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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#261412 | #6705. Median | AH20 | AC ✓ | 3ms | 18160kb | C++14 | 2.0kb | 2023-11-22 21:01:53 | 2023-11-22 21:01:53 |
Judging History
answer
#include<bits/stdc++.h>
using namespace std;
const int maxm = 2e5+7;
vector<int>edge[maxm],rev[maxm];
int inv[maxm],ans[maxm],L[maxm],R[maxm],n,m;
int tinv[maxm],trev[maxm],tmp[maxm];
void init(){
for(int i=1;i<=n;i++){
edge[i].clear();
rev[i].clear();
inv[i] = ans[i] = L[i] = R[i] = 0;
tinv[i] = trev[i] = 0;
tmp[i] = 0;
}
}
void topo(){
//跑一遍拓扑,看看是不是DAG
queue<int>Q;
for(int i=1;i<=n;i++){
if(inv[i] == 0) Q.push(i);
}
while(Q.size()){
int now = Q.front();
Q.pop();
for(auto u:edge[now]){
--inv[u];
if(inv[u] == 0){
Q.push(u);
}
}
}
}
void print(){
for(int i=1;i<=n;i++) cout<<ans[i];
cout<<"\n";
}
int dfs1(int now){
if(tmp[now]) return 0;
tmp[now] = 1;
for(auto u:edge[now]){
tmp[now] += dfs1(u);
}
return tmp[now];
}
int dfs2(int now){
if(tmp[now]) return 0;
tmp[now] = 1;
for(auto u:rev[now]){
tmp[now] += dfs2(u);
}
return tmp[now];
}
void calc1(){
for(int i=1;i<=n;i++){
for(int j=1;j<=n;j++) tmp[j] = 0;
dfs1(i);
L[i] = tmp[i];
}
}
void calc2(){
for(int i=1;i<=n;i++){
for(int j=1;j<=n;j++) tmp[j] = 0;
dfs2(i);
R[i] = tmp[i];
}
}
void solve(){
cin>>n>>m;
init();
for(int i=1;i<=m;i++){
int u,v;cin>>u>>v;
edge[v].push_back(u);
rev[u].push_back(v);
inv[u]++;tinv[u]++;
trev[v]++;
}
topo();
for(int i=1;i<=n;i++){
if(inv[i]){
//说明不是DAG,直接返回false
print();
return;
}
}
calc1();
calc2();
for(int i=1;i<=n;i++){
if(L[i]<=(n+1)/2 and R[i]<=(n+1)/2) ans[i] = 1;
}
print();
}
int main(){
ios::sync_with_stdio(false);
cin.tie(0);cout.tie(0);
int T;cin>>T;
while(T--) solve();
return 0;
}
这程序好像有点Bug,我给组数据试试?
详细
Test #1:
score: 100
Accepted
time: 0ms
memory: 17580kb
input:
2 5 4 1 2 3 2 2 4 2 5 3 2 1 1 2 3
output:
01000 000
result:
ok 2 lines
Test #2:
score: 0
Accepted
time: 3ms
memory: 18160kb
input:
66 13 2 9 13 7 11 11 19 9 1 8 1 5 1 2 8 4 2 2 1 5 2 6 3 3 11 3 2 4 6 6 10 9 8 3 5 1 7 5 8 3 9 4 9 6 7 3 1 2 3 11 6 9 4 1 6 5 2 1 5 4 6 8 4 15 15 10 6 15 8 7 6 11 1 5 2 3 4 11 13 4 6 10 12 10 13 1 6 15 2 5 12 13 14 5 3 15 86 14 12 8 1 14 9 8 15 5 10 1 9 11 2 6 2 7 10 10 13 14 5 4 13 5 8 4 10 13 9 6 9...
output:
1111111111111 01001000111 111 11111111111 111111111111111 001001000000000 00100 01100 1111111 1000000000000 111101101 111111111 000011111011101 010111111 001100000 0100001001101 1111111111111 001000010000000 10010111011 001000000000100 11111111111 00100000011 11111 01000000110 11101110111 00000 1111...
result:
ok 66 lines