QOJ.ac

QOJ

ID题目提交者结果用时内存语言文件大小提交时间测评时间
#273801#7105. Pixel Artikaurov#AC ✓633ms28484kbC++204.5kb2023-12-03 04:19:262023-12-03 04:19:27

Judging History

你现在查看的是最新测评结果

  • [2023-12-03 04:19:27]
  • 评测
  • 测评结果:AC
  • 用时:633ms
  • 内存:28484kb
  • [2023-12-03 04:19:26]
  • 提交

answer

#include <bits/stdc++.h>
using namespace std;
typedef long long ll;
typedef vector<int> vi;
typedef vector<long long> vll;
typedef pair<int, int> pii;
typedef pair<ll, ll> pll;
typedef pair<double, double> pdd;
typedef long double ld;
const ld PI = acosl(-1);
const ll mod7 = 1e9 + 7;
const ll mod9 = 998244353;
const ll INF = 2 * 1024 * 1024 * 1023;
const char nl = '\n';
#define forn(i, n) for (int i = 0; i < int(n); i++)
#define all(v) v.begin(),v.end()
#pragma GCC optimize("O2")
// #pragma GCC target("avx2,bmi,bmi2,lzcnt,popcnt")
#include <ext/pb_ds/assoc_container.hpp> 
#include <ext/pb_ds/tree_policy.hpp>
using namespace __gnu_pbds;
template<class T> using ordered_set = tree<T, null_type , less<T> , rb_tree_tag , tree_order_statistics_node_update>;
 
ll l, r, k, n, m, p, q, u, v, w, x, y, z;
string s, t;
 
vi d4x = {1, 0, -1, 0};
vi d4y = {0, 1, 0, -1};
vi d8x = {1, 0, -1, 0, 1, 1, -1, -1};
vi d8y = {0, 1, 0, -1, 1, -1, 1, -1};
 
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
 
////////////////////  LIBRARY CODE ////////////////////
struct DSU {
    vector<int> e;
 
    DSU(int N) { 
        e = vector<int>(N, -1); 
    }
 
    // get representive component (uses path compression)
    int get(int x) { return e[x] < 0 ? x : e[x] = get(e[x]); }
 
    bool same_set(int a, int b) { return get(a) == get(b); }
 
    int size(int x) { return -e[get(x)]; }
 
    bool unite(int x, int y) {  // union by size, merge y into x
        x = get(x), y = get(y);
        if (x == y) return false;
        if (e[x] > e[y]) swap(x, y);
        e[x] += e[y]; e[y] = x;
        return true;
    }
};
///////////////////////////////////////////////////////

vector<vi> hor[100010];
vector<vi> vert[100010];

int check(int x, int y) {

  auto ptr = lower_bound(all(hor[x]), vi{y, (int)1e9, (int)1e9});

  if(ptr != hor[x].begin()) {
    ptr--;
    if((*ptr)[1] >= y) return (*ptr)[2];
  }

  ptr = lower_bound(all(vert[y]), vi{x, (int)1e9, (int)1e9});

  if(ptr != vert[y].begin()) {
    ptr--;
    if((*ptr)[1] >= x) return (*ptr)[2];
  }

  return -1;
}

bool multiTest = 1;
void solve(int tt) {

  cin >> n >> m >> k;

  vector<vi> lines;

  set<int> cols;

  vi d2(n+10, 0);
  vi d1(n+10, 0);

  vi newComponent(n+10, 0);

  forn(i, k) {
    ll x1, x2, y1, y2;
    cin >> x1 >> y1 >> x2 >> y2;
    lines.push_back({x1, y1, x2, y2});
    if(x1 == x2) {
      hor[x1].push_back({y1, y2, i});
      newComponent[x1]++;
      d1[x1] += y2 + 1 - y1;
    }
    else {
      vert[y1].push_back({x1, x2, i});
      newComponent[x1]++;
      d2[x1]++;
      d2[x2+1]--;
      cols.insert(y1);
    }
  }

  for(int i = 1; i <= n; i++) {
    sort(all(hor[i]));
  }

  for(int z : cols) {
    sort(all(vert[z]));
  }

  // for(int i = 1; i <= n; i++) {
  //   for(int j = 1; j <= m; j++) cout << check(i, j) << ' ';
  //   cout << nl;
  // }

  vector<pii> edges[n+10];

  forn(i, k) {

    forn(dir, 4) {
      int newX = lines[i][0] + d4x[dir];
      int newY = lines[i][1] + d4y[dir];

      if(newX <= 0 || newX > n || newY <= 0 || newY > m) continue;
      int spot = check(newX, newY);
      if(spot == -1 || spot == i) continue;

      int requiredRow = max(newX, lines[i][0]);
      edges[requiredRow].push_back({i, spot});
    }

    forn(dir, 4) {
      int newX = lines[i][2] + d4x[dir];
      int newY = lines[i][3] + d4y[dir];

      if(newX <= 0 || newX > n || newY <= 0 || newY > m) continue;
      int spot = check(newX, newY);
      if(spot == -1 || spot == i) continue;

      int requiredRow = max(newX, lines[i][0]);
      edges[requiredRow].push_back({i, spot});
    }
  }

  // for(int i = 1; i <= 3; i++) {
  //   cout << i << nl;
  //   for(auto[y, z] : edges[i]) cout << y << ' ' << z << nl;
  // }

  ll curAns1 = 0;
  ll curVert = 0;

  ll curAns2 = 0;

  DSU graphDSU(k+10);
  for(int i = 1; i <= n; i++) {
    curAns1 += d1[i];
    curVert += d2[i];
    curAns1 += curVert;

    curAns2 += newComponent[i];
    for(auto [y, z] : edges[i]) {
      if(graphDSU.same_set(y, z)) continue;
      curAns2--;
      graphDSU.unite(y, z);
    }
    cout << curAns1 << ' ' << curAns2 << nl;

  }

  for(int i = 1; i <= n; i++) hor[i].clear();
  for(int z : cols) vert[z].clear();
 
}
 
 
 
int main() {
 
    ios::sync_with_stdio(0);
    cin.tie(0);
    cout.tie(0);
 
    cout << fixed << setprecision(14);
 
    int t = 1;
    if (multiTest) cin >> t;
    for (int ii = 0; ii < t; ii++) {
        solve(ii);
    }
}

这程序好像有点Bug,我给组数据试试?

详细

Test #1:

score: 100
Accepted
time: 0ms
memory: 8256kb

input:

3
2 5 2
1 1 1 2
2 3 2 5
2 5 2
1 1 1 3
2 3 2 5
3 3 3
1 1 1 2
3 1 3 2
1 3 2 3

output:

2 1
5 2
3 1
6 1
3 1
4 1
6 2

result:

ok 7 lines

Test #2:

score: 0
Accepted
time: 633ms
memory: 28484kb

input:

2130
2 5 2
1 1 1 2
2 3 2 5
2 5 2
1 1 1 3
2 3 2 5
3 3 3
1 1 1 2
3 1 3 2
1 3 2 3
3 100 51
1 2 2 2
1 4 2 4
1 6 2 6
1 8 2 8
1 10 2 10
1 12 2 12
1 14 2 14
1 16 2 16
1 18 2 18
1 20 2 20
1 22 2 22
1 24 2 24
1 26 2 26
1 28 2 28
1 30 2 30
1 32 2 32
1 34 2 34
1 36 2 36
1 38 2 38
1 40 2 40
1 42 2 42
1 44 2 44
...

output:

2 1
5 2
3 1
6 1
3 1
4 1
6 2
50 50
100 50
200 1
50 50
150 1
200 1
2 1
4 1
6 1
8 1
10 1
12 1
14 1
16 1
18 1
20 1
22 1
24 1
26 1
28 1
30 1
32 1
34 1
36 1
38 1
40 1
42 1
44 1
46 1
48 1
50 1
52 1
54 1
56 1
58 1
60 1
62 1
64 1
66 1
68 1
70 1
72 1
74 1
76 1
78 1
80 1
82 1
84 1
86 1
88 1
90 1
92 1
94 1
96 1...

result:

ok 355756 lines

Extra Test:

score: 0
Extra Test Passed