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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#254321 | #7754. Rolling For Days | ucup-team2230# | WA | 1ms | 3496kb | C++14 | 3.2kb | 2023-11-18 11:04:11 | 2023-11-18 11:04:11 |
Judging History
answer
#include <bits/stdc++.h>
using namespace std;
using ll=long long;
#define rng(i,a,b) for(int i=int(a);i<int(b);i++)
#define rep(i,b) rng(i,0,b)
#define gnr(i,a,b) for(int i=int(b)-1;i>=int(a);i--)
#define per(i,b) gnr(i,0,b)
#define pb push_back
#define eb emplace_back
#define a first
#define b second
#define bg begin()
#define ed end()
#define all(x) x.bg,x.ed
#define si(x) int(x.size())
#ifdef LOCAL
#define dmp(x) cerr<<__LINE__<<" "<<#x<<" "<<x<<endl
#else
#define dmp(x) void(0)
#endif
template<class t,class u> bool chmax(t&a,u b){if(a<b){a=b;return true;}else return false;}
template<class t,class u> bool chmin(t&a,u b){if(b<a){a=b;return true;}else return false;}
template<class t> using vc=vector<t>;
template<class t> using vvc=vc<vc<t>>;
using P=pair<int,int>;
using vi=vc<int>;
const uint mod=998244353;
struct mint{
uint v;
mint(ll vv=0){s(vv%mod+mod);}
mint& s(uint vv){
v=vv<mod?vv:vv-mod;
return *this;
}
mint operator-()const{return mint()-*this;}
mint& operator+=(const mint&r){return s(v+r.v);}
mint&operator-=(const mint&r){return s(v+mod-r.v);}
mint&operator*=(const mint&r){v=(unsigned ll)v*r.v%mod;return *this;}
mint&operator/=(const mint&r){return *this*=r.inv();}
mint operator+(const mint&r)const{return mint(*this)+=r;}
mint operator-(const mint&r)const{return mint(*this)-=r;}
mint operator*(const mint&r)const{return mint(*this)*=r;}
mint operator/(const mint&r)const{return mint(*this)/=r;}
mint pow(ll n)const{
if(n<0)return inv().pow(-n);
mint res(1),x(*this);
while(n){
if(n&1)res*=x;
x*=x;
n>>=1;
}
return res;
}
mint inv()const{return pow(mod-2);}
};
void solve(){
int n,m;
cin>>n>>m;
vc<int> A(m),B(m);
for(int i=0;i<m;i++) cin>>A[i];
int c=0;
for(int i=0;i<m;i++){
cin>>B[i];
c+=B[i];
}
vc<mint> pd(m);
for(int i=0;i<m;i++){
pd[i]=1;
for(int j=0;j<B[i];j++) pd[i]*=A[i]-j;
}
vc<mint> fac(n+1),finv(n+1);
fac[0]=finv[0]=1;
for(int i=1;i<=n;i++){
fac[i]=fac[i-1]*i;
finv[i]=finv[i-1]/i;
}
auto C=[&](int a,int b)->mint{
if(a<b) return 0;
return fac[a]*finv[b]*finv[a-b];
};
vc<int> sa(1<<m),sb(1<<m);
vc<vc<mint>> way(1<<m,vc<mint>(c+1));
vc<vc<vc<mint>>> prom(1<<m,vc<vc<mint>>(c+1,vc<mint>(m)));
for(int S=0;S<1<<m;S++){
way[S][0]=1;
for(int i=0;i<m;i++){
if(S>>i&1){
sa[S]+=A[i];
sb[S]+=B[i];
}
}
for(int k=0;k<sb[S];k++){
way[S][k+1]=way[S][k]*(sa[S]-k);
for(int i=0;i<m;i++){
if((S>>i&1)&&k>=B[i]-1){
prom[S][k+1][i]=way[S^(1<<i)][k-B[i]+1]*C(k,B[i]-1)*pd[i];
way[S][k+1]-=prom[S][k+1][i];
}
}
}
}
vc<vc<mint>> dp(1<<m,vc<mint>(n+1));
dp[0][0]=1;
mint ret=0;
for(int S=0;S<1<<m;S++){
for(int k=0;k<c;k++){
if(dp[S][k].v==0) continue;
int z=k-sb[S],T=((1<<m)-1)^S;
ret+=dp[S][k]*(n-k)/(n-k-sa[S]+sb[S]);
mint inv=(mint) 1/(way[T][z]*(sa[T]-z));
mint rem=1;
for(int i=0;i<m;i++){
if(!(S>>i&1)){
mint p=prom[T][z+1][i]*inv;
dp[S^(1<<i)][k+1]+=dp[S][k]*p;
rem-=p;
}
}
dp[S][k+1]+=dp[S][k]*rem;
}
}
cout<<ret.v<<endl;
}
int main(){
cin.tie(0);
ios::sync_with_stdio(0);
cout<<fixed<<setprecision(20);
int T=1;
while(T--) solve();
}
詳細信息
Test #1:
score: 100
Accepted
time: 1ms
memory: 3392kb
input:
2 2 1 1 1 1
output:
2
result:
ok answer is '2'
Test #2:
score: 0
Accepted
time: 0ms
memory: 3380kb
input:
4 2 2 2 2 1
output:
582309210
result:
ok answer is '582309210'
Test #3:
score: -100
Wrong Answer
time: 0ms
memory: 3496kb
input:
5 5 1 1 1 1 1 0 0 0 0 1
output:
1
result:
wrong answer expected '5', found '1'