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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#276025#5069. VacationrageOfThunder#WA 497ms160036kbC++148.0kb2023-12-05 14:53:412023-12-05 14:53:41

Judging History

你现在查看的是最新测评结果

  • [2023-12-05 14:53:41]
  • 评测
  • 测评结果:WA
  • 用时:497ms
  • 内存:160036kb
  • [2023-12-05 14:53:41]
  • 提交

answer

#include <bits/stdc++.h>
#define ls num << 1
#define rs ls | 1
#define li ls, l, mid
#define ri rs, mid + 1, r
#define SZ(x) (int) x.size() - 1
#define all(x) x.begin(), x.end()
#define ms(x, y) memset(x, y, sizeof x)
#define F(i, x, y) for (int i = (x); i <= (y); i++)
#define DF(i, x, y) for (int i = (x); i >= (y); i--)
using namespace std;
typedef long long ll;
typedef unsigned long long ull;
template <typename T> void chkmax(T &x, T y) {x = max(x, y); }
template <typename T> void chkmin(T &x, T y) {x = min(x, y); }
char buf[1<<21],*p1=buf,*p2=buf,obuf[1<<25],*O=obuf;
#define getchar() (p1==p2&&(p2=(p1=buf)+fread(buf,1,1<<21,stdin),p1==p2)?EOF:*p1++)
inline int read(){
	int s=0,w=1;
	char ch=getchar();
	for(;!isdigit(ch);ch=getchar())if(ch=='-')w=-1;
	for(;isdigit(ch);ch=getchar()) s=s*10+ch-'0';
	return s*w;
}
inline void print(ll x) {
	static char buf_num[20];
    int n = 0;
    do buf_num[n++] = x % 10 + '0'; while(x /= 10);
    while (n--) *O++=buf_num[n];
	*O++='\n';
}
// template <typename T> void writeln(T x) { print(x); *O++='\n'; }
const int N = 2e6 + 10;
int n, m, c, a[N], tot;
struct segment1 {
	struct seg {
		ll lans, rans, ans, sum;
		inline seg operator + (const seg& t) {
			return {max(lans, sum + t.lans), max(t.rans, t.sum + rans), max(max(ans, t.ans), rans + t.lans), sum + t.sum};
		}
	} t[4194304];
	inline void pushup(int num) {
		t[num] = t[ls] + t[rs];
	}
	inline void build(int num, int l, int r) {
		if (l == r) {
			t[num].sum = t[num].ans = t[num].lans = t[num].rans = a[l];
			return;
		} int mid = (l + r) >> 1;
		build(li); build(ri);
		pushup(num);
	}
	inline void modify(int num, int l, int r, int x, int y) {
		if (l == r) {
			t[num].sum = t[num].ans = t[num].lans = t[num].rans = y;
			// cout << l << " " << t[num].sum << endl;
			return;
		} int mid = (l + r) >> 1;
		if (mid >= x) modify(li, x, y);
		else modify(ri, x, y);
		pushup(num);
		// if (x == 22) cout << l << " " << r << " " << t[num].sum << endl;
	}
	inline seg query(int num, int l, int r, int L, int R) {
		if (L <= l && r <= R) {
			// cout << t[0].sum << endl;
			// cout << l << " " << r << " " << t[num].sum << " " << t[num].ans << endl;
			return t[num];
		}
		int mid = (l + r) >> 1;
		if (mid < L) return query(ri, L, R);
		if (mid >= R) return query(li, L, R);
		return query(li, L, R) + query(ri, L, R);
	}
} seg1;
struct segment2 {
	// int ls[N * 4], rs[N * 4], tot;
	// ll tag[2][N * 4];
	vector <array <int, 2>> tag;
	struct seg {
		ll ans, mx[2];
		inline seg operator + (const seg& t) {
			return {max(max(ans, t.ans), mx[0] + t.mx[1]), {max(mx[0], t.mx[0]), max(mx[1], t.mx[1])}};
		}
	};
	vector <seg> t;
	inline void resize(int mxn) {
		int N=1;
		while(N<=mxn) N<<=1;
		tag.resize(N<<1), t.resize(N<<1);
		return ;
	}
	inline void down(int k, int num, ll tt) {
		// cout << num << " " << tt << endl;
		tag[num][k] += tt;
		t[num].ans += tt;
		t[num].mx[k] += tt;
	}
	inline void pushdown(int num) {
		F(i, 0, 1)
			if (tag[num][i]) {
				down(i, ls, tag[num][i]);
				down(i, rs, tag[num][i]);
				tag[num][i] = 0;
			}
	}
	inline void modify(int num, int l, int r, int x, int y, ll z) {
		if (l == r) {
			t[num].mx[y] = z;
			t[num].ans = -1e18;
			return;
		} pushdown(num);
		int mid = (l + r) >> 1;
		if (mid >= x) modify(li, x, y, z);
		else modify(ri, x, y, z);
		t[num] = t[ls] + t[rs];
	}
	inline void change(int num, int l, int r, int L, int R, int x, int y) {
		if (L <= l && r <= R) {
			down(x, num, y);
			return;
		} pushdown(num);
		int mid = (l + r) >> 1;
		if (mid >= L) change(li, L, R, x, y);
		if (mid < R) change(ri, L, R, x, y);
		t[num] = t[ls] + t[rs];
	}
	inline seg query1(int num, int l, int r, int L, int R) {
		if (L <= l && r <= R) return t[num];
		pushdown(num);
		int mid = (l + r) >> 1;
		if (mid < L) return query1(ri, L, R);
		if (mid >= R) return query1(li, L, R);
		return query1(li, L, R) + query1(ri, L, R);
	}
	inline pair <ll, ll> query2(int num, int l, int r, int x) {
		if (l == r) return make_pair(-1e18, t[num].mx[1]);
		pushdown(num);
		int mid = (l + r) >> 1;
		if (mid >= x) {
			pair <ll, ll> tt = query2(li, x);
			return make_pair(tt.first, max(tt.second, t[rs].mx[1]));
		} pair <ll, ll> tt = query2(ri, x);
		return make_pair(max(tt.first, t[ls].mx[0]), tt.second);
	}
	inline ll query2(int num, int l, int r, int L, int R, int x) {
		if (L > R) return 0;
		if (L <= l && r <= R) return t[num].mx[x];
		pushdown(num);
		int mid = (l + r) >> 1;
		if (mid < L) return query2(ri, L, R, x);
		if (mid >= R) return query2(li, L, R, x);
		return max(query2(li, L, R, x), query2(ri, L, R, x));
	}
} seg[N];
struct segment3 {
	ll maxn[4194304];
	#define ls num << 1
	#define rs ls | 1
	inline void build(int num, int l, int r) {
		if (l == r) {
			maxn[num] = seg1.query(1, 1, n, (l - 1) * c + 1, l * c).ans;
			return;
		} int mid = (l + r) >> 1;
		build(li); build(ri);
		maxn[num] = max(maxn[ls], maxn[rs]);
	}
	inline void modify(int num, int l, int r, int x, ll y) {
		if (l == r) {
			maxn[num] = y;
			return;
		} int mid = (l + r) >> 1;
		if (mid >= x) modify(li, x, y);
		else modify(ri, x, y);
		maxn[num] = max(maxn[ls], maxn[rs]);
	}
	inline ll query(int num, int l, int r, int L, int R) {
		if (L > R) return 0;
		if (L <= l && r <= R) return maxn[num];
		int mid = (l + r) >> 1;
		if (mid < L) return query(ri, L, R);
		if (mid >= R) return query(li, L, R);
		return max(query(li, L, R), query(ri, L, R));
	}
} seg3, seg4;
signed main() {
	n = read(); m = read(); c = read();
	F(i, 1, n) a[i] = read();
	seg1.build(1, 1, n);
	tot = (n - 1) / c + 1;
	seg3.build(1, 1, tot);
	// F(i, 1, tot) seg3.modify(1, 1, tot, i, seg1.query(1, 1, n, l[i], r[i]).ans);
	// return 0;
	F(i, 1, tot - 1) {
		seg[i].resize(c);
		ll s = 0;
		int l1 = (i - 1) * c + 1, r1 = l1 + c - 1;
		DF(j, r1, l1) {
			s += a[j];
			seg[i].modify(1, 0, c, j - l1, 1, s);
		} s = 0;
		int l2 = r1 + 1, r2 = r1 + c;
		F(j, l2, r2) {
			s += a[j];
			seg[i].modify(1, 0, c, j - l2, 0, s);
		} seg4.modify(1, 1, tot, i, seg[i].t[1].ans);
	}
	F(_, 1, m) {
		int f = read(), x = read(), y = read();
		int numx = (x - 1) / c + 1, lx = (numx - 1) * c + 1, rx = numx * c;
		int numy = (y - 1) / c + 1, ly = (numy - 1) * c + 1, ry = numy * c;
		if (f == 1) {
			int k = y - a[x]; a[x] = y;
			seg1.modify(1, 1, n, x, a[x]);
			seg3.modify(1, 1, tot, numx, seg1.query(1, 1, n, lx, rx).ans);
			if (numx > 1) {
				seg[numx - 1].change(1, 0, c, x - lx, rx - lx, 0, k);
				seg4.modify(1, 1, tot, numx - 1, seg[numx - 1].t[1].ans);
			}
			if (numx < tot) {
				seg[numx].change(1, 0, c, 0, x - lx, 1, k);
				seg4.modify(1, 1, tot, numx, seg[numx].t[1].ans);
				// work2(numx);
			}
		} else {
			if (numx == numy) {
				print(max(0ll, seg1.query(1, 1, n, x, y).ans));
				continue;
			}
			ll ans = 0;
			chkmax(ans, seg1.query(1, 1, n, x, rx).ans);
			chkmax(ans, seg1.query(1, 1, n, ly, y).ans);
			if (numx + 1 == numy) {
				int l1 = x - lx;
				int l2 = 0, r2 = y - ly;
				if (l1 <= r2) {
					chkmax(ans, seg[numx].query1(1, 0, c, l1, r2).ans);
					pair <ll, ll> tmp = seg[numx].query2(1, 0, c, l1);
					chkmax(ans, tmp.first + tmp.second);
					tmp = seg[numx].query2(1, 0, c, r2 + 1);
					chkmax(ans, tmp.first + tmp.second);
				} else {
					chkmax(ans, seg[numx].query2(1, 0, c, l1, c, 1) + seg[numx].query2(1, 0, c, l2, r2, 0));
					// chkmax(ans, seg2.query2(rrt[numx], 0, c, max(l1, r2 + 1), r1, 1) + seg2.query2(rrt[numx], 0, c, l2, r2, 0));
				}
				print(ans);
				continue;
			}
			chkmax(ans, seg3.query(1, 1, tot, numx + 1, numy - 1));
			chkmax(ans, seg4.query(1, 1, tot, numx + 1, numy - 2));
			chkmax(ans, seg[numx].query1(1, 0, c, x - lx, c).ans);
			pair <ll, ll> tmp = seg[numx].query2(1, 0, c, x - lx);
			chkmax(ans, tmp.first + tmp.second);
			chkmax(ans, seg[numy - 1].query1(1, 0, c, 0, y - ly).ans);
			tmp = seg[numy - 1].query2(1, 0, c, y - ly + 1);
			chkmax(ans, tmp.first + tmp.second);
			print(ans);
		}
	} fwrite(obuf,O-obuf,1,stdout);
	return 0;
}

詳細信息

Test #1:

score: 100
Accepted
time: 18ms
memory: 98824kb

input:

5 6 3
0 -5 -3 8 -3
2 3 5
1 2 5
2 1 5
1 4 -3
2 3 5
2 1 5

output:

8
10
0
5

result:

ok 4 number(s): "8 10 0 5"

Test #2:

score: 0
Accepted
time: 497ms
memory: 160036kb

input:

200000 500000 1
387060158 961744470 37167782 737122872 -532977662 1604246 -30977399 871848791 444997246 454204578 -813187501 -660394286 448014171 -835115276 -631880452 887715308 258530352 805589560 -414653327 -156732249 -335096199 -80266237 367896009 738406627 -903652056 446120866 415658444 -1347916...

output:

999902477
999981999
999343404
999847372
999957587
998160312
999981999
999981999
999981999
999980061
999981999
999981999
999981999
999876122
999981999
999996602
999981999
999981999
999981999
999723649
999981999
999957587
999896087
999981999
999981999
999981999
999981999
999981999
999957587
999981999
...

result:

ok 250051 numbers

Test #3:

score: -100
Wrong Answer
time: 468ms
memory: 142936kb

input:

200000 500000 5
802774074 383481934 -295470374 285359286 751657057 197444479 626916547 -828168464 288373833 -493446966 -208422769 956745384 919286225 959643271 -176531848 -380256966 357111771 -50890039 -637284768 -337010918 259019684 752475630 -259898780 98620995 -704832505 -532710796 -971600790 -84...

output:

4544135313
4544135313
4443416295
3390067591
4544135313
4544135313
4322308420
4386413596
4386413596
4165697630
4322308420
4287938127
4443416295
4544135313
4386413596
4165697630
4386413596
4386413596
4386413596
4323325838
4443416295
4386413596
4385851999
4544135313
4443416295
4443416295
4323325838
432...

result:

wrong answer 12040th numbers differ - expected: '4323325838', found: '5044550592'