QOJ.ac
QOJ
ID | Problem | Submitter | Result | Time | Memory | Language | File size | Submit time | Judge time |
---|---|---|---|---|---|---|---|---|---|
#268567 | #7845. Fast Forward | Yarema# | WA | 0ms | 3816kb | C++14 | 1.3kb | 2023-11-28 18:32:06 | 2023-11-28 18:32:07 |
Judging History
answer
#include <bits/stdc++.h>
using namespace std;
#define FOR(i, a, b) for(int i = (a); i < (b); i++)
#define RFOR(i, a, b) for(int i = (a) - 1; i >= (b); i--)
#define SZ(a) int(a.size())
#define ALL(a) a.begin(), a.end()
#define PB push_back
#define MP make_pair
#define F first
#define S second
typedef long long LL;
typedef vector<int> VI;
typedef pair<int, int> PII;
typedef double db;
const int N = 1'000'447;
const int LOG = 20;
int up[N][LOG];
int main()
{
ios::sync_with_stdio(0);
cin.tie(0);
cout << fixed << setprecision(15);
int n, k;
cin >> n >> k;
vector<LL> a(n);
vector<LL> pref(2 * n + 1);
FOR (i, 0, n)
{
cin >> a[i];
pref[i + 1] = a[i];
pref[n + i + 1] = a[i];
}
FOR (i, 0, 2 * n)
pref[i + 1] += pref[i];
FOR (i, 0, 2 * n + 1)
{
int to = upper_bound(ALL(pref), pref[i] + k) - pref.begin();
up[i][0] = to;
}
up[2 * n + 1][0] = 2 * n + 1;
FOR (i, 1, LOG)
{
FOR (j, 0, 2 * n + 2)
{
up[j][i] = up[up[j][i - 1]][i - 1];
}
}
FOR (i, 0, n)
{
int ans = 0;
int idx = i;
RFOR (j, LOG, 0)
{
if (up[idx][j] < i + n)
{
idx = up[idx][j];
ans += 1 << j;
}
}
if (i)
cout << ' ';
cout << ans;
}
cout << '\n';
return 0;
}
Details
Tip: Click on the bar to expand more detailed information
Test #1:
score: 100
Accepted
time: 0ms
memory: 3816kb
input:
7 7 1 1 1 1 1 1 1
output:
0 0 0 0 0 0 0
result:
ok single line: '0 0 0 0 0 0 0'
Test #2:
score: 0
Accepted
time: 0ms
memory: 3612kb
input:
3 3 1 1 3
output:
0 1 1
result:
ok single line: '0 1 1'
Test #3:
score: -100
Wrong Answer
time: 0ms
memory: 3612kb
input:
10 5 4 1 5 5 1 3 2 1 5 2
output:
3 4 4 3 4 3 4 4 3 4
result:
wrong answer 1st lines differ - expected: '5 4 5 4 4 5 4 4 5 4', found: '3 4 4 3 4 3 4 4 3 4'