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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#247876#7627. Phonyucup-team088#WA 5ms12160kbC++1710.7kb2023-11-11 16:23:272023-11-11 16:23:27

Judging History

你现在查看的是最新测评结果

  • [2023-11-11 16:23:27]
  • 评测
  • 测评结果:WA
  • 用时:5ms
  • 内存:12160kb
  • [2023-11-11 16:23:27]
  • 提交

answer

#pragma GCC optimize("O3")
#pragma GCC optimize("unroll-loops")
#include<iostream>
#include<string>
#include<cstdio>
#include<vector>
#include<cmath>
#include<algorithm>
#include<functional>
#include<iomanip>
#include<queue>
#include<ciso646>
#include<random>
#include<map>
#include<set>
#include<bitset>
#include<stack>
#include<unordered_map>
#include<unordered_set>
#include<utility>
#include<cassert>
#include<complex>
#include<numeric>
#include<array>
#include<chrono>
using namespace std;

//#define int long long
typedef long long ll;

typedef unsigned long long ul;
typedef unsigned int ui;
//ll mod = 1;
constexpr ll mod = 998244353;
//constexpr ll mod = 1000000007;
const int mod17 = 1000000007;
const ll INF = (ll)mod17 * mod17;
typedef pair<int, int>P;

#define rep(i,n) for(int i=0;i<n;i++)
#define per(i,n) for(int i=n-1;i>=0;i--)
#define Rep(i,sta,n) for(int i=sta;i<n;i++)
#define rep1(i,n) for(int i=1;i<=n;i++)
#define per1(i,n) for(int i=n;i>=1;i--)
#define Rep1(i,sta,n) for(int i=sta;i<=n;i++)
#define all(v) (v).begin(),(v).end()
typedef pair<ll, ll> LP;

using ld = double;
typedef pair<ld, ld> LDP;
const ld eps = 1e-10;
const ld pi = acosl(-1.0);

template<typename T>
void chmin(T& a, T b) {
    a = min(a, b);
}
template<typename T>
void chmax(T& a, T b) {
    a = max(a, b);
}
template<typename T>
vector<T> vmerge(vector<T>& a, vector<T>& b) {
    vector<T> res;
    int ida = 0, idb = 0;
    while (ida < a.size() || idb < b.size()) {
        if (idb == b.size()) {
            res.push_back(a[ida]); ida++;
        }
        else if (ida == a.size()) {
            res.push_back(b[idb]); idb++;
        }
        else {
            if (a[ida] < b[idb]) {
                res.push_back(a[ida]); ida++;
            }
            else {
                res.push_back(b[idb]); idb++;
            }
        }
    }
    return res;
}
template<typename T>
void cinarray(vector<T>& v) {
    rep(i, v.size())cin >> v[i];
}
template<typename T>
void coutarray(vector<T>& v) {
    rep(i, v.size()) {
        if (i > 0)cout << " "; cout << v[i];
    }
    cout << "\n";
}
ll mod_pow(ll x, ll n, ll m = mod) {
    if (n < 0) {
        ll res = mod_pow(x, -n, m);
        return mod_pow(res, m - 2, m);
    }
    if (abs(x) >= m)x %= m;
    if (x < 0)x += m;
    //if (x == 0)return 0;
    ll res = 1;
    while (n) {
        if (n & 1)res = res * x % m;
        x = x * x % m; n >>= 1;
    }
    return res;
}
//mod should be <2^31
struct modint {
    int n;
    modint() :n(0) { ; }
    modint(ll m) {
        if (m < 0 || mod <= m) {
            m %= mod; if (m < 0)m += mod;
        }
        n = m;
    }
    operator int() { return n; }
};
bool operator==(modint a, modint b) { return a.n == b.n; }
bool operator<(modint a, modint b) { return a.n < b.n; }
modint operator+=(modint& a, modint b) { a.n += b.n; if (a.n >= mod)a.n -= (int)mod; return a; }
modint operator-=(modint& a, modint b) { a.n -= b.n; if (a.n < 0)a.n += (int)mod; return a; }
modint operator*=(modint& a, modint b) { a.n = ((ll)a.n * b.n) % mod; return a; }
modint operator+(modint a, modint b) { return a += b; }
modint operator-(modint a, modint b) { return a -= b; }
modint operator*(modint a, modint b) { return a *= b; }
modint operator^(modint a, ll n) {
    if (n == 0)return modint(1);
    modint res = (a * a) ^ (n / 2);
    if (n % 2)res = res * a;
    return res;
}

ll inv(ll a, ll p) {
    return (a == 1 ? 1 : (1 - p * inv(p % a, a)) / a + p);
}
modint operator/(modint a, modint b) { return a * modint(inv(b, mod)); }
modint operator/=(modint& a, modint b) { a = a / b; return a; }
const int max_n = 1 << 20;
modint fact[max_n], factinv[max_n];
void init_f() {
    fact[0] = modint(1);
    for (int i = 0; i < max_n - 1; i++) {
        fact[i + 1] = fact[i] * modint(i + 1);
    }
    factinv[max_n - 1] = modint(1) / fact[max_n - 1];
    for (int i = max_n - 2; i >= 0; i--) {
        factinv[i] = factinv[i + 1] * modint(i + 1);
    }
}
modint comb(int a, int b) {
    if (a < 0 || b < 0 || a < b)return 0;
    return fact[a] * factinv[b] * factinv[a - b];
}
modint combP(int a, int b) {
    if (a < 0 || b < 0 || a < b)return 0;
    return fact[a] * factinv[a - b];
}

ll gcd(ll a, ll b) {
    a = abs(a); b = abs(b);
    if (a < b)swap(a, b);
    while (b) {
        ll r = a % b; a = b; b = r;
    }
    return a;
}
template<typename T>
void addv(vector<T>& v, int loc, T val) {
    if (loc >= v.size())v.resize(loc + 1, 0);
    v[loc] += val;
}
/*const int mn = 2000005;
bool isp[mn];
vector<int> ps;
void init() {
    fill(isp + 2, isp + mn, true);
    for (int i = 2; i < mn; i++) {
        if (!isp[i])continue;
        ps.push_back(i);
        for (int j = 2 * i; j < mn; j += i) {
            isp[j] = false;
        }
    }
}*/

//[,val)
template<typename T>
auto prev_itr(set<T>& st, T val) {
    auto res = st.lower_bound(val);
    if (res == st.begin())return st.end();
    res--; return res;
}

//[val,)
template<typename T>
auto next_itr(set<T>& st, T val) {
    auto res = st.lower_bound(val);
    return res;
}
using mP = pair<modint, modint>;
mP operator+(mP a, mP b) {
    return { a.first + b.first,a.second + b.second };
}
mP operator+=(mP& a, mP b) {
    a = a + b; return a;
}
mP operator-(mP a, mP b) {
    return { a.first - b.first,a.second - b.second };
}
mP operator-=(mP& a, mP b) {
    a = a - b; return a;
}
LP operator+(LP a, LP b) {
    return { a.first + b.first,a.second + b.second };
}
LP operator+=(LP& a, LP b) {
    a = a + b; return a;
}
LP operator-(LP a, LP b) {
    return { a.first - b.first,a.second - b.second };
}
LP operator-=(LP& a, LP b) {
    a = a - b; return a;
}

mt19937 mt(time(0));

const string drul = "DRUL";
string senw = "SENW";
//DRUL,or SENW
//int dx[4] = { 1,0,-1,0 };
//int dy[4] = { 0,1,0,-1 };

//------------------------------------
template<typename T>
struct BIT {
private:
    vector<T> node; int n;
public:
    BIT(int n_) {
        n = n_; node.resize(n, 0);
    }
    //0-indexed
    void add(int a, T w) {
        for (int i = a; i < n; i |= i + 1)node[i] += w;
    }
    //[0,a)
    T sum(int a) {
        T ret = 0;
        for (int i = a - 1; i >= 0; i = (i & (i + 1)) - 1)ret += node[i];
        return ret;
    }
    //[a,b)
    T sum(int a, int b) {
        return sum(b) - sum(a);
    }
};

using T = __int128;
void solve() {
    int n, q; ll k; cin >> n >> q >> k;
    vector<ll> a(n);
    rep(i, n)cin >> a[i];
    sort(all(a));
    vector<LP> rs;
    rep(i, n)rs.push_back({ a[i] % k,i });
    sort(all(rs));
    vector<int> locs(n);
    rep(i, n)locs[rs[i].second] = i;
    BIT<int> bt(n);
    BIT<int> bttmp(n);


    vector<pair<T, int>> qs;
    T sumq = 0;
    rep(i, q) {
        char typ; cin >> typ;
        if (typ == 'A') {
            int x; cin >> x;
            qs.push_back({ sumq,x });
        }
        else {
            ll x; cin >> x;
            sumq += x;
        }
    }

    T sum = 0;

    vector < pair<ll, P>> vp;
    rep(i, n) {
        int le = i;
        while (i + 1 < n&&a[i] / k == a[i + 1] / k)i++;
        vp.push_back({ a[i] / k,{le,i + 1} });
    }
    int loc = 0;

    auto getxs = [&](int x) {
        int cl = -1, cr = n;
        while (cr - cl > 1) {
            int mid = (cl + cr) / 2;
            int c = bt.sum(0,mid);
            if (c > x)cr = mid;
            else cl = mid;
        }
        return cl;
    };
    vector<ll> ans;
    int cnt = 0;
    per(i, vp.size()) {
        int le = vp[i].second.first;
        int ri = vp[i].second.second;
        Rep(j, le, ri) {
            bttmp.add(locs[j], 1);
        }
        cnt += vp[i].second.second - vp[i].second.first;
        ll dif = vp[i].first;
        if (i > 0)dif -= vp[i - 1].first;
        else {
            dif += INF;
        }
        while (loc < qs.size() && qs[loc].first <= sum + (T)(dif - 1) * cnt) {
            T dif = qs[loc].first - sum;
            ll dd = dif / cnt;
            ll r = dif % cnt;
            int x = qs[loc].second;
            ll ansval;
            if (x > cnt) {
                ansval = a[n - x];
            }
            else if (x <= cnt - r) {
                int v = getxs(cnt - r - x);
                ansval = (vp[i].first - dd) * k + rs[v].first;
            }
            else {
                x -= cnt - r;
                int v = getxs(cnt-x);
                ansval = (vp[i].first - dd - 1) * k + rs[v].first;
            }
            ans.push_back(ansval);
            loc++;
        }
        while (loc < qs.size() && qs[loc].first <= sum + (T)dif * cnt) {
            T dif = qs[loc].first - sum;
            ll dd = dif / cnt;
            ll r = dif % cnt;
            int x = qs[loc].second;
            ll ansval;
            if (x <= cnt - r) {
                int v = getxs(cnt - r - x);
                ansval = (vp[i].first - dd) * k + rs[v].first;
            }
            else {
                x -= cnt - r;
                int vv = getxs(cnt - r);
                //cout << "?? " << vv << "\n";
                int cl = -1, cr = n;
                while (cr - cl > 1) {
                    int mid = (cl + cr) / 2;
                    int num = 0;
                    num += bt.sum(max(mid, vv), n);
                    num += bttmp.sum(mid, n);
                    if (num >= x) {
                        cl = mid;
                    }
                    else {
                        cr = mid;
                    }
                }
                //cout << "?? " << cl << "\n";
                ansval = (vp[i].first - dd - 1) * k + rs[cl].first;
            }
            ans.push_back(ansval);
            loc++;
        }
        //cout << loc << ans.size() << "\n";
        Rep(j, le, ri) {
            bttmp.add(locs[j], -1);
            bt.add(locs[j], 1);
        }
        sum += (T)dif * cnt;
    }
    assert(loc == qs.size());
    //cout << qs.size() << "\n";
    for (auto v : ans)cout << v << "\n";

    /*ll dr = 0;
    ll dd = 0;
    
    rep(i, q) {
        char typ; cin >> typ;
        if (typ == 'A') {
            int x; cin >> x; x--;
            ll ans;
            if (loc == vp.size()) {
                ans = a[n - x];
            }
            else {

            }
        }
        else {
            ll x; cin >> x;
            
        }
    }*/
}



signed main() {
    ios::sync_with_stdio(false);
    cin.tie(0);
    //cout << fixed<<setprecision(10);
    //init_f();
    //init();
    //init2();
    //while(true)
    //expr();
    //int t; cin >> t; rep(i, t)
    solve();
    return 0;
}


詳細信息

Test #1:

score: 100
Accepted
time: 4ms
memory: 12160kb

input:

3 5 5
7 3 9
A 3
C 1
A 2
C 2
A 3

output:

3
4
-1

result:

ok 3 lines

Test #2:

score: -100
Wrong Answer
time: 5ms
memory: 11904kb

input:

5 8 8
294 928 293 392 719
A 4
C 200
A 5
C 10
A 2
C 120
A 1
A 3

output:

294
200
191
0
-1

result:

wrong answer 5th lines differ - expected: '-2', found: '-1'