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IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#246709#7523. Partially Free MealikefumyRE 0ms9576kbC++206.2kb2023-11-11 01:11:372023-11-11 01:11:37

Judging History

你现在查看的是最新测评结果

  • [2023-11-11 01:11:37]
  • 评测
  • 测评结果:RE
  • 用时:0ms
  • 内存:9576kb
  • [2023-11-11 01:11:37]
  • 提交

answer

#include<bits/stdc++.h>
using namespace std;
#define ll long long
#define ull unsigned long long
#define db double
#define pii pair<int,int>
#define pli pair<ll,int>
#define pil pair<int,ll>
#define pll pair<ll,ll>
#define ti3 tuple<int,int,int>
#define int128 __int128_t
#define pii128 pair<int128,int128>
const int inf = 1 << 30;
const ll linf = 1e18;
const ll mod = 1e9 + 7;
const db EPS = 1e-10;
const db pi = acos(-1);
template<class T> bool chmin(T& x, T y){
    if(x > y) {
        x = y;
        return true;
    } else return false;
}
template<class T> bool chmax(T& x, T y){
    if(x < y) {
        x = y;
        return true;
    } else return false;
}

// overload macro
#define CAT( A, B ) A ## B
#define SELECT( NAME, NUM ) CAT( NAME, NUM )

#define GET_COUNT( _1, _2, _3, _4, _5, _6 /* ad nauseam */, COUNT, ... ) COUNT
#define VA_SIZE( ... ) GET_COUNT( __VA_ARGS__, 6, 5, 4, 3, 2, 1 )

#define VA_SELECT( NAME, ... ) SELECT( NAME, VA_SIZE(__VA_ARGS__) )(__VA_ARGS__)

// rep(overload)
#define rep( ... ) VA_SELECT(rep, __VA_ARGS__)
#define rep2(i, n) for (int i = 0; i < int(n); i++)
#define rep3(i, a, b) for (int i = a; i < int(b); i++)
#define rep4(i, a, b, c) for (int i = a; i < int(b); i += c)

// repll(overload)
#define repll( ... ) VA_SELECT(repll, __VA_ARGS__)
#define repll2(i, n) for (ll i = 0; i < (ll)(n); i++)
#define repll3(i, a, b) for (ll i = a; i < (ll)(b); i++)
#define repll4(i, a, b, c) for (ll i = a; i < (ll)(b); i += c)

// rrep(overload)
#define rrep( ... ) VA_SELECT(rrep, __VA_ARGS__)    
#define rrep2(i, n) for (int i = n - 1; i >= 0; i--)
#define rrep3(i, a, b) for (int i = b - 1; i >= a; i--)
#define rrep4(i, a, b, c) for (int i = b - 1; i >= a; i -= c)

// rrepll(overload)
#define rrepll( ... ) VA_SELECT(rrepll, __VA_ARGS__)
#define rrepll2(i, n) for (ll i = (ll)(n) - 1; i >= 0ll; i--)
#define rrepll3(i, a, b) for (ll i = b - 1; i >= (ll)(a); i--)
#define rrepll4(i, a, b, c) for (ll i = b - 1; i >= (ll)(a); i -= c)

// for_earh
#define fore(e, v) for (auto&& e : v)

// vector
#define all(v) v.begin(), v.end()
#define rall(v) v.rbegin(), v.rend()

template<class T, T(* op)(T, T), T(* e)()>
struct segment_tree {
private:
    int n, tn;
    vector<T> node;

public:
    segment_tree(int _n, vector<T> a = {}) : tn(_n) {
        n = 1;
        while (n < _n) n *= 2;

        node.resize(2 * n, e());
        if (!a.empty()) {
            for (int i = 0; i < (int)a.size(); i++) {
                update(i, a[i]);
            }
        }
    }

    void update(int i, T val) {
        i += n;
        node[i] = val;
        while (i / 2) {
            i /= 2;
            node[i] = op(node[i * 2], node[i * 2 + 1]);
        }
    }

    T get_val(int l, int r) {
        l += n;
        r += n;
        
        T lval = e(), rval = e();
        while (l < r) {
            if (l & 1) lval = op(lval, node[l++]);
            if (r & 1) rval = op(node[--r], rval);
            l /= 2, r /= 2;
        }

        return op(lval, rval);
    }

    template<class F>
    int right_search(int i, F f) {
        int ret = i, len = 1;
        i += n;
        T val = e();
        while (ret < n) {
            if (i & 1) {
                if (!f(op(val, node[i]))) break;
                val = op(val, node[i]);
                ret += len;
                i++;
            }
            len *= 2, i /= 2;
        }

        while (len > 1) {
            len /= 2, i *= 2;
            if (f(op(val, node[i]))) {
                val = op(val, node[i]);
                ret += len;
                i++;
            }
        }
        
        return min(ret, tn);
    }

    template<class F>
    int left_search(int i, F f) {
        int ret = i, len = 1;
        i += n;
        T val = e();
        while (ret > 0) {
            if (i & 1) {
                i--;
                if (!f(op(node[i], val))) break;
                val = op(node[i], val);
                ret -= len;
            }
            len *= 2, i /= 2;
        }

        while (len > 1) {
            len /= 2, i = i * 2 + 1;
            if (f(op(node[i], val))) {
                val = op(node[i], val);
                ret -= len;
                i--;
            }
        }

        return ret;
    }
};

int n;
int l[200010], r[200010], lb[200010], ub[200010], anum[200010];
ll ans[200010], idx[200010];

pil op(pil a, pil b) {
    return {a.first + b.first, a.second + b.second};
}

pil e() {
    return {0, 0};
}

int main() {
    cin.tie(nullptr);
    ios_base::sync_with_stdio(false);
    cout << fixed << setprecision(20);
    cin >> n;
    vector<pii> m;
    vector<int> as;
    rep (i, 1, n + 1) {
        ll a, b;
        cin >> a >> b;
        m.push_back({b, a});
        as.push_back(a);
        r[i] = n, ans[i] = linf;
    }

    sort(all(m));
    sort(all(as));
    map<int, int> cnt;
    rep (i, n) {
        anum[i] = lower_bound(all(as), m[i].second) - as.begin() + cnt[m[i].second]++;
    }

    vector<int> q = {(n + 2) / 2};
    lb[(n + 2) / 2] = 1, ub[(n + 2) / 2] = n + 1;
    while (!q.empty()) {
        vector<int> nq;
        segment_tree<pil, op, e> st(n);
        int prei = 0;
        fore (k, q) {
            rep (i, min(l[k], prei), r[k]) {
                auto [b, a] = m[i];
                if (prei <= i) st.update(anum[i], {1, a});
                if (i + 1 < k) continue;
                int it = st.right_search(0, [&](pil p) {
                    return p.first <= k;
                });
                ll mnsum = st.get_val(0, it).second;
                if (ans[k] >= mnsum + b) ans[k] = mnsum + b, idx[k] = i;
            }

            auto update = [&](int x, int y, int nl, int nr) -> void {
                if (x == y) return;
                int mid = (x + y) / 2;
                lb[mid] = x, ub[mid] = y, l[mid] = nl, r[mid] = nr;
                nq.push_back(mid);
            };

            prei = r[k];
            update(lb[k], k, l[k], idx[k] + 1);
            update(k + 1, ub[k], idx[k], r[k]);
        }
        q = nq;
    }

    rep (i, 1, n + 1) {
        cout << ans[i] << '\n';
    }
}

Details

Tip: Click on the bar to expand more detailed information

Test #1:

score: 100
Accepted
time: 0ms
memory: 9576kb

input:

3
2 5
4 3
3 7

output:

7
11
16

result:

ok 3 lines

Test #2:

score: -100
Runtime Error

input:

200000
466436993 804989151
660995237 756645598
432103296 703610564
6889895 53276988
873617076 822481192
532911431 126844295
623111499 456772252
937464699 762157133
708503076 786039753
78556972 5436013
582960979 398984169
786333369 325119902
930705057 615928139
924915828 506145001
164984329 208212435...

output:


result: