QOJ.ac

QOJ

ID题目提交者结果用时内存语言文件大小提交时间测评时间
#270950#7744. Elevatorucup-team134#WA 41ms6200kbC++174.3kb2023-12-01 18:37:412023-12-01 18:37:41

Judging History

你现在查看的是最新测评结果

  • [2023-12-01 18:37:41]
  • 评测
  • 测评结果:WA
  • 用时:41ms
  • 内存:6200kb
  • [2023-12-01 18:37:41]
  • 提交

answer

#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
#include <ext/rope>

#define ll long long
#define pb push_back
#define f first
#define s second
#define sz(x) (int)(x).size()
#define all(x) x.begin(), x.end()
#define rall(x) x.rbegin(), x.rend()
#define ios ios_base::sync_with_stdio(false);cin.tie(NULL)
#define ld long double
#define li __int128

using namespace std;
using namespace __gnu_pbds;
using namespace __gnu_cxx;

mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());
template<class T> using ordered_set = tree<T, null_type, less<T>, rb_tree_tag,tree_order_statistics_node_update>; ///find_by_order(),order_of_key()
template<int D, typename T>struct vec : public vector<vec<D - 1, T>> {template<typename... Args>vec(int n = 0, Args... args) : vector<vec<D - 1, T>>(n, vec<D - 1, T>(args...)) {}};
template<typename T>struct vec<1, T> : public vector<T> {vec(int n = 0, T val = T()) : vector<T>(n, val) {}};
template<class T1,class T2> ostream& operator<<(ostream& os, const pair<T1,T2>& a) { os << '{' << a.f << ", " << a.s << '}'; return os; }
template<class T> ostream& operator<<(ostream& os, const vector<T>& a){os << '{';for(int i=0;i<sz(a);i++){if(i>0&&i<sz(a))os << ", ";os << a[i];}os<<'}';return os;}
template<class T> ostream& operator<<(ostream& os, const deque<T>& a){os << '{';for(int i=0;i<sz(a);i++){if(i>0&&i<sz(a))os << ", ";os << a[i];}os<<'}';return os;}
template<class T> ostream& operator<<(ostream& os, const set<T>& a) {os << '{';int i=0;for(auto p:a){if(i>0&&i<sz(a))os << ", ";os << p;i++;}os << '}';return os;}
template<class T> ostream& operator<<(ostream& os, const set<T,greater<T> >& a) {os << '{';int i=0;for(auto p:a){if(i>0&&i<sz(a))os << ", ";os << p;i++;}os << '}';return os;}
template<class T> ostream& operator<<(ostream& os, const multiset<T>& a) {os << '{';int i=0;for(auto p:a){if(i>0&&i<sz(a))os << ", ";os << p;i++;}os << '}';return os;}
template<class T> ostream& operator<<(ostream& os, const multiset<T,greater<T> >& a) {os << '{';int i=0;for(auto p:a){if(i>0&&i<sz(a))os << ", ";os << p;i++;}os << '}';return os;}
template<class T1,class T2> ostream& operator<<(ostream& os, const map<T1,T2>& a) {os << '{';int i=0;for(auto p:a){if(i>0&&i<sz(a))os << ", ";os << p;i++;}os << '}';return os;}
int ri(){int x;scanf("%i",&x);return x;}
void rd(int&x){scanf("%i",&x);}
void rd(long long&x){scanf("%lld",&x);}
void rd(double&x){scanf("%lf",&x);}
void rd(long double&x){scanf("%Lf",&x);}
void rd(string&x){cin>>x;}
void rd(char*x){scanf("%s",x);}
template<typename T1,typename T2>void rd(pair<T1,T2>&x){rd(x.first);rd(x.second);}
template<typename T>void rd(vector<T>&x){for(T&p:x)rd(p);}
template<typename C,typename...T>void rd(C&a,T&...args){rd(a);rd(args...);}
//istream& operator>>(istream& is,__int128& a){string s;is>>s;a=0;int i=0;bool neg=false;if(s[0]=='-')neg=true,i++;for(;i<s.size();i++)a=a*10+s[i]-'0';if(neg)a*=-1;return is;}
//ostream& operator<<(ostream& os,__int128 a){bool neg=false;if(a<0)neg=true,a*=-1;ll high=(a/(__int128)1e18);ll low=(a-(__int128)1e18*high);string res;if(neg)res+='-';if(high>0){res+=to_string(high);string temp=to_string(low);res+=string(18-temp.size(),'0');res+=temp;}else res+=to_string(low);os<<res;return os;}

const int N=1e5+5;
ll cnt[N][3];
void test(){
	int n;
	ll k;
	rd(n,k);
	vector<int> pos(n);
	for(int i=0;i<n;i++){
		int c,w,f;
		rd(c,w,f);
		pos[i]=f;
		cnt[f][w]+=c;
	}
	sort(all(pos));
	pos.erase(unique(all(pos)),pos.end());
	reverse(all(pos));
	ll ans=0;
	ll lastCap=0;
	int cntLeft1=0;
	for(auto p:pos){
		ll moguLast=min(cnt[p][2],lastCap/2);
		cnt[p][2]-=moguLast;
		lastCap-=2*moguLast;
		if(lastCap==1){
			lastCap=0;
			cntLeft1++;
		}
		ll needFull=(2*cnt[p][2])/k;
		ans+=needFull*p;
		cnt[p][2]-=needFull*(k/2);
		if(cnt[p][2]){
			ans+=p;
			lastCap=k-2*cnt[p][2];
		}

		ll take=min(cnt[p][1],lastCap-1);
		cnt[p][1]-=take;
		lastCap-=take;
		if(lastCap==1){
			lastCap=0;
			cntLeft1++;
		}
		needFull=(cnt[p][1])/k;
		ans+=needFull*p;
		cnt[p][1]-=needFull*k;
		if(cntLeft1>=cnt[p][1]){
			cntLeft1-=cnt[p][1];
			continue;
		}
		// nned to start a new one!
		ans+=p;
		lastCap=k-cnt[p][1];
	}
	printf("%lld\n",ans);
	
	for(auto p:pos)cnt[p][1]=cnt[p][2]=0;
}
int main()
{
	int t=ri();
	while(t--)test();	
	return 0;
}

详细

Test #1:

score: 100
Accepted
time: 1ms
memory: 3760kb

input:

2
4 6
1 1 8
7 2 5
1 1 7
3 2 6
8 1200000
100000 1 100000
100000 1 12345
100000 2 100000
100000 2 12345
100000 1 100000
100000 1 12345
100000 2 100000
100000 2 12345

output:

24
100000

result:

ok 2 lines

Test #2:

score: -100
Wrong Answer
time: 41ms
memory: 6200kb

input:

5501
8 104
5 2 3
6 2 4
5 2 3
6 2 9
8 2 4
2 1 3
7 2 4
8 2 8
1 290
3 1 1
12 12
6 1 2
1 2 2
1 1 2
1 2 4
6 1 1
1 2 5
6 1 4
4 1 4
6 2 4
6 2 5
4 2 5
4 1 4
5 334
1 1 4
1 2 3
4 2 1
5 1 1
2 1 2
13 218
5 2 3
5 1 4
1 2 1
1 2 5
3 2 2
1 1 3
4 2 2
1 2 5
2 2 1
2 1 5
3 2 1
5 2 1
1 1 4
10 260
7 2 1
5 1 1
5 2 4
6 1 6...

output:

9
1
23
4
5
7
1
3
9
6
1
10
4
9
17
6
4
1
8
5
5
7
1
3
23
6
3
3
2
2
2
3
8
1
5
6
9
11
150
7
10
2
7
7
8
6
5
5
1
7
3
5
10
7
7
10
8
1
4
2
3
9
1
5
2
9
1
6
7
7
6
10
18
8
10
4
10
9
2
8
3
5
9
3
6
5
3
2
6
1
3
2
2
1
6
9
6
3
4
8
9
9
2
6
1
2
6
7
5
2
5
21
8
1
2
3
4
9
3
4
6
5
9
6
1
7
3
7
3
2
2
8
7
3
5
9
7
10
7
3
2
4
...

result:

wrong answer 39th lines differ - expected: '147', found: '150'