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QOJ
ID | Problem | Submitter | Result | Time | Memory | Language | File size | Submit time | Judge time |
---|---|---|---|---|---|---|---|---|---|
#270952 | #7744. Elevator | ucup-team134# | AC ✓ | 75ms | 6484kb | C++17 | 4.6kb | 2023-12-01 18:50:40 | 2023-12-01 18:50:41 |
Judging History
answer
#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
#include <ext/rope>
#define ll long long
#define pb push_back
#define f first
#define s second
#define sz(x) (int)(x).size()
#define all(x) x.begin(), x.end()
#define rall(x) x.rbegin(), x.rend()
#define ios ios_base::sync_with_stdio(false);cin.tie(NULL)
#define ld long double
#define li __int128
using namespace std;
using namespace __gnu_pbds;
using namespace __gnu_cxx;
mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
template<class T> using ordered_set = tree<T, null_type, less<T>, rb_tree_tag,tree_order_statistics_node_update>; ///find_by_order(),order_of_key()
template<int D, typename T>struct vec : public vector<vec<D - 1, T>> {template<typename... Args>vec(int n = 0, Args... args) : vector<vec<D - 1, T>>(n, vec<D - 1, T>(args...)) {}};
template<typename T>struct vec<1, T> : public vector<T> {vec(int n = 0, T val = T()) : vector<T>(n, val) {}};
template<class T1,class T2> ostream& operator<<(ostream& os, const pair<T1,T2>& a) { os << '{' << a.f << ", " << a.s << '}'; return os; }
template<class T> ostream& operator<<(ostream& os, const vector<T>& a){os << '{';for(int i=0;i<sz(a);i++){if(i>0&&i<sz(a))os << ", ";os << a[i];}os<<'}';return os;}
template<class T> ostream& operator<<(ostream& os, const deque<T>& a){os << '{';for(int i=0;i<sz(a);i++){if(i>0&&i<sz(a))os << ", ";os << a[i];}os<<'}';return os;}
template<class T> ostream& operator<<(ostream& os, const set<T>& a) {os << '{';int i=0;for(auto p:a){if(i>0&&i<sz(a))os << ", ";os << p;i++;}os << '}';return os;}
template<class T> ostream& operator<<(ostream& os, const set<T,greater<T> >& a) {os << '{';int i=0;for(auto p:a){if(i>0&&i<sz(a))os << ", ";os << p;i++;}os << '}';return os;}
template<class T> ostream& operator<<(ostream& os, const multiset<T>& a) {os << '{';int i=0;for(auto p:a){if(i>0&&i<sz(a))os << ", ";os << p;i++;}os << '}';return os;}
template<class T> ostream& operator<<(ostream& os, const multiset<T,greater<T> >& a) {os << '{';int i=0;for(auto p:a){if(i>0&&i<sz(a))os << ", ";os << p;i++;}os << '}';return os;}
template<class T1,class T2> ostream& operator<<(ostream& os, const map<T1,T2>& a) {os << '{';int i=0;for(auto p:a){if(i>0&&i<sz(a))os << ", ";os << p;i++;}os << '}';return os;}
int ri(){int x;scanf("%i",&x);return x;}
void rd(int&x){scanf("%i",&x);}
void rd(long long&x){scanf("%lld",&x);}
void rd(double&x){scanf("%lf",&x);}
void rd(long double&x){scanf("%Lf",&x);}
void rd(string&x){cin>>x;}
void rd(char*x){scanf("%s",x);}
template<typename T1,typename T2>void rd(pair<T1,T2>&x){rd(x.first);rd(x.second);}
template<typename T>void rd(vector<T>&x){for(T&p:x)rd(p);}
template<typename C,typename...T>void rd(C&a,T&...args){rd(a);rd(args...);}
//istream& operator>>(istream& is,__int128& a){string s;is>>s;a=0;int i=0;bool neg=false;if(s[0]=='-')neg=true,i++;for(;i<s.size();i++)a=a*10+s[i]-'0';if(neg)a*=-1;return is;}
//ostream& operator<<(ostream& os,__int128 a){bool neg=false;if(a<0)neg=true,a*=-1;ll high=(a/(__int128)1e18);ll low=(a-(__int128)1e18*high);string res;if(neg)res+='-';if(high>0){res+=to_string(high);string temp=to_string(low);res+=string(18-temp.size(),'0');res+=temp;}else res+=to_string(low);os<<res;return os;}
const int N=1e5+5;
ll cnt[N][3];
void test(){
int n;
ll k;
rd(n,k);
vector<int> pos(n);
for(int i=0;i<n;i++){
int c,w,f;
rd(c,w,f);
pos[i]=f;
cnt[f][w]+=c;
}
sort(all(pos));
pos.erase(unique(all(pos)),pos.end());
reverse(all(pos));
ll ans=0;
ll lastCap=0;
int cntLeft1=0;
for(auto p:pos){
ll needFull=(2*cnt[p][2])/k;
ans+=needFull*p;
cnt[p][2]-=needFull*(k/2);
ll moguLast=min(cnt[p][2],lastCap/2);
cnt[p][2]-=moguLast;
lastCap-=2*moguLast;
if(lastCap==1){
if(cntLeft1){
lastCap=2;
if(cnt[p][2]){
lastCap=0;
cnt[p][2]--;
}
}
else{
lastCap=0;
}
cntLeft1^=1;
}
if(cnt[p][2]){
ans+=p;
lastCap=k-2*cnt[p][2];
}
needFull=(cnt[p][1])/k;
ans+=needFull*p;
cnt[p][1]-=needFull*k;
// take from last cap
ll take=min(cnt[p][1],lastCap);
cnt[p][1]-=take;
lastCap-=take;
if(cnt[p][1]&&cntLeft1){
cntLeft1=0;
cnt[p][1]--;
}
if(lastCap==1){ // will only happen if I have no more
if(cntLeft1){
lastCap=2;
}
else{
lastCap=0;
}
cntLeft1^=1;
}
// need to start a new one!
if(cnt[p][1]){
ans+=p;
lastCap=k-cnt[p][1];
}
}
printf("%lld\n",ans);
for(auto p:pos)cnt[p][1]=cnt[p][2]=0;
}
int main()
{
int t=ri();
while(t--)test();
return 0;
}
这程序好像有点Bug,我给组数据试试?
Details
Tip: Click on the bar to expand more detailed information
Test #1:
score: 100
Accepted
time: 1ms
memory: 3732kb
input:
2 4 6 1 1 8 7 2 5 1 1 7 3 2 6 8 1200000 100000 1 100000 100000 1 12345 100000 2 100000 100000 2 12345 100000 1 100000 100000 1 12345 100000 2 100000 100000 2 12345
output:
24 100000
result:
ok 2 lines
Test #2:
score: 0
Accepted
time: 41ms
memory: 6220kb
input:
5501 8 104 5 2 3 6 2 4 5 2 3 6 2 9 8 2 4 2 1 3 7 2 4 8 2 8 1 290 3 1 1 12 12 6 1 2 1 2 2 1 1 2 1 2 4 6 1 1 1 2 5 6 1 4 4 1 4 6 2 4 6 2 5 4 2 5 4 1 4 5 334 1 1 4 1 2 3 4 2 1 5 1 1 2 1 2 13 218 5 2 3 5 1 4 1 2 1 1 2 5 3 2 2 1 1 3 4 2 2 1 2 5 2 2 1 2 1 5 3 2 1 5 2 1 1 1 4 10 260 7 2 1 5 1 1 5 2 4 6 1 6...
output:
9 1 23 4 5 7 1 3 9 6 1 10 4 9 17 6 4 1 8 5 5 7 1 3 23 6 3 3 2 2 2 3 8 1 5 6 9 11 147 7 10 2 7 7 8 6 5 5 1 7 3 5 10 7 7 10 8 1 4 2 3 9 1 5 2 9 1 6 7 7 6 10 18 8 10 4 10 9 2 8 3 5 9 3 6 5 3 2 6 1 3 2 2 1 6 9 6 3 4 8 9 9 2 6 1 2 6 7 5 2 5 21 8 1 2 3 4 9 3 4 6 5 9 6 1 7 3 7 3 2 2 8 7 3 5 9 7 10 7 3 2 4 ...
result:
ok 5501 lines
Test #3:
score: 0
Accepted
time: 60ms
memory: 6384kb
input:
3 100000 8 8 2 6 7 2 8 5 1 10 7 2 7 4 1 7 6 2 9 7 1 2 3 1 1 5 1 10 5 1 1 3 2 10 5 2 5 7 1 6 5 2 7 7 2 1 5 1 6 2 2 10 8 1 7 7 1 1 10 2 6 9 1 1 8 1 4 10 1 4 6 1 1 4 1 4 1 2 9 3 2 6 6 1 3 4 1 7 9 2 5 8 2 4 7 2 1 2 2 10 6 2 9 3 1 3 2 2 3 2 2 4 7 2 4 8 1 1 5 2 3 5 2 7 7 2 9 1 1 4 5 1 2 2 1 9 3 2 1 9 2 2 ...
output:
568601 4708350936 93900404329230
result:
ok 3 lines
Test #4:
score: 0
Accepted
time: 75ms
memory: 6484kb
input:
3 100000 174 90429 1 64237 30851 1 44358 63571 2 89174 20391 2 28747 13561 2 88689 81508 2 28383 85733 1 5777 37524 2 34730 10588 2 88519 61493 2 83682 55885 1 65270 17669 2 63015 85387 1 64757 91420 2 74020 9067 2 91750 20809 1 52771 36478 2 17941 62064 1 36433 72912 2 6100 53923 2 73971 65825 2 39...
output:
2156004461915 884586357480 59034901233
result:
ok 3 lines
Test #5:
score: 0
Accepted
time: 65ms
memory: 6316kb
input:
3 100000 4418822 19907 1 13081 59730 2 93611 35050 1 5867 87777 1 21890 18374 1 82418 79526 2 76106 33510 2 45826 75573 1 42240 35449 1 98727 80720 2 65290 32021 2 51348 52399 2 97828 75498 2 51728 89905 1 22825 2855 1 26204 11427 1 99583 55530 2 37895 22256 2 92230 19533 1 9142 16138 1 54018 53102 ...
output:
84699074 270668 100000
result:
ok 3 lines
Extra Test:
score: 0
Extra Test Passed