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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#267731#6304. RectanglezhaohaikunWA 18ms46452kbC++148.4kb2023-11-27 17:29:262023-11-27 17:29:26

Judging History

你现在查看的是最新测评结果

  • [2023-11-27 17:29:26]
  • 评测
  • 测评结果:WA
  • 用时:18ms
  • 内存:46452kb
  • [2023-11-27 17:29:26]
  • 提交

answer

// MagicDark
#include <bits/stdc++.h>
#define mid ((l + r) >> 1)
#define ls num << 1
#define rs ls | 1
#define li ls, l, mid
#define ri rs, mid + 1, r
#define x1 cryforthezi1
#define x2 cryforthezi2
#define y1 cryforthezi3
#define y2 cryforthezi4
#define debug cerr << "[" << __LINE__ << "] "
#define SZ(x) (int) x.size() - 1
#define all(x) x.begin(), x.end()
#define ms(x, y) memset(x, y, sizeof x)
#define F(i, x, y) for (int i = (x); i <= (y); i++)
#define DF(i, x, y) for (int i = (x); i >= (y); i--)
using namespace std;
typedef long long ll;
typedef unsigned long long ull;
template <typename T> inline void chkmax(T &x, T y) {x = max(x, y);}
template <typename T> inline void chkmin(T &x, T y) {x = min(x, y);}
template <typename T> inline void read(T &x) {
	x = 0; int f = 1; char c = getchar();
	for (; !isdigit(c); c = getchar()) if (c == '-') f = -f;
	for (; isdigit(c); c = getchar()) x = (x << 1) + (x << 3) + (c ^ 48);
	x *= f;
}
const int N = 2e5 + 10, MOD = 998244353, T = 1e9, inv6 = 166374059;
int n, x1[N], y1[N], x2[N], y2[N], yy[N], ans, lp[N], rp[N];
int cx, cy, tx[N], ty[N];
int len[N << 2], mx[N << 2], tag[N << 2], seg[N << 2], lmax[N], rmin[N];
inline void add(int &x, ll y) {x = (x + y) % MOD;}
void build(int num, int l, int r) {
	seg[num] = mx[num] = tag[num] = 0, len[num] = ty[r + 1] - ty[l];
	if (l == r) return;
	build(li), build(ri);
}
vector <tuple <int, int, int, int>> g1;
vector <tuple <int, int>> g2;
vector <tuple <int, int, int>> g3;
void down(int num, int x) {
	g1.emplace_back(num, mx[num], tag[num], seg[num]);
	mx[num] = tag[num] = x;
	seg[num] = (ll) len[num] * x % MOD;
}
void pushdown(int num) {
	if (tag[num]) {
		g2.emplace_back(num, tag[num]);
		down(ls, tag[num]), down(rs, tag[num]);
		tag[num] = 0;
	}
}
void pushup(int num) {
	g3.emplace_back(num, mx[num], seg[num]);
	mx[num] = mx[rs];
	seg[num] = (seg[ls] + seg[rs]) % MOD;
}
void change(int num, int l, int r, int L, int R, int x) {
	if (L <= l && r <= R) return down(num, x);
	pushdown(num);
	if (mid >= L) change(li, L, R, x);
	if (mid < R) change(ri, L, R, x);
	pushup(num);
}
int query(int num, int l, int r, int L, int R) {
	if (L <= l && r <= R) return seg[num];
	pushdown(num);
	if (mid >= R) return query(li, L, R);
	if (mid < L) return query(ri, L, R);
	return (query(li, L, R) + query(ri, L, R)) % MOD;
}
int findpos(int num, int l, int r, int x) {
	if (l == r) return l;
	pushdown(num);
	if (mx[ls] > x) return findpos(li, x);
	return findpos(ri, x);
}
vector <int> gg[N << 2];
void modify(int num, int l, int r, int L, int R, int x) {
	if (L <= l && r <= R) return gg[num].push_back(x);
	if (mid >= L) modify(li, L, R, x);
	if (mid < R) modify(ri, L, R, x);
}
void analysis(int num, int l, int r) {
	unsigned t1 = g1.size(), t2 = g2.size(), t3 = g3.size();
	for (int id: gg[num]) {
		int g = mx[1] <= y1[id] ? cy : findpos(1, 1, cy, y1[id]) - 1;
		// debug << mx[1] << endl;
		// debug << "~ " << id << " " << yy[id] << " " << g << " " << y1[id] << endl;
		if (yy[id] <= g) change(1, 1, cy, yy[id], g, y1[id]);
	}
	if (l == r) {
		if (lmax[l] > rmin[l]) {
			int L = lower_bound(ty + 1, ty + cy + 1, lmax[l]) - ty;
			if (L <= cy) {
				int R = mx[1] <= rmin[l] ? cy : findpos(1, 1, cy, rmin[l]) - 1;
				if (L <= R) {
					// debug << L << " " << R << endl;
					add(ans, ((ll) (ty[R + 1] - ty[L]) * (rmin[l] + 1) % MOD - query(1, 1, cy, L, R) + MOD) * (tx[l + 1] - tx[l]));
					// debug << l << " " << ((ll) (ty[R + 1] - ty[L]) * (rmin[l] + 1) % MOD - query(1, 1, cy, L, R) + MOD) * (tx[l + 1] - tx[l]) % MOD << endl;
					// debug << query(1, 1, cy, L, R) << endl;
					// debug << l << " " << L << " " << R << "  " << ans << " " << lmax[l] << " " << rmin[l] << endl;
					// debug << query(1, 1, cy, 4, 4) << endl;
				}
			}
		}
	} else analysis(li), analysis(ri);
	while (g1.size() > t1) {
		int id = get <0> (g1.back());
		mx[id] = get <1> (g1.back());
		tag[id] = get <2> (g1.back());
		seg[id] = get <3> (g1.back());
		g1.pop_back();
	}
	while (g2.size() > t2) {
		int id = get <0> (g2.back());
		tag[id] = get <1> (g2.back());
		g2.pop_back();
	}
	while (g3.size() > t3) {
		int id = get <0> (g3.back());
		mx[id] = get <1> (g3.back());
		seg[id] = get <2> (g3.back());
		g3.pop_back();
	}
}
struct P1 {// 大根堆
	priority_queue <int> q1, q2;
	void insert(int x) {
		q1.push(x);
	}
	void erase(int x) {
		q2.push(x);
	}
	unsigned size() {
		return q1.size() - q2.size();
	}
	bool empty() {
		return q1.size() == q2.size();
	}
	int top() {
		while (q2.size() && q2.top() == q1.top()) q1.pop(), q2.pop();
		return q1.top();
	}
	void pop() {
		while (q2.size() && q2.top() == q1.top()) q1.pop(), q2.pop();
		q1.pop();
	}
};
struct P2 {// 小根堆
	priority_queue <int, vector <int>, greater <int>> q1, q2;
	void insert(int x) {
		q1.push(x);
	}
	void erase(int x) {
		q2.push(x);
	}
	unsigned size() {
		return q1.size() - q2.size();
	}
	bool empty() {
		return q1.size() == q2.size();
	}
	int top() {
		while (q2.size() && q2.top() == q1.top()) q1.pop(), q2.pop();
		return q1.top();
	}
	void pop() {
		while (q2.size() && q2.top() == q1.top()) q1.pop(), q2.pop();
		q1.pop();
	}
};
vector <int> ins[N], del[N];//, preins[N], sufins[N];
int t1[N];
bool t2[N];
void solve() {
	F(i, 1, 2 * n + 5) {
		ins[i].clear();
		del[i].clear();
	}
	F(i, 1, 8 * n + 10) {
		gg[i].clear();
	}
	cx = 0, cy = 0;
	tx[++cx] = 1;
	ty[++cy] = 1;
	F(i, 1, n) {
		tx[++cx] = x1[i];
		if (x2[i] != T) tx[++cx] = x2[i] + 1;
		ty[++cy] = y1[i];
		if (y2[i] != T) ty[++cy] = y2[i] + 1;
	}
	sort(tx + 1, tx + cx + 1);
	F(i, 1, cx) lp[i] = 0, rp[i] = T + 1;
	sort(ty + 1, ty + cy + 1);
	tx[(cx = unique(tx + 1, tx + cx + 1) - tx)--] = T + 1;
	ty[(cy = unique(ty + 1, ty + cy + 1) - ty)--] = T + 1;
	build(1, 1, cy);
	F(i, 1, n) {
		int x1 = lower_bound(tx + 1, tx + cx + 1, ::x1[i]) - tx;
		int x2 = lower_bound(tx + 1, tx + cx + 1, ::x2[i] + 1) - tx;
		chkmax(lp[x2], ::x1[i]);
		chkmin(rp[x1 - 1], ::x2[i]);
		yy[i] = lower_bound(ty + 1, ty + cy + 1, y2[i] + 1) - ty;
		if (x1 > 1) modify(1, 1, cx, 1, x1 - 1, i), ins[1].push_back(i), del[x1].push_back(i);
		if (x2 <= cx) modify(1, 1, cx, x2, cx, i), ins[x2].push_back(i);
	}
	P1 l;
	P2 r;
	int L = 1, R = T;
	F(i, 1, cx) {
		for (int j: ins[i]) {
			l.insert(y1[j]);
			r.insert(y2[j]);
		}
		for (int j: del[i]) {
			l.erase(y1[j]);
			r.erase(y2[j]);
		}
		if (l.empty()) lmax[i] = 0, add(ans, (ll) T * (T - 1) / 2 % MOD * (tx[i + 1] - tx[i]));//, debug << i << " " << (ll) T * (T - 1) / 2 % MOD * (tx[i + 1] - tx[i]) % MOD;
		else {
			lmax[i] = l.top(), rmin[i] = r.top();
			if (lmax[i] <= rmin[i]) {
				add(ans, ((ll) T * (T - 1) / 2 - (ll) (T - (rmin[i] - lmax[i] + 1)) * (T - (rmin[i] - lmax[i] + 1) - 1) / 2) % MOD * (tx[i + 1] - tx[i]));//, debug << i << " " << ((ll) T * (T - 1) / 2 - (ll) (T - (rmin[i] - lmax[i] + 1)) * (T - (rmin[i] - lmax[i] + 1) - 1) / 2) % MOD * (tx[i + 1] - tx[i]) % MOD << " " << lmax[i] << " " << rmin[i] << " " << tx[i + 1] - tx[i] << endl;
				swap(lmax[i], rmin[i]);
				lmax[i]++;
				rmin[i]--;
			}
		}
		if (lp[i]) {
			chkmax(L, lp[i]);
			chkmin(R, tx[i] - 1);
		}
		t1[i] = max(0, min(tx[i] - 1, R) - L + 1);
		t2[i] = R >= tx[i];
		// debug << i << " " << L << " " << R << endl;
	}
	L = 1, R = T;
	DF(i, cx, 1) {
		if (rp[i] <= T) {
			chkmax(L, tx[i + 1]);
			chkmin(R, rp[i]);
		}
		int k1 = max(0, R - max(tx[i + 1], L) + 1);
		bool k2 = L <= tx[i];
		add(ans, (ll) (tx[i + 1] - tx[i]) * t1[i] % MOD * k1);
		// debug << i << " " << t2[i] << " " << k2 << endl;
		if (t2[i]) add(ans, (ll) (tx[i + 1] - tx[i]) * (tx[i + 1] - tx[i] - 1) / 2 % MOD * k1);
		if (k2) add(ans, (ll) (tx[i + 1] - tx[i]) * (tx[i + 1] - tx[i] - 1) / 2 % MOD * t1[i]);
		if (t2[i] && k2) add(ans, (ll) (tx[i + 1] - tx[i]) * (tx[i + 1] - tx[i] - 1) % MOD * (tx[i + 1] - tx[i] - 2) % MOD * inv6);
		// debug << i << " " << ans << endl;
	}
	// debug << ans << endl;
	// exit(0);
	analysis(1, 1, cx);
	// debug << ans << endl;
	// debug << cx << " " << ans << endl;
	// exit(0);
}
void zhk() {
	ans = 0;
	read(n);
	F(i, 1, n) read(x1[i]), read(y1[i]), read(x2[i]), read(y2[i]);
	solve();
	// debug << ans << endl;
	F(i, 1, n) swap(x1[i], y1[i]), swap(x2[i], y2[i]);
	solve();
	cout << ans << '\n';
}
signed main() {
	// debug << (T - 1) % MOD << endl;
	int _ = 1;
	cin >> _;
	while (_--) zhk();
	return 0;
}
/* why?
*/

详细

Test #1:

score: 100
Accepted
time: 0ms
memory: 46392kb

input:

3
1
1 1 1000000000 1000000000
3
1 1 2 2
3 3 4 4
5 5 6 6
5
581574116 47617804 999010750 826131769
223840663 366320907 613364068 926991396
267630832 51913575 488301124 223957497
217461197 492085159 999485867 913732845
28144453 603781668 912516656 993160442

output:

230616300
64
977066618

result:

ok 3 number(s): "230616300 64 977066618"

Test #2:

score: -100
Wrong Answer
time: 18ms
memory: 46452kb

input:

1000
10
5 7 6 10
4 3 6 9
1 6 3 7
1 1 7 10
1 2 7 7
5 2 8 3
2 1 5 7
1 1 10 6
1 7 2 8
4 7 5 9
10
6 6 8 10
4 4 9 9
2 4 6 5
5 3 10 10
1 3 4 4
2 2 3 6
7 5 8 6
2 7 8 8
5 7 10 10
2 4 7 8
10
3 6 6 10
1 2 7 4
7 5 10 9
4 5 8 9
2 7 5 9
2 2 9 7
3 3 8 4
1 1 8 6
5 4 10 6
3 9 7 10
10
3 1 8 9
1 3 8 10
4 1 7 4
2 4 5 ...

output:

28090346
21067813
91293527
63203269
14045217
24579047
49158123
56180656
10533939
83
28090370
101827336
512901422
38624242
10533926
42135595
7022611
7022661
7022622
31601639
21067817
35112979
7022628
7022679
17556483
42135554
59692019
28090452
14045202
73737096
42135505
31601703
49158090
28090434
108...

result:

wrong answer 2nd numbers differ - expected: '21067815', found: '21067813'