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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#260578#7738. Equivalent Rewritingucup-team1447#WA 11ms97252kbC++143.0kb2023-11-22 13:17:062023-11-22 13:17:08

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你现在查看的是最新测评结果

  • [2023-11-22 13:17:08]
  • 评测
  • 测评结果:WA
  • 用时:11ms
  • 内存:97252kb
  • [2023-11-22 13:17:06]
  • 提交

answer

// what is matter? never mind. 
#pragma GCC optimize("Ofast")
#pragma GCC optimize("unroll-loops")
//#pragma GCC target("sse,sse2,sse3,sse4,popcnt,abm,mmx,avx,avx2") 
#include<bits/stdc++.h>
#define For(i,a,b) for(int i=(a);i<=(b);++i)
#define Rep(i,a,b) for(int i=(a);i>=(b);--i)
#define ll long long
#define ull unsigned long long
#define int long long
using namespace std;
inline int read()
{
    char c=getchar();int x=0;bool f=0;
    for(;!isdigit(c);c=getchar())f^=!(c^45);
    for(;isdigit(c);c=getchar())x=(x<<1)+(x<<3)+(c^48);
    if(f)x=-x;return x;
}

#define mod 1000000007
struct modint{
	int x;
	modint(int o=0){x=o;}
	modint &operator = (int o){return x=o,*this;}
	modint &operator +=(modint o){return x=x+o.x>=mod?x+o.x-mod:x+o.x,*this;}
	modint &operator -=(modint o){return x=x-o.x<0?x-o.x+mod:x-o.x,*this;}
	modint &operator *=(modint o){return x=1ll*x*o.x%mod,*this;}
	modint &operator ^=(int b){
		modint a=*this,c=1;
		for(;b;b>>=1,a*=a)if(b&1)c*=a;
		return x=c.x,*this;
	}
	modint &operator /=(modint o){return *this *=o^=mod-2;}
	friend modint operator +(modint a,modint b){return a+=b;}
	friend modint operator -(modint a,modint b){return a-=b;}
	friend modint operator *(modint a,modint b){return a*=b;}
	friend modint operator /(modint a,modint b){return a/=b;}
	friend modint operator ^(modint a,int b){return a^=b;}
	friend bool operator ==(modint a,int b){return a.x==b;}
	friend bool operator !=(modint a,int b){return a.x!=b;}
	bool operator ! () {return !x;}
	modint operator - () {return x?mod-x:0;}
	bool operator <(const modint&b)const{return x<b.x;}
};
inline modint qpow(modint x,int y){return x^y;}

vector<modint> fac,ifac,iv;
inline void initC(int n)
{
	if(iv.empty())fac=ifac=iv=vector<modint>(2,1);
	int m=iv.size(); ++n;
	if(m>=n)return;
	iv.resize(n),fac.resize(n),ifac.resize(n);
	For(i,m,n-1){
		iv[i]=iv[mod%i]*(mod-mod/i);
		fac[i]=fac[i-1]*i,ifac[i]=ifac[i-1]*iv[i];
	}
}
inline modint C(int n,int m){
	if(m<0||n<m)return 0;
	return initC(n),fac[n]*ifac[m]*ifac[n-m];
}
inline modint sign(int n){return (n&1)?(mod-1):(1);}

#define fi first
#define se second
#define pb push_back
#define mkp make_pair
typedef pair<int,int>pii;
typedef vector<int>vi;
 
#define maxn 1000005
#define inf 0x3f3f3f3f

int n,m,res[maxn];

vi a[maxn];
set<int>ban[maxn];
vi p[maxn];

void work()
{
	m=read(),n=read();
	For(i,1,n)a[i].clear();
	For(i,1,m){
		ban[i].clear();
		res[i]=i;
		p[i].resize(read());
		for(int&x:p[i]){
			x=read();
			a[x].pb(i);
		}
	}
	For(i,1,n){
		if(a[i].size()){
			int sz=a[i].size();
			int u=a[i].back();
			For(j,0,sz-2){
				ban[u].insert(a[i][j]);
				ban[a[i][j]].insert(u);
			}
		}
	}
	For(i,1,m)
		For(j,1,m)
			if(i!=j && !ban[i].count(j)) {
				swap(res[i],res[j]);
				puts("Yes");
				For(k,1,m)cout<<res[k]<<" \n"[k==m];
				return;
			}
	puts("No");
}

signed main()
{
	int T=read();
	while(T--)work();
    return 0;
}
/*

*/

詳細信息

Test #1:

score: 0
Wrong Answer
time: 11ms
memory: 97252kb

input:

3
3 6
3 3 1 5
2 5 3
2 2 6
2 3
3 1 3 2
2 3 1
1 3
2 2 1

output:

Yes
3 2 1
No
No

result:

wrong answer two transactions are not equivalent. (test case 1)