using ldb = long double;
//#define double ldb

template<class T>
ostream& operator<<(ostream& os, const pair<T, T> pr) {
  return os << pr.first << ' ' << pr.second;
}
template<class T, size_t N>
ostream& operator<<(ostream& os, const array<T, N> &arr) {
  for(const T &X : arr)
    os << X << ' ';
  return os;
}
template<class T>
ostream& operator<<(ostream& os, const vector<T> &vec) {
  for(const T &X : vec)
    os << X << ' ';
  return os;
}


signed main() {
  ios::sync_with_stdio(false), cin.tie(NULL);

  int t; cin >> t;
  while(t--) {
    int n; cin >> n;
    vector<int> b(n);
    for(int &x : b)
      cin >> x;

    bool ok = b[0] == 1;
    for(int i = 1; i < n; i++)
      ok = ok and b[i] - b[i - 1] <= 1 and b[i] >= b[i - 1];

    if (ok) {
      vector<int> a(1, 1);
      for(int i = 1; i < n; i++)
        a.emplace_back(a.back() + (b[i] != b[i - 1]));
      cout << "YES\n";
      cout << a << '\n';
    } else {
      cout << "NO\n";
    }
  }

  return 0;
}

Source code, Language: C++20

Details

Tip: Click on the bar to expand more detailed information

Test #1:

score: 100

Accepted

time: 0ms

memory: 3548kb

input:

2
6
1 2 3 2 5 7
2
1 2

output:

NO
YES
1 2

result:

ok t=2 (2 test cases)

Test #2:

score: 0

Accepted

time: 2ms

memory: 3560kb

input:

3483
5
2 3 5 1 1
2
8 1
10
1 2 3 4 4 5 6 6 6 7
10
1 1 2 2 2 2 3 4 4 5
2
5 8
3
7 10 8
5
4 1 3 3 8
10
1 2 2 2 2 2 2 3 3 3
10
1 1 2 3 4 5 5 5 5 6
9
1 2 3 4 5 5 6 6 7
7
8 8 8 8 9 1 2
5
8 9 8 3 5
10
1 2 3 3 3 3 4 4 4 5
5
7 1 6 4 3
7
5 6 8 6 1 5 5
10
1 2 2 3 4 4 4 4 5 5
3
10 4 5
3
1 5 3
5
2 8 1 2 1
3
7 8 3...

output:

NO
NO
YES
1 2 3 4 4 5 6 6 6 7 
YES
1 1 2 2 2 2 3 4 4 5 
NO
NO
NO
YES
1 2 2 2 2 2 2 3 3 3 
YES
1 1 2 3 4 5 5 5 5 6 
YES
1 2 3 4 5 5 6 6 7 
NO
NO
YES
1 2 3 3 3 3 4 4 4 5 
NO
NO
YES
1 2 2 3 4 4 4 4 5 5 
NO
NO
NO
NO
NO
NO
YES
1 1 1 2 2 3 3 4 4 
NO
NO
NO
NO
NO
NO
NO
YES
1 2 3 3 3 4 4 4 5 5 
YES
1 1 2 2 2...

result:

ok t=3483 (3483 test cases)