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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#251110 | #5414. Stop, Yesterday Please No More | Eutopia | WA | 0ms | 10180kb | C++14 | 2.6kb | 2023-11-14 11:02:54 | 2023-11-14 11:02:55 |
Judging History
answer
#include <bits/stdc++.h>
#define endl '\n'
#define buff ios::sync_with_stdio(false), cin.tie(nullptr), cout.tie(nullptr);
/*
#pragma GCC optimize ("Ofast")
#pragma GCC optimize ("unroll-loops")
#pragma GCC optimize(3)
*/
using namespace std;
typedef long long ll;
typedef pair<ll, ll> pll;
typedef vector<ll> vll;
typedef vector<pair<ll, ll>> vpll;
const ll MAX_INT = 0x3f3f3f3f;
const ll MAX_LL = 0x3f3f3f3f3f3f3f3f;
const ll CF = 1e3 + 9;
const ll mod = 1e9 + 7;
ll n, m, K;
char s[1000009];
ll f[CF << 2][CF << 2];
void solve() {
cin >> n >> m >> K;
scanf("%s", s + 1);
ll L = 1, R = m, U = 1, D = n;
// for (auto &itt : str) {
// if (itt == 'U') U = max(1ll, U - 1), D = max(1ll, D - 1);
// else if (itt == 'D') U = min(n, U + 1), D = min(n, D + 1);
// else if (itt == 'L') L = max(1ll, L - 1), R = max(1ll, R - 1);
// else L = min(m, L + 1), R = min(m, R + 1);
// }
ll l = 1, r = m, u = 1, d = n;
ll siz = strlen(s + 1);
for (int i = 1; i <= siz; i++) {
if (s[i] == 'D') u++, d++;
else if (s[i] == 'U') u--, d--;
else if (s[i] == 'R') l--, r--;
else l++, r++;
L = max(L, l);
R = min(R, r);
U = max(U, u);
D = min(D, d);
}
if (U > D || L > R) {
if (K == 0) printf("%d\n", n * m);
else printf("0\n");
return;
}
// ¼ÆË㻹²î¼¸Ö»´üÊóÐèÒªÓö´½â¾ö
int delta = (D - U + 1) * (R - L + 1) - K;
if (delta < 0) {
printf("0\n");
return;
}
// ¼Ç¼¶´µÄÆ«ÒÆÁ¿
// Æ«ÒÆÁ¿·¶Î§ÊÇ [-n, n] ÒÔ¼° [-m, m]£¬Òò´Ë¶¼¼ÓÉÏ n + 1 ºÍ m + 1 ±ä³É·Ç¸ºÊý
for (int i = 0; i <= n * 2 + 5; i++) for (int j = 0; j <= m * 2 + 5; j++) f[i][j] = 0;
int BIAS_R = n + 1, BIAS_C = m + 1;
f[BIAS_R][BIAS_C] = 1;
for (int i = 1, r = BIAS_R, c = BIAS_C; s[i]; i++) {
if (s[i] == 'U') r++;
else if (s[i] == 'D') r--;
else if (s[i] == 'L') c++;
else if (s[i] == 'R') c--;
f[r][c] = 1;
}
// ¶þάǰ׺ºÍ
for (int i = 1; i <= n * 2 + 5; i++) for (int j = 1; j <= m * 2 + 5; j++) f[i][j] += f[i][j - 1];
for (int i = 1; i <= n * 2 + 5; i++) for (int j = 1; j <= m * 2 + 5; j++) f[i][j] += f[i - 1][j];
ll ans = 0;
// ö¾Ù¶´µÄ³õʼ×ø±ê
for (int i = 1; i <= n; i++) for (int j = 1; j <= m; j++) {
int biasR = BIAS_R - i, biasC = BIAS_C - j;
int t = f[D + biasR][R + biasC] - f[U - 1 + biasR][R + biasC] - f[D + biasR][L - 1 + biasC] + f[U - 1 + biasR][L - 1 + biasC];
if (t == delta) ans++;
}
printf("%d\n", ans);
}
int main() {
// buff
int t = 1;
cin >> t;
while (t--) {
solve();
}
return 0;
}
/*
3
4 5 3
ULDDRR
4 5 0
UUUUUUU
4 5 10
UUUUUUU
1
3 18 33
UDRLR
*/
详细
Test #1:
score: 100
Accepted
time: 0ms
memory: 3844kb
input:
3 4 5 3 ULDDRR 4 5 0 UUUUUUU 4 5 10 UUUUUUU
output:
2 20 0
result:
ok 3 number(s): "2 20 0"
Test #2:
score: -100
Wrong Answer
time: 0ms
memory: 10180kb
input:
1060 19 12 0 UDLDDUUUUDDDLLRDUDUURULUUUDRDUDRDRLRLRLULULLLDLDDRLUUUURUUUDDRLLRUUUDULURUULLRDRLRDDURDUUURRRLURLRUULRRUDURDLUUURDLURDDLUUURDDRLLURRDLRUDLRDRLLRRDRDDLDRURRRLUDULLLRUUDLRRURRDLLRRRDLLRDDDLRLRURURDDDL 11 1 0 UR 3 18 33 UDRLR 17 11 132 RLDRDLDRUU 6 10 13 UULUDDLRDLUUDLDD 1 15 0 D 6 20 50 D...
output:
228 11 3 99 9 15 17 240 7 0 0 9 11 18 26 0 6 17 108 4 2 2 3 7 0 15 4 15 0 7 10 9 4 5 320 9 5 3 0 0 5 0 11 0 0 7 0 22 36 51 12 7 6 2 2 48 28 8 63 22 49 13 5 4 108 10 9 44 0 13 8 0 4 30 12 99 105 10 14 17 0 66 8 11 28 52 16 56 11 10 56 90 14 0 121 3 48 2 33 10 0 30 5 8 3 11 16 45 20 34 0 20 0 4 0 39 0...
result:
wrong answer 3rd numbers differ - expected: '20', found: '3'