QOJ.ac

QOJ

ID题目提交者结果用时内存语言文件大小提交时间测评时间
#268999#5146. SkillsTerkWA 75ms498276kbC++142.0kb2023-11-29 10:00:152023-11-29 10:00:16

Judging History

你现在查看的是最新测评结果

  • [2023-11-29 10:00:16]
  • 评测
  • 测评结果:WA
  • 用时:75ms
  • 内存:498276kb
  • [2023-11-29 10:00:15]
  • 提交

answer

#include<bits/stdc++.h>
using namespace std;
const int N=1e3+5,W=205;
namespace IO
{
    char Is[(1<<21)+10],Os[(1<<21)+10];
    int Ipt,Opt;
    char gc()
    {
        if(Ipt==1<<21)Ipt=0;
        if(!Ipt){Is[fread(Is,1,1<<21,stdin)]=0;}
        return Is[Ipt++];
    }
    void flush(){fwrite(Os,1,Opt,stdout);Opt=0;}
    void pc(char x)
    {
        if(Opt==1<<21)flush();
        Os[Opt++]=x;
    }
    int read()
    {
        int x=0;char ch=gc();while(ch<'0'||ch>'9')ch=gc();while(ch<='9'&&ch>='0')x=x*10+ch-'0',ch=gc();return x;
    }
}
using namespace IO;
int n;
int Rem[N][3],Gy[N][W][W][3];
void Max(int &a,int b){
	if(b>a) a=b;
}
int nxt(int x){//注意不要直接+1 因为0的话就不会加 所以开个函数算方便 
	return x==0?0:x+1;
}
int main(){
	int t;
	cin>>t;
	while(t--){
		cin>>n;
		for(int i=1;i<=n;i++) Rem[i][0]=read(),Rem[i][1]=read(),Rem[i][2]=read();
		memset(Gy,-0x3f,sizeof(Gy));
		Gy[0][0][0][0]=Gy[0][0][0][1]=Gy[0][0][0][2]=0;
		for(int i=0;i<n;i++){
			for(int j=0;j<205;j++){
				for(int k=0;k<205;k++){
					Max(Gy[i+1][nxt(j)][nxt(k)][0],Gy[i][j][k][0]+Rem[i+1][0]-nxt(j)-nxt(k));
					Max(Gy[i+1][1][nxt(k)][1],Gy[i][j][k][0]+Rem[i+1][1]-nxt(k)-1);
					Max(Gy[i+1][1][nxt(j)][2],Gy[i][j][k][0]+Rem[i+1][2]-nxt(j)-1);
									
					Max(Gy[i+1][1][nxt(k)][0],Gy[i][j][k][1]+Rem[i+1][0]-nxt(k)-1);
					Max(Gy[i+1][nxt(j)][nxt(k)][1],Gy[i][j][k][1]+Rem[i+1][1]-nxt(j)-nxt(k));
					Max(Gy[i+1][nxt(j)][1][2],Gy[i][j][k][1]+Rem[i+1][2]-nxt(j)-1);
					
					
					Max(Gy[i+1][nxt(k)][1][0],Gy[i][j][k][2]+Rem[i+1][0]-nxt(k)-1);
					Max(Gy[i+1][nxt(j)][1][1],Gy[i][j][k][2]+Rem[i+1][1]-nxt(j)-1);
					Max(Gy[i+1][nxt(j)][nxt(k)][2],Gy[i][j][k][2]+Rem[i+1][2]-nxt(j)-nxt(k));
					
				}
			}
		}
		int ans=0;//可以都不选 
		for(int j=0;j<205;j++){
			for(int k=0;k<205;k++){
				ans=max(ans,max(Gy[n][j][k][0],max(Gy[n][j][k][1],Gy[n][j][k][2])));
			}
		}
		cout<<ans<<'\n';
	}
	return 0;
}

详细

Test #1:

score: 0
Wrong Answer
time: 75ms
memory: 498276kb

input:

2
3
1 1 10
1 10 1
10 1 1
5
1 2 3
6 5 4
7 8 9
12 11 10
13 14 15

output:

26
15

result:

wrong answer 2nd numbers differ - expected: '41', found: '15'