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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#249772#6300. Best Carry Player 2tpc_icpc_n#TL 5ms4196kbC++203.0kb2023-11-12 15:13:372023-11-12 15:13:37

Judging History

你现在查看的是最新测评结果

  • [2023-11-12 15:13:37]
  • 评测
  • 测评结果:TL
  • 用时:5ms
  • 内存:4196kb
  • [2023-11-12 15:13:37]
  • 提交

answer

#include <algorithm>
#include <array>
#include <bitset>
#include <cassert>
#include <chrono>
#include <cmath>
#include <complex>
#include <deque>
#include <forward_list>
#include <fstream>
#include <functional>
#include <iomanip>
#include <ios>
#include <iostream>
#include <limits>
#include <list>
#include <map>
#include <memory>
#include <numeric>
#include <optional>
#include <queue>
#include <random>
#include <set>
#include <sstream>
#include <stack>
#include <string>
#include <tuple>
#include <type_traits>
#include <unordered_map>
#include <unordered_set>
#include <utility>
#include <vector>

using u64 = std::uint64_t;

const std::string MAX = "MAX";

std::string minstr(const std::string& a, const std::string& b) {
    if(a == MAX) return b;
    if(b == MAX) return a;
    if(a.size() < b.size()) return a;
    if(b.size() < a.size()) return b;
    for(int i = a.size(); i --> 0;) {
        if(a[i] < b[i]) return a;
        if(b[i] < a[i]) return b;
    }
    return a;
}

std::string push_back(std::string a, int num) {
    a.push_back((char)(num + '0'));
    return a;
}
const int D = 40;
std::vector dp(D, std::vector(D, std::vector(2, std::vector(2, MAX))));

void solve() {
    u64 X;
    int K;
    std::cin >> X >> K;
    std::string S = std::to_string(X);

    for(int i = 0; i < D; i++) {
        for(int k = 0; k < D; k++) {
            for(int c = 0; c < 2; c++) {
                for(int z = 0; z < 2; z++) {
                    dp[i][k][c][z] = MAX;
                }
            }
        }
    }
    
    dp[0][0][0][0] = "";
    u64 ten = 1;
    u64 now = X;
    for(int i = 0; i < D - 1; i++) {
        u64 num = now % 10;
        now /= 10;
        for(int k = 0; k < D; k++) {
            for(int c = 0; c < 2; c++) {
                for(int z = 0; z < 2; z++) {
                if(dp[i][k][c][z] == MAX) continue;
                u64 x = num + c;
                if(k + 1 < D && x > 0) {
                    dp[i + 1][k + 1][1][z || (10 - x) > 0] = minstr(dp[i + 1][k + 1][1][z || (10 - x) > 0], push_back(dp[i][k][c][z], 10 - x));
                }
                if(x <= 9) {
                    dp[i + 1][k][0][z] = minstr(dp[i + 1][k][0][z], push_back(dp[i][k][c][z], 0));
                }
                if(x <= 8) {
                    dp[i + 1][k][0][1] = minstr(dp[i + 1][k][0][1], push_back(dp[i][k][c][z], 1));
                }
                }
            }
        }
        ten *= 10;
    }
    std::string ans = minstr(dp[D - 1][K][0][1], dp[D - 1][K][1][1]);
    if(ans == MAX) {
        std::cout << -1 << std::endl;
    }
    
    else {
        while(ans.back() == '0') {
            ans.pop_back();
        } 
        std::reverse(ans.begin(), ans.end());
        std::cout << ans << std::endl;
    }
}

int main() {
    std::cin.tie(0);
    std::ios::sync_with_stdio(false);
    int T;
    std::cin >> T;
    while(T--) {
        solve();
    }
}

详细

Test #1:

score: 100
Accepted
time: 0ms
memory: 3972kb

input:

4
12345678 0
12345678 5
12345678 18
990099 5

output:

1
54322
999999999987654322
9910

result:

ok 4 lines

Test #2:

score: 0
Accepted
time: 5ms
memory: 4196kb

input:

21
999990000099999 0
999990000099999 1
999990000099999 2
999990000099999 3
999990000099999 4
999990000099999 5
999990000099999 6
999990000099999 7
999990000099999 8
999990000099999 9
999990000099999 10
999990000099999 11
999990000099999 12
999990000099999 13
999990000099999 14
999990000099999 15
999...

output:

100000
10000
1000
100
10
1
900001
9900001
99900001
999900001
10000000001
9999910000
9999901000
9999900100
9999900010
9999900001
9000009999900001
99000009999900001
999000009999900001
99999999999999999900000000000000000
1000000000000000000

result:

ok 21 lines

Test #3:

score: -100
Time Limit Exceeded

input:

100000
119111011091190000 10
1911011191011999 16
110099199000119 0
19009911191091011 13
199090909919000900 17
19009010011919110 5
90910190019900091 18
10911100000101111 1
110090011101119990 4
100909999119090000 12
90901119109011100 2
111010119991090101 4
900991019109199009 5
100919919990991119 8
911...

output:

88988908810000
8088988808988001
10
88808908989
9800909090080999100
80890
909089809980099909
9
80010
9090000880910000
8900
9909
991
9008900
8880880090
8080090801
8009900808909899
80880898981
909
8800909
99988889901
89908888089
980908890980099000
100
9889801
81
908890008099900891
880990801
9998099
890...

result: