QOJ.ac

QOJ

ID题目提交者结果用时内存语言文件大小提交时间测评时间
#260960#7108. CouleurricofxRE 1ms3356kbC++203.8kb2023-11-22 17:05:342023-11-22 17:05:36

Judging History

你现在查看的是最新测评结果

  • [2023-11-22 17:05:36]
  • 评测
  • 测评结果:RE
  • 用时:1ms
  • 内存:3356kb
  • [2023-11-22 17:05:34]
  • 提交

answer

#include <bits/stdc++.h>
using namespace std;
using ll = long long;
const int N = 1e5 + 5;

int n, a[N], p[N];

int Tr[N];
void add(int x, int v) {
    for (; x <= n; x += x & -x) Tr[x] += v;
} 
int qry(int x) {
    int res = 0;
    for (; x; x -= x & -x) res += Tr[x];
    return res;
}
ll Calc(int l, int r) {
    ll res = 0;
    for (int i = l; i <= r; i++) {
        add(a[i], 1);
        res += i - l + 1 - qry(a[i]);
    }
    for (int i = l; i <= r; i++) {
        add(a[i], -1);
    }
    return res;
}
#define mid ((l + r) >> 1)
int rt[N], tot;
struct Node {
    int ls, rs, sum;
} tr[N * 30];
void insert(int &p, int l, int r, int pos) {
    tr[++tot] = tr[p];
    p = tot;
    if (l == r) {
        tr[p].sum++;
        return;
    }
    if (pos <= mid) insert(tr[p].ls, l, mid, pos);
    else insert(tr[p].rs, mid + 1, r, pos);
    tr[p].sum = tr[tr[p].ls].sum + tr[tr[p].rs].sum;
}
int qry(int p, int l, int r, int L, int R) {
    if (l > R || r < L || !p) return 0;
    if (l >= L && r <= R) return tr[p].sum;
    return qry(tr[p].ls, l, mid, L, R) + qry(tr[p].rs, mid + 1, r, L, R);
}
int qry(int L, int R, int l, int r) {
    R = min(R, n);
    if (L > R) return 0;
    return qry(rt[R], 1, n, l, r) - qry(rt[L - 1], 1, n, l, r);
}

struct node {
    int l, r;
    mutable ll id;
    node(int L, int R = -1, ll ID = -1) : l(L), r(R), id(ID) {}  
    inline bool operator < (const node &x) const {
        return l < x.l;
    }
};

#define IT set<node>::iterator
set<node> s;

IT split(int pos) {
    IT it = s.lower_bound(node(pos));
    if(it -> l == pos && it != s.end()) return it;
    --it;
    int v = it->id, l = it->l, r = it->r;
    s.erase(it); s.insert(node(l, pos - 1, v));
    return s.insert(node(pos, r, v)).first;
}
void assign(int l, int r, int id) {
    if (l > r) return;
    IT itr = split(r + 1), itl = split(l);
    s.erase(itl, itr);
    s.insert(node(l, r, id));
}
IT find(int pos) {
    IT it = s.lower_bound(node(pos));
    if(it -> l == pos && it != s.end()) return it;
    --it;
    return it;
}
multiset<ll> mx;

void solve() {
    cin >> n;
    s.clear(), mx.clear();
    for (int i = 0; i <= tot; i++) tr[i].ls = tr[i].rs = tr[i].sum = 0;
    tot = 0;
    for (int i = 1; i <= n; i++) {
        rt[i] = rt[i - 1];
        cin >> a[i];
        insert(rt[i], 1, n, a[i]);
    }
    for (int i = 1; i <= n; i++) cin >> p[i];
    ll now = Calc(1, n), ttmp;
    s.insert(node(1, n, now));
    s.insert(node(n + 1, n + 1, -1));
    mx.insert(now);
    for (int i = 1; i <= n; i++) {
        now = *mx.rbegin();
        cout << now << ' ';
        //return;
        p[i] ^= now;
        IT cur = find(p[i]);
        int L = cur->l, R = cur->r, l, r;
        ll  V = cur->id;
        mx.erase(mx.lower_bound(V));
        if (p[i] - L < R - p[i]) {
            l = L, r = p[i] - 1;
            now = Calc(l, r);
            ttmp = now;
            now += qry(l, r, a[p[i]] + 1, n) + qry(p[i] + 1, R, 1, a[p[i]] - 1);
            for (int j = l; j <= r; j++) {
                now += qry(p[i] + 1, R, 1, a[j] - 1);
            }
            assign(l, r, ttmp), assign(p[i], p[i], 0), assign(p[i] + 1, R, V - now);
            mx.insert(ttmp), mx.insert(V - now);
        } else {
            l = p[i] + 1, r = R;
            now = Calc(l, r);
            ttmp = now;
            now += qry(L, p[i] - 1, a[p[i]] + 1, n) + qry(l, r, 1, a[p[i]] - 1);
            for (int j = l; j <= r; j++) {
                now += qry(L, p[i] - 1, a[j] + 1, n);
            }
            assign(l, r, ttmp), assign(p[i], p[i], 0), assign(L, p[i] - 1, V - now);
            mx.insert(ttmp), mx.insert(V - now);
        }
    }
    cout << '\n';
}

int main() {
    ios::sync_with_stdio(0);
    cin.tie(0);
    int T;
    cin >> T;
    while (T--) solve();
    return 0;
}

詳細信息

Test #1:

score: 100
Accepted
time: 1ms
memory: 3356kb

input:

3
5
4 3 1 1 1
5 4 5 3 1
10
9 7 1 4 7 8 5 7 4 8
21 8 15 5 9 2 4 5 10 6
15
4 8 8 1 12 1 10 14 7 14 2 9 13 10 3
37 19 23 15 7 2 10 15 2 13 4 5 8 7 10

output:

7 0 0 0 0 
20 11 7 2 0 0 0 0 0 0 
42 31 21 14 14 4 1 1 1 0 0 0 0 0 0 

result:

ok 3 lines

Test #2:

score: -100
Runtime Error

input:

11116
10
10 5 10 3 6 4 8 5 9 8
31 27 24 11 12 3 0 2 3 1
10
8 2 7 2 8 10 1 10 9 10
6 5 2 13 2 1 0 1 3 1
10
7 10 7 6 1 3 10 6 7 9
21 18 10 1 6 5 4 8 9 10
10
2 10 4 8 8 5 7 2 6 7
20 10 9 1 15 0 4 2 9 7
10
1 2 3 4 5 6 7 8 9 10
1 2 3 4 5 6 7 8 9 10
10
1 2 3 4 5 6 7 8 9 10
6 3 5 2 7 10 9 1 4 8
10
1 10 1 3...

output:

21 18 16 12 10 6 4 1 1 0 
12 12 10 10 4 4 4 2 1 0 
20 16 9 5 3 3 3 0 0 0 
22 14 8 8 5 5 2 1 1 0 
0 0 0 0 0 0 0 0 0 0 
0 0 0 0 0 0 0 0 0 0 
19 12 7 4 4 2 2 1 0 0 
20 18 8 3 1 1 0 0 0 0 
45 21 21 10 3 3 3 0 0 0 
17 11 8 2 1 1 1 0 0 0 
13 4 1 0 0 0 0 0 0 0 
29 27 22 15 9 7 4 3 1 0 
26 16 9 2 1 1 1 1 1 ...

result: