QOJ.ac

QOJ

ID题目提交者结果用时内存语言文件大小提交时间测评时间
#276618#7561. Digit DPyyf_0404RE 0ms3816kbC++143.1kb2023-12-06 00:49:432023-12-06 00:49:43

Judging History

你现在查看的是最新测评结果

  • [2023-12-06 00:49:43]
  • 评测
  • 测评结果:RE
  • 用时:0ms
  • 内存:3816kb
  • [2023-12-06 00:49:43]
  • 提交

answer

#include <bits/stdc++.h>
using namespace std;
const int mod = 998244353, inv6 = 166374059;
int qmod(int x){
	return x + (x >> 31 & mod);
}
void add(int &x, int y){
	x = qmod(x + y - mod);
}
struct Unit{
	int a[4];
	Unit(){
		memset(a, 0, sizeof(a));
	}
	Unit(int x){
		a[0] = 1;
		for(int i = 1; i < 4; i++)
			a[i] = 1ll * a[i - 1] * x % mod;
	}
	Unit& operator += (Unit b){
		for(int i = 0; i < 4; i++)
			add(a[i], b.a[i]);
		return *this;
	}
	Unit& operator *= (int x){
		for(int i = 3; i > 0; i--)
			for(int j = i - 1, t1 = i, t2 = x; j >= 0; t1 = t1 * j / (i - j + 1), t2 = 1ll * x * t2 % mod, j--)
				add(a[i], 1ll * t1 * t2 * a[j] % mod);
		return *this;
	}
	int val()const{
		// return a[3];
		int res = 1ll * a[1] * a[1] % mod * a[1] % mod;
		add(res, qmod(a[3] + a[3] - mod));
		res = qmod(res - 3ll * a[1] * a[2] % mod);
		return 1ll * res * inv6 % mod;
	}
};
int n, q, a[105];
#define mid (l + ((__int128)1 << d - 1))
#define r   (l + ((__int128)1 << d) - 1)
struct Seg{
	Unit s;
	int m;
	Seg *ch[2];
	Seg():s(){
		m = 0;
		ch[0] = ch[1] = 0;
	}
	Seg(Seg *x){
		if(x){
			m = x->m;
			ch[0] = x->ch[0];
			ch[1] = x->ch[1];			
		}
	}
	Seg *get(int k, Seg *pre = 0){
		return ch[k] = new Seg(pre);
	}
	void pushup(int d){
		if(!d) return s = m, void();
		s = ch[0] ? ch[0]->s : Unit();
		if(ch[1]) s += ch[1]->s;
		if(m) s *= m;
	}
	void build(int d = n, __int128 l = 0){
		if(!d) return s = m, void();
		get(0)->build(d - 1, l);
		get(1, ch[0]); ch[1]->m = a[d - 1];
		ch[1]->pushup(d - 1);
		pushup(d);
	}
	void print(int d = n, __int128 l = 0){
		printf("%d %d %d\n", d, s.val(), m);
		if(!d) return;
		ch[0]->print(d - 1, l);
		ch[1]->print(d - 1, mid);
	}
	void upd(Seg *pre, __int128 L, __int128 R, int x, int d = n, __int128 l = 0){
		// cout << d << " " << (int)l << endl;
		if(L <= l && R >= r){
			add(m, x);
			pushup(d);
			return;
		}
		if(L < mid) get(0, pre->ch[0])->upd(pre->ch[0], L, R, x, d - 1, l);
		if(R >= mid) get(1, pre->ch[1])->upd(pre->ch[1], L, R, x, d - 1, mid);
		pushup(d);
	}
	Unit query(__int128 L, __int128 R, int lazy = 0, int d = n, __int128 l = 0){
		if(L <= l && R >= r){
			Unit res = s;
			return res *= lazy;
		}
		add(lazy, m);
		Unit res = L < mid ? ch[0]->query(L, R, lazy, d - 1, l) : Unit();
		if(R >= mid) res += ch[1]->query(L, R, lazy, d - 1, mid);
		return res;
	}
}*rt[50004];
#undef r
__int128 btoi(string &s){
	__int128 res = 0;
	for(int i = 0; i < n; i++)
		res = res << 1 | s[i] ^ '0';
	return res;
}
int main(){
	ios::sync_with_stdio(0);
	cin.tie(0);
	cin >> n >> q;
	for(int i = 0; i < n; i++){
		cin >> a[i];
		a[i] = qmod(a[i] - mod);
	}
	(rt[0] = new Seg())->build();
	// rt[0]->print();
	for(int i = 1, op; i <= q; i++){
		rt[i] = new Seg();
		string s1, s2;
		cin >> op >> s1 >> s2;
		__int128 l = 0, r = 0;
		l = btoi(s1); r = btoi(s2);
		if(op == 1){
			int x;
			cin >> x;
			rt[i]->upd(rt[i - 1], l, r, qmod(x - mod));
			// rt[i]->print();
		}
		else{
			rt[i] = rt[i - 1];
			printf("%d\n", rt[i]->query(l, r).val());
			// rt[i]->print();
		}
	}
	return 0;
}

详细

Test #1:

score: 100
Accepted
time: 0ms
memory: 3756kb

input:

3 3
1 2 4
2 000 111
1 010 101 1
2 000 111

output:

1960
3040

result:

ok 2 number(s): "1960 3040"

Test #2:

score: 0
Accepted
time: 0ms
memory: 3816kb

input:

2 2
1 1
2 00 10
2 00 11

output:

0
2

result:

ok 2 number(s): "0 2"

Test #3:

score: -100
Runtime Error

input:

99 49952
470888 74578 802746 396295 386884 721198 628655 722503 207868 647942 87506 792718 761498 917727 843338 908043 952768 268783 375312 414369 319712 96230 277106 168102 263554 936674 246545 667941 198849 268921 191459 436316 134606 802932 515506 837311 465964 394766 17626 650419 984050 790137 4...

output:


result: