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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#268738#4940. Token DistancebruhWA 488ms246864kbC++208.8kb2023-11-28 20:21:422023-11-28 20:21:43

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你现在查看的是最新测评结果

  • [2023-11-28 20:21:43]
  • 评测
  • 测评结果:WA
  • 用时:488ms
  • 内存:246864kb
  • [2023-11-28 20:21:42]
  • 提交

answer

#pragma GCC optimize("O3,unroll-loops")
#pragma GCC target("avx2,bmi,bmi2,lzcnt,popcnt")

#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/tree_policy.hpp>
using namespace std;
using namespace __gnu_pbds;

typedef long long ll;
typedef long double ld;
typedef __int128 Int;
typedef vector<ll> vi;
typedef pair<ll, ll> ii;
typedef vector<ii> vii;
typedef pair<ll, ii> iii;
typedef unordered_map<ll, ll> unmap;

template<typename T> using pqmax = priority_queue<T>;
template<typename T> using pqmin = priority_queue<T, vector<T>, greater<T>>;
template<typename T> using oset = tree<T, null_type,less<T>, rb_tree_tag, tree_order_statistics_node_update>;

#define fi first
#define se second
#define sz size()
#define pb push_back
#define lb lower_bound
#define ub upper_bound
#define lg(n) (ll)__lg(n)
#define btpc __builtin_popcount

#define all(a) (a).begin(), (a).end()
#define rall(a) (a).rbegin(), (a).rend()
#define FOR(i,a,b) for(ll i = a; i <= b; i ++)
#define REP(i,a,b) for(ll i = a; i < b; i ++)
#define FORD(i,a,b) for(ll i = a; i >= b; i --)
#define FORS(i,a,b,c) for(ll i = a; i <= b; i += c)
#define FORDS(i,a,b,c) for(ll i = a; i >= b; i -= c)
#define FORA(x,a) for(auto x: a)
#define FORAA(l,r,a) for(auto [l, r]: a)

#define EL cerr << endl;
#define DEBUGN(a) cerr << a << endl;
#define DEBUGA(a, n) FOR (i, 1, n) cerr << a[i] << " "; cerr << endl;
#define DEBUG_AOP(a, n) FOR (i, 1, n) cerr << a[i].fi << " " << a[i].se << endl;  
#define DEBUG_A2D(a, n, m) FOR (i, 1, n) {FOR (j, 1, m) cerr << a[i][j] << " "; cerr << endl;}
#define DEBUG cerr << "shut the fuck up please :3" << endl;

#define YES cout << "YES\n"; return;
#define NO cout << "NO\n"; return;
 
template<class X, class Y> bool mimi(X &x, const Y &y) {if(x>y){x=y;return 1;}return 0;}
template<class X, class Y> bool mama(X &x, const Y &y) {if(x<y){x=y;return 1;}return 0;}
istream &operator >> (istream &st, Int &a) {string s;a=0;st>>s;bool g=1;REP(i,0,s.sz){if(i==0&&s[i]=='-'){g = 0;continue;}a=a*10+s[i]-'0';}if(!g)a=-a;return st;}
ostream &operator << (ostream &st, const Int &a) {Int t=a;if(t==0){st<<0;return st;}if(t<0){st<<'-';t=-t;}string b;while(t!=0){b.pb((t%10+'0'));t/=10;}reverse(all(b));st<<b;return st;}

const ll nom = 2;
const ll base[] = {577, 677, 877, 977};
const ll mod[] = {(ll)1e9 + 2277, (ll)1e9 + 5277, (ll)1e9 + 8277, (ll)1e9 + 9277};
const ii dir[] = {{0, 1}, {1, 0}, {0, -1}, {-1, 0}, {1, 1}, {1, -1}, {-1, 1}, {-1, -1}};

const ll INF = 1e18;
const ll N = 1e5 + 5;
const ll T = 4*N - 3;
const ll M = 1e9 + 7;
const ll B = 20;
mt19937_64 rng(static_cast<ll>(std::chrono::duration_cast<std::chrono::nanoseconds>(std::chrono::high_resolution_clock::now().time_since_epoch()).count()));

ll rand(ll l, ll r) {
    return uniform_int_distribution<ll>(l, r)(rng);
}

struct STN {ll minVal, maxVal;};
struct SegmentTree {
    vector<STN> node;
    const STN DEADNODE = {INF, -INF};
    ll uu, vv;
    SegmentTree(ll n, ll uu, ll vv): node(4 * n + 10), uu(uu), vv(vv) {
        fill(all(node), DEADNODE);
    };
    
    STN merge(STN a, STN b) {return {min(a.minVal, b.minVal), max(a.maxVal, b.maxVal)};}

    void update(ll pos, ll val) {update(pos, val, 1, uu, vv);}
    void update(ll pos, ll val, ll id, ll l, ll r) {
        if (l > pos || r < pos) return;
        if (l == r) {
            node[id].minVal = val;
            node[id].maxVal = val;
            return;
        }
        ll mid = (l + r) >> 1;
        update(pos, val, id << 1, l, mid);
        update(pos, val, id << 1 | 1, mid + 1, r);
        node[id] = merge(node[id << 1], node[id << 1 | 1]);
    }

    STN get(ll u, ll v) {return get(u, v, 1, uu, vv);}
    STN get(ll u, ll v, ll id, ll l, ll r) {
        if (l > v || r < u) return DEADNODE;
        if (u <= l && r <= v) return node[id];
        ll mid = (l + r) >> 1;
        return merge(get(u, v, id << 1, l, mid), get(u, v, id << 1 | 1, mid + 1, r));
    }
};

struct STNS {ll val, cnt;};
struct SegmentTreeSum {
    vector<STNS> node;
    const STNS DEADNODE = {(ll)0, 0};
    ll uu, vv;
    
    void init(ll n, ll uu, ll vv) {
        node.resize(4 * n + 10);
        this->uu = uu;
        this->vv = vv;
        fill(all(node), DEADNODE);
    }
    STNS merge(STNS a, STNS b) {return {a.val + b.val, a.cnt + b.cnt};}

    void update(ll pos, ll val, ll cnt) {update(pos, val, cnt, 1, uu, vv);}
    void update(ll pos, ll val, ll cnt, ll id, ll l, ll r) {
        if (l > pos || r < pos) return;
        if (l == r) {
            node[id].val = val;
            node[id].cnt = cnt;
            return;
        }
        ll mid = (l + r) >> 1;
        update(pos, val, cnt, id << 1, l, mid);
        update(pos, val, cnt, id << 1 | 1, mid + 1, r);
        node[id] = merge(node[id << 1], node[id << 1 | 1]);
    }

    STNS get(ll u, ll v) {return get(u, v, 1, uu, vv);}
    STNS get(ll u, ll v, ll id, ll l, ll r) {
        if (l > v || r < u) return DEADNODE;
        if (u <= l && r <= v) return node[id];
        ll mid = (l + r) >> 1;
        return merge(get(u, v, id << 1, l, mid), get(u, v, id << 1 | 1, mid + 1, r));
    }
};

struct MSTN {oset<ii> a;};
struct MergeSortTree {
    vector<MSTN> node;
    const MSTN DEADNODE = {oset<ii>()};
    ll uu, vv;
    void init(ll n, ll uu, ll vv) {
        node.resize(n * 4, DEADNODE);
        this->uu = uu;
        this->vv = vv;
    }
    void build(ll n, ll *a) {build(n, a, 1, uu, vv);}
    void build(ll n, ll *a, ll id, ll l, ll r) {
        if (l == r) {
            node[id].a.insert({a[r], r});
            return;
        }
        ll mid = (l + r) >> 1;
        build(n, a, id << 1, l, mid);
        build(n, a, id << 1 | 1, mid + 1, r);

        FORA (x, node[id << 1].a) node[id].a.insert(x);
        FORA (x, node[id << 1 | 1].a) node[id].a.insert(x);
    }

    void update(ll pos, ii oldValue, ii newValue) {update(pos, oldValue, newValue, 1, uu, vv);}
    void update(ll pos, ii oldValue, ii newValue, ll id, ll l, ll r) {
        if (pos < l || pos > r) return;
        if (l == r) {
            node[id].a.erase(oldValue);
            node[id].a.insert(newValue);
            return;
        }
        ll mid = (l + r) >> 1;
        update(pos, oldValue, newValue, id >> 1, l, mid);
        update(pos, oldValue, newValue, id >> 1 | 1, mid + 1, r);
        node[id].a.erase(oldValue);
        node[id].a.insert(newValue);
    } 

    ll get(ll u, ll v, ll x) {return get(u, v, x, 1ll, uu, vv);}
    ll get(ll u, ll v, ll x, ll id, ll l, ll r) {
        if (r < u || l > v) return 0;
        if (v >= r && l >= u) return node[id].a.order_of_key({x + 1, 0});
        
        ll mid = (l + r) >> 1;
        return get(u, v, x, id << 1, l, mid) + get(u, v, x, id << 1 | 1, mid + 1, r);
    }
};

ll n, q;
ll a[N];
ll b[B + 1][N];
SegmentTree st(N, 0, N - 1);
SegmentTreeSum rt[B + 1];
MergeSortTree mst;

void solve(ll testID) {
    cin >> n >> q;
    FOR (i, 1, n) {
        cin >> a[i];
        st.update(i, a[i]);
    }
    mst.init(n, 1, n);
    mst.build(n, a);

    // mst.update(5, {1, 5}, {4, 5});
    // mst.update(3, {1, 3}, {7, 3});
    // EL EL
    // FORAA (l, r, mst.node[1].a) cout << l << " " << r << endl;
    // EL EL

    FOR (i, 1, B) {
        rt[i].init(n, 1, n);
        FOR (j, 1, n) {
            b[i][j] = a[j] * rand(0, 1); 
            rt[i].update(j, b[i][j], (b[i][j] != 0));
        }
    }

    FOR (_, 1, q) {
        ll type, l, r;
        cin >> type >> l >> r;
        if (type == 1) {
            st.update(l, r);
            FOR (i, 1, B) {
                if (rt[i].get(l, l).cnt == 0) continue;
                rt[i].update(l, r, 1);
            }
            mst.update(l, {a[l], l}, {r, l});
            a[l] = r;
        }
        if (type == 2) {
            ll maxVal = st.get(l, r).maxVal;
            ll minVal = st.get(l, r).minVal; 
            if (maxVal == minVal) {cout << "YES\n"; continue;}
            ll mod = (maxVal - minVal) / (r - l);
            if ((maxVal - minVal) % (r - l) != 0) {cout << "NO\n"; continue;}
            bool res = true;
            FOR (i, 1, B) {
                ll sum = rt[i].get(l, r).val;
                ll cnt = rt[i].get(l, r).cnt;
                ll pos = rand(l, r);
                // cout << l << " " << r << " " << pos << " " << minVal + (pos - l) * mod << " " << mst.get(l, r, minVal + (pos - l) * mod) << endl;
                if ((sum % mod != cnt * a[pos] % mod) || (mst.get(l, r, minVal + (pos - l) * mod) < pos - l + 1)) {
                    res = false;
                    break;
                } 
            }
            if (res) cout << "YES\n";
            else cout << "NO\n";
        }
    }
}

signed main() {
    ios_base::sync_with_stdio(0); cin.tie(0); 
    int test = 1;
    // cin >> test;
    FOR (i, 1, test) solve(i);
}

詳細信息

Test #1:

score: 100
Accepted
time: 0ms
memory: 23924kb

input:

5 7
1 1 1 10 1
2 1 3
2 1 5
1 5 4
1 3 7
2 2 4
2 2 5
2 4 5

output:

YES
NO
NO
YES
YES

result:

ok 5 lines

Test #2:

score: 0
Accepted
time: 2ms
memory: 23888kb

input:

2 1
0 1000000000
2 1 2

output:

YES

result:

ok single line: 'YES'

Test #3:

score: -100
Wrong Answer
time: 488ms
memory: 246864kb

input:

81473 13549
972586683 972586964 972587245 972587526 972587807 972588088 972588369 972588650 972588931 972589212 972589493 972589774 972590055 972590336 972590617 972590898 972591179 972591460 972591741 972592022 972592303 972592584 972592865 972593146 972593427 972593708 972593989 972594270 97259455...

output:

YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
YES
...

result:

wrong answer 5th lines differ - expected: 'NO', found: 'YES'