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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#273455#7883. Takeout Deliveringucup-team088#WA 261ms56480kbC++178.4kb2023-12-03 00:02:552023-12-03 00:02:55

Judging History

你现在查看的是最新测评结果

  • [2023-12-03 00:02:55]
  • 评测
  • 测评结果:WA
  • 用时:261ms
  • 内存:56480kb
  • [2023-12-03 00:02:55]
  • 提交

answer

#pragma GCC optimize("O3")
#pragma GCC optimize("unroll-loops")
#include<iostream>
#include<string>
#include<cstdio>
#include<vector>
#include<cmath>
#include<algorithm>
#include<functional>
#include<iomanip>
#include<queue>
#include<ciso646>
#include<random>
#include<map>
#include<set>
#include<bitset>
#include<stack>
#include<unordered_map>
#include<unordered_set>
#include<utility>
#include<cassert>
#include<complex>
#include<numeric>
#include<array>
#include<chrono>
using namespace std;

//#define int long long
typedef long long ll;

typedef unsigned long long ul;
typedef unsigned int ui;
//ll mod = 1;
constexpr ll mod = 998244353;
//constexpr ll mod = 1000000007;
const int mod17 = 1000000007;
const ll INF = (ll)mod17 * mod17;
typedef pair<int, int>P;

#define rep(i,n) for(int i=0;i<n;i++)
#define per(i,n) for(int i=n-1;i>=0;i--)
#define Rep(i,sta,n) for(int i=sta;i<n;i++)
#define rep1(i,n) for(int i=1;i<=n;i++)
#define per1(i,n) for(int i=n;i>=1;i--)
#define Rep1(i,sta,n) for(int i=sta;i<=n;i++)
#define all(v) (v).begin(),(v).end()
typedef pair<ll, ll> LP;

using ld = double;
typedef pair<ld, ld> LDP;
const ld eps = 1e-10;
const ld pi = acosl(-1.0);

template<typename T>
void chmin(T& a, T b) {
    a = min(a, b);
}
template<typename T>
void chmax(T& a, T b) {
    a = max(a, b);
}
template<typename T>
vector<T> vmerge(vector<T>& a, vector<T>& b) {
    vector<T> res;
    int ida = 0, idb = 0;
    while (ida < a.size() || idb < b.size()) {
        if (idb == b.size()) {
            res.push_back(a[ida]); ida++;
        }
        else if (ida == a.size()) {
            res.push_back(b[idb]); idb++;
        }
        else {
            if (a[ida] < b[idb]) {
                res.push_back(a[ida]); ida++;
            }
            else {
                res.push_back(b[idb]); idb++;
            }
        }
    }
    return res;
}
template<typename T>
void cinarray(vector<T>& v) {
    rep(i, v.size())cin >> v[i];
}
template<typename T>
void coutarray(vector<T>& v) {
    rep(i, v.size()) {
        if (i > 0)cout << " "; cout << v[i];
    }
    cout << "\n";
}
ll mod_pow(ll x, ll n, ll m = mod) {
    if (n < 0) {
        ll res = mod_pow(x, -n, m);
        return mod_pow(res, m - 2, m);
    }
    if (abs(x) >= m)x %= m;
    if (x < 0)x += m;
    //if (x == 0)return 0;
    ll res = 1;
    while (n) {
        if (n & 1)res = res * x % m;
        x = x * x % m; n >>= 1;
    }
    return res;
}
//mod should be <2^31
struct modint {
    int n;
    modint() :n(0) { ; }
    modint(ll m) {
        if (m < 0 || mod <= m) {
            m %= mod; if (m < 0)m += mod;
        }
        n = m;
    }
    operator int() { return n; }
};
bool operator==(modint a, modint b) { return a.n == b.n; }
bool operator<(modint a, modint b) { return a.n < b.n; }
modint operator+=(modint& a, modint b) { a.n += b.n; if (a.n >= mod)a.n -= (int)mod; return a; }
modint operator-=(modint& a, modint b) { a.n -= b.n; if (a.n < 0)a.n += (int)mod; return a; }
modint operator*=(modint& a, modint b) { a.n = ((ll)a.n * b.n) % mod; return a; }
modint operator+(modint a, modint b) { return a += b; }
modint operator-(modint a, modint b) { return a -= b; }
modint operator*(modint a, modint b) { return a *= b; }
modint operator^(modint a, ll n) {
    if (n == 0)return modint(1);
    modint res = (a * a) ^ (n / 2);
    if (n % 2)res = res * a;
    return res;
}

ll inv(ll a, ll p) {
    return (a == 1 ? 1 : (1 - p * inv(p % a, a)) / a + p);
}
modint operator/(modint a, modint b) { return a * modint(inv(b, mod)); }
modint operator/=(modint& a, modint b) { a = a / b; return a; }
const int max_n = 1 << 20;
modint fact[max_n], factinv[max_n];
void init_f() {
    fact[0] = modint(1);
    for (int i = 0; i < max_n - 1; i++) {
        fact[i + 1] = fact[i] * modint(i + 1);
    }
    factinv[max_n - 1] = modint(1) / fact[max_n - 1];
    for (int i = max_n - 2; i >= 0; i--) {
        factinv[i] = factinv[i + 1] * modint(i + 1);
    }
}
modint comb(int a, int b) {
    if (a < 0 || b < 0 || a < b)return 0;
    return fact[a] * factinv[b] * factinv[a - b];
}
modint combP(int a, int b) {
    if (a < 0 || b < 0 || a < b)return 0;
    return fact[a] * factinv[a - b];
}

ll gcd(ll a, ll b) {
    a = abs(a); b = abs(b);
    if (a < b)swap(a, b);
    while (b) {
        ll r = a % b; a = b; b = r;
    }
    return a;
}
template<typename T>
void addv(vector<T>& v, int loc, T val) {
    if (loc >= v.size())v.resize(loc + 1, 0);
    v[loc] += val;
}
/*const int mn = 2000005;
bool isp[mn];
vector<int> ps;
void init() {
    fill(isp + 2, isp + mn, true);
    for (int i = 2; i < mn; i++) {
        if (!isp[i])continue;
        ps.push_back(i);
        for (int j = 2 * i; j < mn; j += i) {
            isp[j] = false;
        }
    }
}*/

//[,val)
template<typename T>
auto prev_itr(set<T>& st, T val) {
    auto res = st.lower_bound(val);
    if (res == st.begin())return st.end();
    res--; return res;
}

//[val,)
template<typename T>
auto next_itr(set<T>& st, T val) {
    auto res = st.lower_bound(val);
    return res;
}
using mP = pair<modint, modint>;
mP operator+(mP a, mP b) {
    return { a.first + b.first,a.second + b.second };
}
mP operator+=(mP& a, mP b) {
    a = a + b; return a;
}
mP operator-(mP a, mP b) {
    return { a.first - b.first,a.second - b.second };
}
mP operator-=(mP& a, mP b) {
    a = a - b; return a;
}
LP operator+(LP a, LP b) {
    return { a.first + b.first,a.second + b.second };
}
LP operator+=(LP& a, LP b) {
    a = a + b; return a;
}
LP operator-(LP a, LP b) {
    return { a.first - b.first,a.second - b.second };
}
LP operator-=(LP& a, LP b) {
    a = a - b; return a;
}

mt19937 mt(time(0));

const string drul = "DRUL";
string senw = "SENW";
//DRUL,or SENW
//int dx[4] = { 1,0,-1,0 };
//int dy[4] = { 0,1,0,-1 };

//------------------------------------

struct edge {
    int to, cost;
};
void solve() {
    int n, m; cin >> n >> m;
    vector<ll> dl(n, INF);
    vector<ll> dr(n, INF);
    dl[0] = 0;
    dr[n - 1] = 0;
    ll ans = INF;
    vector<vector<edge>> G(n);
    vector<pair<int, P>> vp;
    rep(i, m) {
        int a, b, c; cin >> a >> b >> c; a--; b--;
        vp.push_back({ c,{a,b} });
        G[a].push_back({ b,c });
        G[b].push_back({ a,c });
    }
    sort(all(vp));
    vector<vector<int>> vs(n);
    rep(i, n)vs[i].push_back(i);
    vector<int> par(n); rep(i, n)par[i] = i;
    auto find_par = [&](int id) {
        while (par[id] != id) {
            id = par[id];
        }
        return id;
    };
    for (edge e : G[0]) {
        chmin(dl[e.to], (ll)e.cost);
    }
    for (edge e : G[n - 1]) {
        chmin(dr[e.to], (ll)e.cost);
    }
    chmin(ans, dl[n - 1]);
    chmin(ans, dr[0]);

    int idl = 0, idr = n - 1;
    rep(i, vp.size()) {
        int c = vp[i].first;
        int a = vp[i].second.first;
        int b = vp[i].second.second;
        a = find_par(a);
        b = find_par(b);
        if (a == b)continue;
        idl = find_par(idl);
        idr = find_par(idr);
        if (idl == a || idl == b) {
            if (idl == b)swap(a, b);
            if (idr == b) {
                chmin(ans, (ll)2 * c);
                break;
            }
            chmin(ans, dr[b] + c);
            for (int id : vs[b]) {
                for (edge e : G[id]) {
                    int to = find_par(e.to);
                    chmin(dl[e.to], (ll)e.cost);
                }
            }
        }
        if (idr == a || idr == b) {
            if (idr == b)swap(a, b);
            chmin(ans, dl[b] + c);
            for (int id : vs[b]) {
                for (edge e : G[id]) {
                    int to = find_par(e.to);
                    chmin(dr[e.to], (ll)e.cost);
                }
            }
        }
        if (vs[a].size() > vs[b].size()) {
            swap(a, b);
        }
        par[a] = b;
        for (int id : vs[a])vs[b].push_back(id);
        vs[a].clear(); vs[a].shrink_to_fit();
        chmin(dl[b], dl[a]);
        chmin(dr[b], dr[a]);

        /*coutarray(par);
        coutarray(dl);
        coutarray(dr);*/
    }
    cout << ans << "\n";
}



signed main() {
    ios::sync_with_stdio(false);
    cin.tie(0);
    //cout << fixed<<setprecision(10);
    //init_f();
    //init();
    //while(true)
    //expr();
    //int t; cin >> t; rep(i, t)
    solve();
    return 0;
}

详细

Test #1:

score: 100
Accepted
time: 6ms
memory: 11892kb

input:

4 6
1 2 2
1 3 4
1 4 7
2 3 1
2 4 3
3 4 9

output:

5

result:

ok 1 number(s): "5"

Test #2:

score: -100
Wrong Answer
time: 261ms
memory: 56480kb

input:

300000 299999
80516 80517 597830404
110190 110191 82173886
218008 218009 954561262
250110 250111 942489774
66540 66541 156425292
34947 34948 239499776
273789 273790 453201232
84428 84429 439418398
98599 98600 326095035
55636 55637 355015760
158611 158612 684292473
43331 43332 43265001
171621 171622 ...

output:

1999993064

result:

wrong answer 1st numbers differ - expected: '1999991697', found: '1999993064'