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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#252402 | #6744. Square | ucup-team191# | AC ✓ | 30ms | 1608kb | C++14 | 691b | 2023-11-15 19:16:22 | 2023-11-15 19:16:22 |
Judging History
answer
#include <cstdio>
using namespace std;
typedef long long ll;
ll nadi_grupu(ll x){
ll ret = 0;
for(int i = 31;i >= 0;i--) {
ret += (1LL << i);
if(ret * (ret + 1) >= 2 * x)
ret -= (1LL << i);
}
return ret;
}
ll x, y;
void solve(){
scanf("%lld%lld", &x, &y);
if(y <= x) {
printf("%lld\n", x - y);
return;
}
ll x1 = nadi_grupu(x);
ll y1 = nadi_grupu(y);
ll x2 = x - x1 * (x1 + 1) / 2 - 1;
ll y2 = y - y1 * (y1 + 1) / 2 - 1;
if(x1 - x2 <= y1 - y2)
printf("%lld\n", (y1 - y2) - (x1 - x2) + y1 - x1);
else
printf("%lld\n", x2 + y1 - y2 + 2 + y1 - x1);
}
int main(){
int T; scanf("%d", &T);
for(;T--;) solve();
return 0;
}
詳細信息
Test #1:
score: 100
Accepted
time: 0ms
memory: 1536kb
input:
2 5 1 1 5
output:
4 3
result:
ok 2 number(s): "4 3"
Test #2:
score: 0
Accepted
time: 30ms
memory: 1608kb
input:
100000 1 1 1 2 1 3 1 4 1 5 1 6 1 7 1 8 1 9 1 10 1 11 1 12 1 13 1 14 1 15 1 16 1 17 1 18 1 19 1 20 1 21 1 22 1 23 1 24 1 25 1 26 1 27 1 28 1 29 1 30 1 31 1 32 1 33 1 34 1 35 1 36 1 37 1 38 1 39 1 40 1 41 1 42 1 43 1 44 1 45 1 46 1 47 1 48 1 49 1 50 1 51 1 52 1 53 1 54 1 55 1 56 1 57 1 58 1 59 1 60 1 ...
output:
0 2 1 4 3 2 6 5 4 3 8 7 6 5 4 10 9 8 7 6 5 12 11 10 9 8 7 6 14 13 12 11 10 9 8 7 16 15 14 13 12 11 10 9 8 18 17 16 15 14 13 12 11 10 9 20 19 18 17 16 15 14 13 12 11 10 22 21 20 19 18 17 16 15 14 13 12 11 24 23 22 21 20 19 18 17 16 15 14 13 12 26 25 24 23 22 21 20 19 18 1 0 2 2 1 3 4 3 2 4 6 5 4 3 5 ...
result:
ok 100000 numbers