//vanitas vanitatum et omnia vanitas
#include<bits/stdc++.h>
#define fi first
#define se second
#define eb emplace_back
#define mp make_pair
using namespace std;
typedef long double ld;
typedef long long ll;
typedef unsigned long long ull;
typedef __int128 i128;
template<typename T,typename U>
T ceil(T x, U y) {return (x>0?(x+y-1)/y:x/y);}
template<typename T,typename U>
T floor(T x, U y) {return (x>0?x/y:(x-y+1)/y);}
template<class T,class S>
bool chmax(T &a,const S b) {return (a<b?a=b,1:0);}
template<class T,class S>
bool chmin(T &a,const S b) {return (a>b?a=b,1:0);}
int popcnt(int x) {return __builtin_popcount(x);}
int popcnt(ll x)  {return __builtin_popcountll(x);}
int topbit(int x) {return (x==0?-1:31-__builtin_clz(x));}
int topbit(ll x)  {return (x==0?-1:63-__builtin_clzll(x));}
int lowbit(int x) {return (x==0?-1:__builtin_ctz(x));}
int lowbit(ll x)  {return (x==0?-1:__builtin_ctzll(x));}

#define int long long
#define rep(i,a,b) for(int i=(a);i<=(b);i++)
#define per(i,a,b) for(int i=(a);i>=(b);i--)
typedef pair<int,int> pii;
typedef vector<int> vi;
typedef vector<pii> vp;
typedef tuple<int,int,int> tiii;
int read() {
  int x=0,w=1; char c=getchar(); 
  while(!isdigit(c)) {if(c=='-') w=-1; c=getchar();}
  while(isdigit(c)) {x=x*10+(c-'0'); c=getchar();}
  return x*w;
}

const int N=3e5+5,mod=1e9+7;
int n,s[N],lst[N],m,cur,mul,add,pd,p[N],a[N],tk[N];

int ksm(int x,int y,int r=1) {
  for(;y;y>>=1,x=x*x%mod) if(y&1) r=r*x%mod;
  return r;
}

signed main() {
  n=read(); mul=1;
  rep(i,1,n) {
    int opt=read();
    if(opt==1) {
      m++; lst[m]=cur; int k=read(); s[m]=s[m-1]+(tk[m]=k);
      if(!k) {
        ++pd, cur=m, mul=mul*2%mod, add=add*2%mod;
        a[m]=(mod+1-add)*ksm(mul,mod-2)%mod;
        p[m]=1-pd;
      } else {
        add+=k;
        a[m]=(mod-add)*ksm(mul,mod-2)%mod;
        p[m]=-pd;
      }
    } else if(opt==2) {
      int g=read(), x=read();
      int sa=(a[g]*mul+add)%mod, sp=p[g]+pd;
      printf("%lld\n",(sa+(x-1)*ksm(2,sp))%mod);
    } else {
      int ans=0, k=read();
      for(int x=m;x;) {
        if(!tk[x]) {
          if(k&1) {ans=x; break;}
          else k/=2;
          x--;
        } else {
          int ss=s[x]-s[lst[x]];
          if(k>ss) k-=ss;
          else {
            int l=lst[x]+1, r=x;
            while(l<=r) {
              int mid=l+r>>1;
              if(s[x]-s[mid-1]>=k) ans=mid, l=mid+1;
              else r=mid-1; 
            }
            break;
          }
          x=lst[x];
        }
      }
      printf("%lld\n",ans);
    }
  }
  return 0;
}