QOJ.ac
QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#273466 | #1944. Circle of Friends | ucup-team1576 | Compile Error | / | / | C++14 | 3.3kb | 2023-12-03 00:08:32 | 2023-12-03 00:08:33 |
Due to the privacy settings of the submitter, you are not allowed to view this code.
詳細信息
answer.code:3:18: error: declaration does not declare anything [-fpermissive] 3 | #define int long long; | ^~~~ answer.code:4:7: note: in expansion of macro ‘int’ 4 | const int N = 4e5 + 7, W = 20, Mod = 998244353; | ^~~ answer.code:4:11: error: ‘N’ does not name a type 4 | const int N = 4e5 + 7, W = 20, Mod = 998244353; | ^ answer.code:3:18: error: declaration does not declare anything [-fpermissive] 3 | #define int long long; | ^~~~ answer.code:7:1: note: in expansion of macro ‘int’ 7 | int n; i64 a[N]; | ^~~ answer.code:7:5: error: ‘n’ does not name a type 7 | int n; i64 a[N]; | ^ answer.code:7:14: error: ‘N’ was not declared in this scope 7 | int n; i64 a[N]; | ^ answer.code:3:18: error: declaration does not declare anything [-fpermissive] 3 | #define int long long; | ^~~~ answer.code:10:5: note: in expansion of macro ‘int’ 10 | int x; | ^~~ answer.code:10:9: error: ‘x’ does not name a type 10 | int x; | ^ answer.code:3:22: error: expected ‘)’ before ‘;’ token 3 | #define int long long; | ^ answer.code:11:12: note: in expansion of macro ‘int’ 11 | Modint(int o = 0) { x = o; } | ^~~ answer.code:11:11: note: to match this ‘(’ 11 | Modint(int o = 0) { x = o; } | ^ answer.code:11:16: error: ‘o’ does not name a type 11 | Modint(int o = 0) { x = o; } | ^ answer.code:3:22: error: expected ‘)’ before ‘;’ token 3 | #define int long long; | ^ answer.code:12:25: note: in expansion of macro ‘int’ 12 | Modint &operator = (int o) { return x = o, *this; } | ^~~ answer.code:12:24: note: to match this ‘(’ 12 | Modint &operator = (int o) { return x = o, *this; } | ^ answer.code:12:29: error: ‘o’ does not name a type 12 | Modint &operator = (int o) { return x = o, *this; } | ^ answer.code:3:22: error: expected ‘)’ before ‘;’ token 3 | #define int long long; | ^ answer.code:16:26: note: in expansion of macro ‘int’ 16 | Modint &operator ^= (int b) { Modint a = *this, c = 1; for (; b; b >>= 1, a *= a) if (b & 1) c *= a; return x = c.x, *this; } | ^~~ answer.code:16:25: note: to match this ‘(’ 16 | Modint &operator ^= (int b) { Modint a = *this, c = 1; for (; b; b >>= 1, a *= a) if (b & 1) c *= a; return x = c.x, *this; } | ^ answer.code:16:30: error: ‘b’ does not name a type 16 | Modint &operator ^= (int b) { Modint a = *this, c = 1; for (; b; b >>= 1, a *= a) if (b & 1) c *= a; return x = c.x, *this; } | ^ answer.code:3:22: error: expected ‘)’ before ‘;’ token 3 | #define int long long; | ^ answer.code:18:25: note: in expansion of macro ‘int’ 18 | Modint &operator +=(int o) { return x = x + o >= Mod ? x + o - Mod : x + o, *this; } | ^~~ answer.code:18:24: note: to match this ‘(’ 18 | Modint &operator +=(int o) { return x = x + o >= Mod ? x + o - Mod : x + o, *this; } | ^ answer.code:18:29: error: ‘o’ does not name a type 18 | Modint &operator +=(int o) { return x = x + o >= Mod ? x + o - Mod : x + o, *this; } | ^ answer.code:3:22: error: expected ‘)’ before ‘;’ token 3 | #define int long long; | ^ answer.code:19:25: note: in expansion of macro ‘int’ 19 | Modint &operator -=(int o) { return x = x - o < 0 ? x - o + Mod : x - o, *this; } | ^~~ answer.code:19:24: note: to match this ‘(’ 19 | Modint &operator -=(int o) { return x = x - o < 0 ? x - o + Mod : x - o, *this; } | ^ answer.code:19:29: error: ‘o’ does not name a type 19 | Modint &operator -=(int o) { return x = x - o < 0 ? x - o + Mod : x - o, *this; } | ^ answer.code:3:22: error: expected ‘)’ before ‘;’ token 3 | #define int long long; | ^ answer.code:20:25: note: in expansion of macro ‘int’ 20 | Modint &operator *=(int o) { return x = 1ll * x * o % Mod, *this; } | ^~~ answer.code:20:24: note: to match this ‘(’ 20 | Modint &operator *=(int o) { return x = 1ll * x * o % Mod, *this; } | ^ answer.code:20:29: error: ‘o’ does not name a type 20 | Modint &operator *=(int o) { return x = 1ll * x * o % Mod, *this; } | ^ answer.code:3:22: error: expected ‘)’ before ‘;’ token 3 | #define int long long; | ^ answer.code:21:25: note: ...