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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#283030#7789. Outro: True Love WaitsLoging#WA 1ms7968kbC++142.1kb2023-12-13 18:22:022023-12-13 18:22:02

Judging History

你现在查看的是最新测评结果

  • [2023-12-13 18:22:02]
  • 评测
  • 测评结果:WA
  • 用时:1ms
  • 内存:7968kb
  • [2023-12-13 18:22:02]
  • 提交

answer

#include <bits/stdc++.h>

#define Max 2000005

using namespace std;

const int mod=1e9+7;

int T,k,N,s[Max],t[Max];
char S[Max];

inline int qpow(int x,int y){
    int ans=1;
    while(y){
        if(y&1)ans=1ll*ans*x%mod;
        x=1ll*x*x%mod;
        y>>=1;
    }
    return ans;
}

inline bool check0(){
    for(int i=N;i>=1;i--){
        if(t[i]==1)return false;
    }
    return true;
}

inline bool check1(){
    int cnt=0;
    for(int i=N;i>=1;i--){
        if(t[i]==1){
            if(i%2==0)return false;
            cnt++;
        }
    }
    return (cnt==1);
}

inline int calc1(){
    for(int i=N;i>=1;i--){
        if(t[i]==1){
            return (i-1)/2;
        }
    }
    return 0;
}

inline int calc(int k){
    if(!k)return 0;
    return (1ll*(qpow(4,k)-1+mod)*qpow(3,mod-2)%mod-1+mod)%mod;
}

int main(){
    scanf("%d",&T);
    while(T--){
        scanf("%s",S+1);
        int n=strlen(S+1);
        for(int i=1;i<=n;i++)s[n-i+1]=S[i]-'0';
        scanf("%s",S+1);
        scanf("%d",&k);
        int m=strlen(S+1);
        for(int i=1;i<=m;i++)t[m-i+1]=S[i]-'0';
        N=max(n,m);
        for(int i=1;i<=N;i++)t[i]=s[i]^t[i];
        // for(int i=N;i>=1;i--)cout<<t[i];cout<<endl;
        if(check0()){
            printf("%d\n",(1ll*(qpow(4,k)-1+mod)*qpow(3,mod-2)%mod-1+mod)%mod);
        }else if(k==1){
            int ans=0;
            for(int i=N;i>=1;i--){
                if(t[i]==1){
                    if(i&1){
                        ans=(ans+calc(i/2+1)+1)%mod;
                    }else{
                        ans=(ans+2ll*calc(i/2)%mod+2)%mod;
                        t[i-1]^=1;
                    }
                }
            }
            printf("%d\n",ans);
        }else if(k==2){
            if(check1()){
                int p=calc1();
                printf("%d\n",(2ll*calc(p+1)+1)%mod);
            }else{
                puts("-1");
            }
        }else{
            puts("-1");
        }

        for(int i=1;i<=N;i++)s[i]=t[i]=0;
    }
    return 0;
}

详细

Test #1:

score: 100
Accepted
time: 0ms
memory: 7780kb

input:

4
1 10 1
1 10 2
100 0 2
11 11 3

output:

2
-1
9
20

result:

ok 4 number(s): "2 -1 9 20"

Test #2:

score: 0
Accepted
time: 1ms
memory: 7968kb

input:

1
0 0 1

output:

0

result:

ok 1 number(s): "0"

Test #3:

score: 0
Accepted
time: 0ms
memory: 7740kb

input:

100
110111 11111 1
10110 101101 1
11010 111111 1
100110 1 1
10010 11010 1
1100 10111 1
100100 111110 1
101110 101100 1
1011 10110 1
110100 1110 1
11010 11000 1
11110 1000 1
111000 11101 1
110 1001 1
101010 11000 1
10 111110 1
110001 101000 1
1010 1000 1
10101 11 1
111011 11010 1
110001 100000 1
1100...

output:

78
59
69
70
15
38
39
3
32
60
3
29
69
12
45
52
37
3
29
64
22
39
54
69
65
27
33
76
34
18
57
13
81
15
23
70
69
36
18
23
29
42
69
54
6
0
63
3
29
15
10
16
80
24
37
59
71
13
23
31
21
34
23
48
21
47
7
44
42
3
37
75
59
29
55
39
29
28
29
70
55
16
54
47
24
18
79
60
8
26
64
58
32
6
8
37
2
68
42
44

result:

ok 100 numbers

Test #4:

score: -100
Wrong Answer
time: 1ms
memory: 7956kb

input:

100
10011111 111 2
1011101100 1000000100 1
100011111 1001001111 1
1001100101 1100100001 1
10101000 10000100 1
1011110101 100011101 1
110100001 111011010 1
1101001100 1111101101 1
1001101 11011010 1
1101110110 1101011000 1
110011001 1100001111 2
1001111001 1011001111 1
1001110 1101110100 2
1110110100...

output:

-1
248
788
431
73
930
144
319
283
76
-1
305
-1
-1
86
-1
312
293
1293
433
1179
0
884
963
1215
576
-1
1132
499
811
864
949
1322
406
526
862
-1
447
1203
1238
873
-1
-1
1131
1108
438
134
359
80
740
1057
752
31
950
1093
1261
650
235
996
876
504
925
1344
450
1010
273
-1
1144
1041
-1
-1
164
-1
11
798
419
1...

result:

wrong answer 1st numbers differ - expected: '295', found: '-1'