QOJ.ac

QOJ

ID题目提交者结果用时内存语言文件大小提交时间测评时间
#263758#5419. TrianglesKhNURE_KIVIWA 0ms3780kbC++236.5kb2023-11-25 06:34:492023-11-25 06:34:49

Judging History

你现在查看的是最新测评结果

  • [2023-11-25 06:34:49]
  • 评测
  • 测评结果:WA
  • 用时:0ms
  • 内存:3780kb
  • [2023-11-25 06:34:49]
  • 提交

answer

//#pragma GCC optimize("Ofast", "unroll-loops")
//#pragma GCC target("sse", "sse2", "sse3", "ssse3", "sse4")

#ifdef __APPLE__

#include <iostream>
#include <cmath>
#include <algorithm>
#include <stdio.h>
#include <cstdint>
#include <cstring>
#include <string>
#include <cstdlib>
#include <vector>
#include <bitset>
#include <map>
#include <queue>
#include <ctime>
#include <stack>
#include <set>
#include <list>
#include <random>
#include <deque>
#include <functional>
#include <iomanip>
#include <sstream>
#include <fstream>
#include <complex>
#include <numeric>
#include <cassert>
#include <array>
#include <tuple>
#include <unordered_map>
#include <unordered_set>
#include <thread>

#else
#include <bits/stdc++.h>
#endif

#define all(a) a.begin(),a.end()
#define len(a) (int)(a.size())
#define mp make_pair
#define pb push_back
#define fir first
#define sec second
#define fi first
#define se second

using namespace std;

typedef pair<int, int> pii;
typedef long long ll;
typedef long double ld;

template<typename T>
bool umin(T &a, T b) {
    if (b < a) {
        a = b;
        return true;
    }
    return false;
}

template<typename T>
bool umax(T &a, T b) {
    if (a < b) {
        a = b;
        return true;
    }
    return false;
}

#if __APPLE__
#define D for (bool _FLAG = true; _FLAG; _FLAG = false)
#define LOG(...) print(#__VA_ARGS__" ::", __VA_ARGS__) << endl

template<class ...Ts>
auto &print(Ts ...ts) { return ((cerr << ts << " "), ...); }

#else
#define D while (false)
#define LOG(...)
#endif

const int max_n = -1, inf = 1000111222;

//mt19937 rng(chrono::steady_clock::now().time_since_epoch().count());

vector<array<int, 6> > a[11];

void solve() {
    int n;
    cin >> n;
    if(n == 24) {
        cout << "Yes\n"
                "0 0 500000000 0 400000000 300000000\n"
                "1000000000 0 500000000 0 600000000 300000000\n"
                "0 0 0 500000000 300000000 400000000\n"
                "0 1000000000 0 500000000 300000000 600000000\n"
                "0 1000000000 500000000 1000000000 400000000 700000000\n"
                "1000000000 1000000000 500000000 1000000000 600000000 700000000\n"
                "1000000000 1000000000 1000000000 500000000 700000000 600000000\n"
                "1000000000 0 1000000000 500000000 700000000 400000000\n"
                "0 0 400000000 300000000 300000000 400000000\n"
                "0 500000000 300000000 400000000 300000000 600000000\n"
                "0 1000000000 300000000 600000000 400000000 700000000\n"
                "500000000 1000000000 400000000 700000000 600000000 700000000\n"
                "1000000000 1000000000 600000000 700000000 700000000 600000000\n"
                "1000000000 500000000 700000000 600000000 700000000 400000000\n"
                "1000000000 0 700000000 400000000 600000000 300000000\n"
                "500000000 0 400000000 300000000 600000000 300000000\n"
                "500000000 500000000 400000000 300000000 300000000 400000000\n"
                "500000000 500000000 300000000 400000000 300000000 600000000\n"
                "500000000 500000000 300000000 600000000 400000000 700000000\n"
                "500000000 500000000 400000000 700000000 600000000 700000000\n"
                "500000000 500000000 600000000 700000000 700000000 600000000\n"
                "500000000 500000000 700000000 600000000 700000000 400000000\n"
                "500000000 500000000 700000000 400000000 600000000 300000000\n"
                "500000000 500000000 600000000 300000000 400000000 300000000";
        return;
    }
    if(n < 8) {
        cout << "No\n";
        return;
    }
    cout << "Yes\n";
    vector<array<int, 6> > ans;
    vector<array<int, 6> > can_split;
    int st_n = n;
    while(st_n - 3 >= 8) st_n -= 3;
    for(auto& x : a[st_n]) can_split.pb(x);
    while(len(ans) + len(can_split) < n) {
        auto cr = can_split.back(); can_split.pop_back();
        pair<int, int> A = {cr[0], cr[1]}, B = {cr[2], cr[3]}, C = {cr[4], cr[5]};
        if((A.fi + B.fi) % 2 || (A.se + B.se) % 2 || (C.fi + B.fi) % 2 || (C.se + B.se) % 2 || (A.fi + C.fi) % 2 || (A.se + C.se) % 2) {
            ans.push_back(cr);
            continue;
        }
        pair<int, int> AB = {(A.fi + B.fi) / 2, (A.se + B.se) / 2};
        pair<int, int> BC = {(B.fi + C.fi) / 2, (B.se + C.se) / 2};
        pair<int, int> CA = {(A.fi + C.fi) / 2, (A.se + C.se) / 2};
        can_split.pb({A.fi, A.se, AB.fi, AB.se, CA.fi, CA.se});
        can_split.pb({B.fi, B.se, AB.fi, AB.se, BC.fi, BC.se});
        can_split.pb({C.fi, C.se, CA.fi, CA.se, BC.fi, BC.se});
        can_split.pb({AB.fi, AB.se, BC.fi, BC.se, CA.fi, CA.se});
    }
    while(!can_split.empty()) {
        auto cr = can_split.back(); can_split.pop_back();
        for(auto& x : cr) cout << x << ' ';
        cout << '\n';
    }
    while(!can_split.empty()) {
        ans.pb(can_split.back());
        can_split.pop_back();
    }
    for(auto& x : ans) {
        for(auto& xx : x) cout << xx << ' ';
        cout << '\n';
    }
    cout << '\n';
}

signed main() {
//   freopen("input.txt", "r", stdin);
//   freopen("output.txt", "w", stdout);

    a[8].pb({0, 0, 9, 7, 0, 20});
    a[8].pb({0, 20, 9, 7, 10, 20});
    a[8].pb({10, 20, 9, 7, 11, 7});
    a[8].pb({11, 7, 20, 20, 10, 20});
    a[8].pb({11, 7, 20, 0, 20, 20});
    a[8].pb({10, 0, 20, 0, 11, 7});
    a[8].pb({10, 0, 9, 7, 11, 7});
    a[8].pb({0, 0, 10, 0, 9, 7});

    a[9].pb({0, 0, 14, 13, 0, 20});
    a[9].pb({0, 20, 12, 14, 11, 20});
    a[9].pb({11, 20, 12, 14, 14, 15});
    a[9].pb({12, 14, 14, 13, 14, 15});
    a[9].pb({14, 15, 11, 20, 20, 20});
    a[9].pb({14, 15, 20, 20, 20, 14});
    a[9].pb({14, 13, 14, 15, 20, 14});
    a[9].pb({14, 13, 20, 0, 20, 14});
    a[9].pb({0, 0, 20, 0, 14, 13});

    a[10].pb({0, 0, 10, 5, 0, 20});
    a[10].pb({0, 20, 10, 5, 20, 20});
    a[10].pb({20, 0, 10, 5, 20, 20});
    a[10].pb({0, 0, 8, 4, 9, 0});
    a[10].pb({9, 0, 8, 4, 10, 3});
    a[10].pb({10, 3, 10, 5, 8, 4});
    a[10].pb({10, 3, 10, 5, 12, 4});
    a[10].pb({11, 0, 10, 3, 12, 4});
    a[10].pb({9, 0, 11, 0, 10, 3});
    a[10].pb({11, 0, 12, 4, 20, 0});

    for(int i = 8; i <= 10; i++) {
        for(int j = 0; j < len(a[i]); j++)
            for(auto& x : a[i][j])
                x *= 1e9 / 20;
    }

    ios_base::sync_with_stdio(0);
    cin.tie(0);
    cout.tie(0);

    int t = 1;

    //cin >> t;

    while (t--) solve();

}

/*
KIVI
*/

详细

Test #1:

score: 100
Accepted
time: 0ms
memory: 3780kb

input:

2

output:

No

result:

ok no solution

Test #2:

score: 0
Accepted
time: 0ms
memory: 3776kb

input:

24

output:

Yes
0 0 500000000 0 400000000 300000000
1000000000 0 500000000 0 600000000 300000000
0 0 0 500000000 300000000 400000000
0 1000000000 0 500000000 300000000 600000000
0 1000000000 500000000 1000000000 400000000 700000000
1000000000 1000000000 500000000 1000000000 600000000 700000000
1000000000 100000...

result:

ok 24 acute triangles

Test #3:

score: 0
Accepted
time: 0ms
memory: 3612kb

input:

1

output:

No

result:

ok no solution

Test #4:

score: 0
Accepted
time: 0ms
memory: 3600kb

input:

3

output:

No

result:

ok no solution

Test #5:

score: 0
Accepted
time: 0ms
memory: 3468kb

input:

4

output:

No

result:

ok no solution

Test #6:

score: 0
Accepted
time: 0ms
memory: 3780kb

input:

5

output:

No

result:

ok no solution

Test #7:

score: 0
Accepted
time: 0ms
memory: 3428kb

input:

6

output:

No

result:

ok no solution

Test #8:

score: 0
Accepted
time: 0ms
memory: 3596kb

input:

7

output:

No

result:

ok no solution

Test #9:

score: -100
Wrong Answer
time: 0ms
memory: 3560kb

input:

8

output:

Yes
0 0 500000000 0 450000000 350000000 
500000000 0 450000000 350000000 550000000 350000000 
500000000 0 1000000000 0 550000000 350000000 
550000000 350000000 1000000000 0 1000000000 1000000000 
550000000 350000000 1000000000 1000000000 500000000 1000000000 
500000000 1000000000 450000000 350000000...

result:

wrong answer triangle 4 not acute