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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#271261#7738. Equivalent Rewritingiorit#WA 4ms63260kbC++142.9kb2023-12-02 08:44:322023-12-02 08:44:32

Judging History

你现在查看的是最新测评结果

  • [2023-12-02 08:44:32]
  • 评测
  • 测评结果:WA
  • 用时:4ms
  • 内存:63260kb
  • [2023-12-02 08:44:32]
  • 提交

answer

#include <bits/stdc++.h>
using namespace std;

namespace IO {
	#if ONLINE_JUDGE
	#define getc() (IS == IT && (IT = (IS = ibuf) + fread(ibuf, 1, IL, stdin), IS == IT) ? EOF : *IS++)
	#else
	#define getc() getchar()
	#endif
	const int IL = 1 << 21, OL = 1 << 21;
	int olen = 0;
	char ibuf[IL], *IS = ibuf, *IT = ibuf, obuf[OL];
	inline int read() {
		register char ch = getc(); register int x = 0, f = 1;
		while(!isdigit(ch)) { if(ch == '-') f = -1; ch = getc(); }
		while(isdigit(ch)) x = x * 10 + ch - 48, ch = getc();
		return x * f;
	}
	inline double readdb() {
		register char ch = getc(); register double x = 0, f = 1;
		while(!isdigit(ch)) { if(ch == '-') f = -1; ch = getc(); }
		while(isdigit(ch)) x = x * 10 + ch - 48, ch = getc();
		if(ch == '.') {
			register double b = 0.1;
			ch = getc();
			while(isdigit(ch)) x += (ch - 48) * b, b *= 0.1, ch = getc();
		}
		return x * f;
	}
	inline int readstr(char *s) {
		register char ch = getc(); register int len = 0;
		while(!isalpha(ch)) ch = getc();
		while(isalpha(ch)) s[++len] = ch, ch = getc();
		return len;
	}
	inline void flush() { fwrite(obuf, 1, olen, stdout); olen = 0; }
	inline void putc(register char ch) { obuf[olen++] = ch; }
	template<class T>
	inline void write(register T x) {
		if(x < 0) obuf[olen++] = '-', x = -x;
		if(x > 9) write(x / 10);
		obuf[olen++] = x % 10 + 48;
	}
} using namespace IO;
const int N = 1e6 + 10;
int T, n, m, a[N], pre[N], col[N];
vector<int> vc[N], ans[N];
bool vis[N];
int cnt[N];
void MAIN() {
	n = read(), m = read();
	for(int i = 1; i <= m; i++)
		a[i] = col[i] = 0;
	for(int i = 1; i <= n; i++) {
		cnt[i] = vis[i] = pre[i] = 0;
		int x = read();
		vc[i].clear();
		ans[i].clear();
		for(int j = 1; j <= x; j++) {
			int y = read();
			a[y] = i;
			vc[i].push_back(y);
		}
	}
	for(int i = 1; i <= m; i++)
		vis[a[i]] = 1;
	for(int i = 1; i <= n; i++)
		if(!vis[i]) {
			puts("Yes");
			printf("%d ", i);
			if(i == n) {
				for(int j=  1; j < n; j++)
					if(j < n - 1)printf("%d ", j);
					else printf("%d\n", j);
			}
			else {
				for(int j = 1; j <= n; j++) {
					if(j == i) continue;
					if(j < n) printf("%d ", j);
					else printf("%d\n", j);
				}
			}
			return;
		}
	for(int i = 1; i <= n; i++) {
		for(auto x : vc[i]) {
			if(a[x] == i) { pre[i] = max(pre[i], col[x]); }
//			if(x==3)cout<<"!:"<<col[x]<<endl; 
			col[x] = i;

		}
		cnt[pre[i] + 1]++;
		ans[pre[i] + 1].push_back(i);
	}
//	for(int i = 1; i <= n; i++)
//		printf("cnt:%d %d\n", i, cnt[i]);
	bool flg = 0;
	for(int i = 1; i <= n; i++)
		if(cnt[i] != 1) {
			flg = 1;
			break;
		}
	if(!flg) {
		puts("No");
		return;
	}
	puts("Yes");
	int t = 0;
	for(int i = 1; i <= n; i++) {
		reverse(ans[i].begin(), ans[i].end());
		for(auto x : ans[i]) {
			printf("%d", x);
			t++;
			if(t != n) printf(" ");
			else printf("\n");
		}
	}
}
int main() {
	T = read();
	while(T--) MAIN();
	return 0;
}

详细

Test #1:

score: 100
Accepted
time: 3ms
memory: 61184kb

input:

3
3 6
3 3 1 5
2 5 3
2 2 6
2 3
3 1 3 2
2 3 1
1 3
2 2 1

output:

Yes
3 1 2
No
No

result:

ok OK. (3 test cases)

Test #2:

score: -100
Wrong Answer
time: 4ms
memory: 63260kb

input:

1
10 5
2 2 4
4 1 3 4 2
1 2
3 2 1 4
4 5 2 4 3
3 2 5 4
3 5 4 2
3 1 3 2
5 1 4 2 3 5
1 4

output:

Yes
1 2 3 4 5 6 7 8 9 10

result:

wrong answer two transactions are same. (test case 1)