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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#252295#7711. Rikka with LinesSolitaryDream#AC ✓672ms25180kbC++173.3kb2023-11-15 17:48:232023-11-15 17:48:23

Judging History

你现在查看的是最新测评结果

  • [2023-11-15 17:48:23]
  • 评测
  • 测评结果:AC
  • 用时:672ms
  • 内存:25180kb
  • [2023-11-15 17:48:23]
  • 提交

answer

#include<bits/stdc++.h>
using namespace std;

#define int long long

using pii=pair<int,int>;

const int N=3e5+1e3+7;

int T,n;

int a,b,c,d;

int K[N],B[N];

struct POS {
    int p;
    pii x;
};

bool operator <(const POS &a,const POS &b)
{
    if(a.p!=b.p)
        return a.p<b.p;
    if((__int128)a.x.second*b.x.second>0)
        return (__int128)a.x.first*b.x.second<(__int128)a.x.second*b.x.first;
    else
        return (__int128)a.x.first*b.x.second>(__int128)a.x.second*b.x.first;
}

int C[N];

void add(int x,int v)
{
    while(x<=n*2)
    {
        C[x]+=v;
        x+=x&-x;
    }
}

int qry(int x)
{
    int ret=0;
    while(x)
    {
        ret+=C[x];
        x-=x&-x;
    }
    return ret;
}

signed main()
{
    ios::sync_with_stdio(false);
    cin.tie(0);
    cin>>T;
    while(T--)
    {
        cin>>n;
        cin>>a>>b>>c>>d;
        // n=100000,a=0,b=0,c=10000,d=10000;
        for(int i=1;i<=n;i++)
            // K[i]=rand()%10000+1,B[i]=rand()%10000+1;
            cin>>K[i]>>B[i];
        vector<pair<POS,POS> >line;
        vector<POS> X;
        for(int i=1;i<=n;i++)
        {
            POS W[4];
            int C=0;
            {
                int Y=K[i]*a+B[i];
                if(Y>=b&&Y<d)
                    W[C++]={1,{Y-a,1}};
            }

            {
                int Y=K[i]*c+B[i];
                if(Y<=d&&Y>b)
                    W[C++]={3,{d-Y,1}};
            }

            {
                pii t={d-B[i],K[i]};
                if(t.second<0)
                    t.first*=-1,t.second*=-1;
                if(t.first<c*t.second&&t.first>=a*t.second)
                    W[C++]={2,{t.first-a*t.second,t.second}};
            }

            {
                pii t={b-B[i],K[i]};
                if(t.second<0)
                    t.first*=-1,t.second*=-1;
                if(t.first<=c*t.second&&t.first>a*t.second)
                    W[C++]={4,{c*t.second-t.first,t.second}};
            }
            if(!C)
                continue;
            sort(W,W+C);
            line.push_back({W[0],W[C-1]});
            X.push_back(W[0]);
            X.push_back(W[C-1]);
        }
        sort(X.begin(),X.end());
        vector<pii> A;
        for(auto [L,R]:line)
        {
            int l=lower_bound(X.begin(),X.end(),L)-X.begin()+1;
            int r=lower_bound(X.begin(),X.end(),R)-X.begin()+1;
            if(l>r)
                swap(l,r);
            A.push_back({l,r});
        }

        int ans=1ll*A.size()*(A.size()-1)/2;

        fill(C+1,C+n*2+1,0);
        sort(A.begin(),A.end());
        for(int i=(int)A.size()-1,j;i>=0;i=j-1)
        {
            j=i;
            while(j-1>=0&&A[j-1].first==A[i].first)
                j--;
            for(int k=j;k<=i;k++)
                ans-=qry(A[k].second-1);
            for(int k=j;k<=i;k++)
                add(A[k].second,1);
        }

        fill(C+1,C+n*2+1,0);
        sort(A.begin(),A.end());
        for(int i=(int)A.size()-1,j;i>=0;i=j-1)
        {
            j=i;
            while(j-1>=0&&A[j-1].first==A[i].first)
                j--;
            for(int k=j;k<=i;k++)
                ans-=qry(n*2)-qry(A[k].second);
            for(int k=j;k<=i;k++)
                add(A[k].first,1);
        }
        
        cout<<ans<<"\n";
    }
}

详细

Test #1:

score: 100
Accepted
time: 0ms
memory: 7636kb

input:

1
4 0 0 2 2
2 -1
1 0
-1 2
2 2

output:

4

result:

ok 1 number(s): "4"

Test #2:

score: 0
Accepted
time: 672ms
memory: 25180kb

input:

1000
99981 -729383395 -411431000737086146 -663099572 622842060014806018
6815159 -4872972553264521
-44664715 3425012672809037
-896158824 -386342591542384
-375531970 1040294806535662
483111943 -6742268275140254
611052273 -1055860484502308
434838119 6111752598959468
848557869 532300694586514
857250003 ...

output:

1698824
4934994056
4441828315
4940204114
50258056
114560
286
121981
733
118004
1443
111163
115592
38
132
969
112781
115434
115592
1780
1774
116291
109859
246
56
656
116385
110419
3004
1482
111880
117084
281
115308
13187
112786
112123
109307
110632
119
158
120389
118502
117113
104312
111069
134
11784...

result:

ok 1000 numbers