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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#265499 | #7743. Grand Finale | ucup-team1191# | WA | 77ms | 18748kb | C++20 | 6.5kb | 2023-11-25 18:48:36 | 2023-11-25 18:48:37 |
Judging History
answer
/*
author: Maksim1744
created: 25.11.2023 13:13:05
*/
#include "bits/stdc++.h"
using namespace std;
using ll = long long;
using ld = long double;
#define mp make_pair
#define pb push_back
#define eb emplace_back
#define sum(a) ( accumulate ((a).begin(), (a).end(), 0ll))
#define mine(a) (*min_element((a).begin(), (a).end()))
#define maxe(a) (*max_element((a).begin(), (a).end()))
#define mini(a) ( min_element((a).begin(), (a).end()) - (a).begin())
#define maxi(a) ( max_element((a).begin(), (a).end()) - (a).begin())
#define lowb(a, x) ( lower_bound((a).begin(), (a).end(), (x)) - (a).begin())
#define uppb(a, x) ( upper_bound((a).begin(), (a).end(), (x)) - (a).begin())
template<typename T> vector<T>& operator-- (vector<T> &v){for (auto& i : v) --i; return v;}
template<typename T> vector<T>& operator++ (vector<T> &v){for (auto& i : v) ++i; return v;}
template<typename T> istream& operator>>(istream& is, vector<T> &v){for (auto& i : v) is >> i; return is;}
template<typename T> ostream& operator<<(ostream& os, vector<T> v){for (auto& i : v) os << i << ' '; return os;}
template<typename T, typename U> pair<T,U>& operator-- (pair<T, U> &p){--p.first; --p.second; return p;}
template<typename T, typename U> pair<T,U>& operator++ (pair<T, U> &p){++p.first; ++p.second; return p;}
template<typename T, typename U> istream& operator>>(istream& is, pair<T, U> &p){is >> p.first >> p.second; return is;}
template<typename T, typename U> ostream& operator<<(ostream& os, pair<T, U> p){os << p.first << ' ' << p.second; return os;}
template<typename T, typename U> pair<T,U> operator-(pair<T,U> a, pair<T,U> b){return mp(a.first-b.first, a.second-b.second);}
template<typename T, typename U> pair<T,U> operator+(pair<T,U> a, pair<T,U> b){return mp(a.first+b.first, a.second+b.second);}
template<typename T, typename U> void umin(T& a, U b){if (a > b) a = b;}
template<typename T, typename U> void umax(T& a, U b){if (a < b) a = b;}
#ifdef HOME
#define SHOW_COLORS
#include "/mnt/c/Libs/tools/print.cpp"
#else
#define show(...) void(0)
#define debugf(fun) fun
#define debugv(var) var
#define mclock void(0)
#define shows void(0)
#define debug if (false)
#define OSTREAM(...) ;
#define OSTREAM0(...) ;
#endif
const int N = 2510;
array<array<int, N / 2>, N> dp_full;
array<array<bool, N / 2>, N> dp_can;
const int inf = 1e9;
void test_case(int test) {
int m, n;
cin >> m >> n;
string cur, s;
cin >> cur >> s;
// dp_full
int maxc2 = (n + 1) / 2;
{
for (int i = 0; i <= n; ++i)
for (int j = 0; j <= maxc2; ++j)
dp_full[i][j] = inf;
dp_full[0].fill(0);
dp_full[1].fill(0);
dp_full[1][0] = 1;
for (int i = 0; i < n; ++i) {
for (int c2 = 0; c2 <= maxc2; ++c2) {
int c1 = dp_full[i][c2];
if (c1 >= inf / 2) continue;
// if last used 1
{
bool last1 = (s[n - i - 1] == 'Q');
bool last2 = (s[n - i - 1] == 'B');
// show(i+1, max(0,c2-last2), max(1, c1 + 1 - last1));
dp_full[i + 1][max(0, c2 - last2)] = min(max(1, c1 + 1 - last1), dp_full[i + 1][max(0, c2 - last2)]);
}
// if last used 2
if (i + 2 <= n) {
// second to last will be skipped
// bool plast1 = (s[n - i - 1] == 'Q');
// bool plast2 = (s[n - i - 1] == 'B');
bool plast1 = (s[n - i - 2] == 'Q');
bool plast2 = (s[n - i - 2] == 'B');
// show(i, c2, c1, plast1, plast2);
// show(i+2, max(1,c2-plast2), max(0, c1 - plast1));
dp_full[i + 2][max(1, c2 + 1 - plast2)] = min(max(0, c1 - plast1), dp_full[i + 2][max(1, c2 + 1 - plast2)]);
}
}
for (int c2 = 1; c2 <= maxc2; ++c2)
dp_full[i + 1][c2] = min(dp_full[i + 1][c2], dp_full[i + 1][c2 - 1]);
}
}
// dp_can
{
for (int i = 0; i <= n; ++i)
for (int j = 0; j <= maxc2; ++j)
dp_can[i][j] = false;
dp_can[0][0] = true;
int have1 = count(cur.begin(), cur.end(), 'Q');
int have2 = count(cur.begin(), cur.end(), 'B');
for (int i = 0; i < n; ++i) {
for (int c2 = 0; c2 <= maxc2; ++c2) {
if (!dp_can[i][c2]) continue;
assert(c2 * 2 <= i);
int left1 = have1 - (i - c2 * 2);
assert(left1 >= 0);
int left2 = have2 - c2;
assert(left2 >= 0);
if (left1)
dp_can[i + 1][c2] = true;
if (left2)
dp_can[min(n, i + 2)][c2 + 1] = true;
}
have1 += (s[i] == 'Q');
have2 += (s[i] == 'B');
}
}
debug {
cerr << "dp_full:" << endl;
for (int i = 0; i <= n; ++i)
for (int j = 0; j <= maxc2; ++j)
cerr << dp_full[i][j] << " \n"[j == maxc2];
cerr << "dp_can:" << endl;
for (int i = 0; i <= n; ++i)
for (int j = 0; j <= maxc2; ++j)
cerr << dp_can[i][j] << " \n"[j == maxc2];
}
// calc ans
int ans = inf;
{
int have1 = count(cur.begin(), cur.end(), 'Q');
int have2 = count(cur.begin(), cur.end(), 'B');
for (int i = 0; i <= n; ++i) {
for (int used_c2 = 0; used_c2 <= maxc2; ++used_c2) {
if (!dp_can[i][used_c2]) continue;
int need_size = cur.size() + used_c2;
int left1 = have1;
int left2 = have2 - used_c2;
if (left1 >= dp_full[n - i][min(maxc2, left2)]) {
ans = min(ans, need_size);
}
}
if (i != n) {
have1 += (s[i] == 'Q');
have2 += (s[i] == 'B');
}
}
}
if (ans == inf)
cout << "IMPOSSIBLE\n";
else
cout << ans << '\n';
}
int main() {
ios_base::sync_with_stdio(false); cin.tie(NULL);
int T;
cin >> T;
for (int test = 1; test <= T; ++test) {
test_case(test);
}
return 0;
}
詳細信息
Test #1:
score: 100
Accepted
time: 0ms
memory: 5428kb
input:
2 2 6 BG BQWBWW 4 6 GQBW WWWWQB
output:
3 IMPOSSIBLE
result:
ok 2 lines
Test #2:
score: 0
Accepted
time: 1ms
memory: 5500kb
input:
2 3 8 QBG BBBWBWWW 3 8 QBG BBBWBWWW
output:
3 3
result:
ok 2 lines
Test #3:
score: -100
Wrong Answer
time: 77ms
memory: 18748kb
input:
13 184 887 WBQBBWWBQBQBQBWWBBQQWWQQQBBBQWWWQWBBBBWWWQQBQQQWQBBQQWQQBBWWQWQQBWBQWWWWQWQQWQBWWQQWWQQBWWQWBBBWWQWBQBQWQQWWBQBQQBWQBQBWWBWQWQWBWBQWWQBQQQBWQQWQWWBQBWWQQBQWBQQBQQBQBBQBWBQQWWQBWBBQQBQG QWBQBQBWBQQWWWWQBBBQQQBBBWWWWQWQWWQQQBQBWQQQBWQWQBWWBQQQWQWBQBBQBWBBWBQWQBWWQQBWQQWWQWWQQWBQQWQWBBQBWBQQ...
output:
184 114 164 161 118 193 121 204 134 115 33 160 169
result:
wrong answer 2nd lines differ - expected: '372', found: '114'