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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#246685 | #5159. Justice Served | thanhchauns2# | WA | 1ms | 5728kb | C++17 | 3.5kb | 2023-11-11 00:14:58 | 2023-11-11 00:15:00 |
Judging History
answer
#pragma GCC optimize("O3,unroll-loops")
#pragma GCC target("avx2,bmi,bmi2,lzcnt,popcnt")
#define rd read()
#define pb push_back
#define eb emplace_back
#define f first
#define s second
#define p pair
#include <bits/stdc++.h>
#include <ext/pb_ds/assoc_container.hpp>
#include <ext/pb_ds/trie_policy.hpp>
using namespace std;
using namespace __gnu_pbds;
namespace {
typedef long long ll; typedef long double ld; typedef unsigned long long ull; typedef pair<int,int> pii; typedef pair<ll,ll> pll;
// istream& operator>>(istream& i, ll &v){ long long t; i >> t; v = t; return i;}
// ostream& operator<<(ostream& out, ll &v){
// vector<long long> x; ll u = v;
// while(u){x.pb(u % 10); u /= 10;}
// reverse(x.begin(), x.end());
// for (auto &o : x){out << o;} return out;
// }
ll read(){ ll x; cin >> x; return x; } ld PI = 3.14159265358979323846; ld eps = 1e-6; ll mod = 1e9 + 7;
template<typename T> void Unique(T &a) {a.erase(unique(a.begin(), a.end()), a.end());}
template<typename T1, typename T2> ostream& operator<<(ostream& out, const p<T1, T2>& x) {return out << x.f << ' ' << x.s;}
template<typename T1, typename T2> istream& operator>>(istream& in, p<T1, T2>& x) {return in >> x.f >> x.s;}
template<typename T> istream& operator>>(istream& in, vector<T>& a) {for(auto &x : a) in >> x; return in;};
template<typename T> ostream& operator<<(ostream& out, vector<T>& a) {for(auto &x : a) out << x << ' '; return out;};
template<typename T> istream& operator>>(istream& in, deque<T>& a) {for(auto &x : a) in >> x; return in;};
template<typename T> ostream& operator<<(ostream& out, deque<T>& a) {for(auto &x : a) out << x << ' '; return out;};
template<typename T> using ordered_set = tree<T, null_type,less<T>, rb_tree_tag,tree_order_statistics_node_update>;
template<typename T> using ordered_multiset = tree<T, null_type,less_equal<T>, rb_tree_tag,tree_order_statistics_node_update>;
template<typename T> using pq = priority_queue<T>; template<typename T> using reverse_pq = priority_queue<T, vector<T>, greater<T> >;
template<typename T> using matrix = vector<vector<T> >; template<typename T> using rubik = vector<vector<vector<T> > >;
vector<ll> rdv(int sz) { vector<ll> x(sz); cin >> x;return x; }
mt19937_64 mrand(chrono::steady_clock::now().time_since_epoch().count());
const int N = 1e6 + 5;
} // main template
ll ans[N]{}, n, x;
ll TREE[2 * N]{};
void add(ll p, ll value){
for (TREE[p += n] = value; p > 1; p >>= 1) TREE[p>>1] = max(TREE[p], TREE[p^1]);
}
ll query(ll l, ll r){
ll ans = -10;
for (l += n, r += n; l < r; l >>= 1, r >>= 1){
if (l & 1){
ans = max(ans, TREE[l++]);
}
if (r & 1){
ans = max(ans, TREE[--r]);
}
}
return ans;
}
void solve(){
n = rd, x = 1; matrix<ll> C; set<ll> S; map<ll, ll> MM;
for (int i = 0; i < n; i++){
ll f = rd, s = rd; s += f;
C.pb({s, -f, i}); S.insert(f); S.insert(s); // last, -first, index
}
for (int i = 0; i <= 2 * n; i++){
TREE[i] = -1;
}
n *= 2;
// cout << C << '\n';
for (auto &o : S){
MM[o] = x++;
}
for (auto &o : C){
o[0] = MM[o[0]];
o[1] = -MM[-o[1]];
}
// cout << C << '\n';
sort(C.rbegin(), C.rend());
for (int i = 0; i < C.size(); i++){
ll idx = C[i][2];
ans[idx] = query(0, -C[i][1] + 1) + 1;
add(-C[i][1], ans[idx]);
}
for (int i = 0; i < n / 2; i++){
cout << ans[i] << ' ';
}
}
signed main(){
cin.tie(0) -> ios::sync_with_stdio(false);
for (int i = 1, j = 1; i > 0; i--, j++) {
solve();
}
}
詳細信息
Test #1:
score: 0
Wrong Answer
time: 1ms
memory: 5728kb
input:
4 2 8 1 7 4 5 5 2
output:
1 0 2 3
result:
wrong answer 1st lines differ - expected: '0 0 1 2', found: '1 0 2 3 '