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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#246429#7686. The Phantom Menacedo_while_trueTL 608ms470452kbC++144.7kb2023-11-10 20:15:292023-11-10 20:15:30

Judging History

你现在查看的是最新测评结果

  • [2024-10-08 14:11:03]
  • hack成功,自动添加数据
  • (/hack/941)
  • [2024-10-08 10:05:28]
  • hack成功,自动添加数据
  • (/hack/940)
  • [2024-10-07 19:51:15]
  • hack成功,自动添加数据
  • (/hack/938)
  • [2024-10-07 19:28:01]
  • hack成功,自动添加数据
  • (/hack/937)
  • [2024-10-07 17:16:32]
  • hack成功,自动添加数据
  • (/hack/936)
  • [2024-10-07 16:53:09]
  • hack成功,自动添加数据
  • (/hack/935)
  • [2024-10-07 16:22:17]
  • hack成功,自动添加数据
  • (/hack/934)
  • [2023-11-10 20:15:30]
  • 评测
  • 测评结果:TL
  • 用时:608ms
  • 内存:470452kb
  • [2023-11-10 20:15:29]
  • 提交

answer

#include<cstdio>
#include<vector>
#include<queue>
#include<cstring>
#include<iostream>
#include<algorithm>
#include<ctime>
#include<map>
#include<random>
#include<assert.h>
#include<functional>
#define pb emplace_back
#define mp make_pair
#define fi first
#define se second
#define dbg(x) cerr<<"In Line "<< __LINE__<<" the "<<#x<<" = "<<x<<'\n'
#define dpi(x,y) cerr<<"In Line "<<__LINE__<<" the "<<#x<<" = "<<x<<" ; "<<"the "<<#y<<" = "<<y<<'\n'
#define DE(fmt,...) fprintf(stderr, "Line %d : " fmt "\n",__LINE__,##__VA_ARGS__)
using namespace std;
typedef long long ll;
typedef unsigned long long ull;
typedef pair<int,int>pii;
typedef pair<ll,int>pli;
typedef pair<ll,ll>pll;
typedef pair<int,ll>pil;
typedef vector<int>vi;
typedef vector<ll>vll;
typedef vector<pii>vpii;
typedef vector<pll>vpll;
template<typename T>T cmax(T &x, T y){return x=x>y?x:y;}
template<typename T>T cmin(T &x, T y){return x=x<y?x:y;}
template<typename T>
T &read(T &r){
	r=0;bool w=0;char ch=getchar();
	while(ch<'0'||ch>'9')w=ch=='-'?1:0,ch=getchar();
	while(ch>='0'&&ch<='9')r=r*10+(ch^48),ch=getchar();
	return r=w?-r:r;
}
template<typename T1,typename... T2>
void read(T1 &x,T2& ...y){read(x);read(y...);}
const ll mod1=1000000007;
const ll mod2=998244353;
const ll base1=233;
const ll base2=277;
const int N=2000010;
int n,m;
int p[N],q[N];
string a[N],b[N];
ll bas1[N],bas2[N];
vll sa1[N],sa2[N];
vll sb1[N],sb2[N];
pll qrya(int i,int l,int r){
	return mp(
		(sa1[i][r]-sa1[i][l-1]*bas1[r-l+1]%mod1+mod1)%mod1,
		(sa2[i][r]-sa2[i][l-1]*bas2[r-l+1]%mod2+mod2)%mod2
	);
}
pll qryb(int i,int l,int r){
	return mp(
		(sb1[i][r]-sb1[i][l-1]*bas1[r-l+1]%mod1+mod1)%mod1,
		(sb2[i][r]-sb2[i][l-1]*bas2[r-l+1]%mod2+mod2)%mod2
	);
}
int tot;
vpii eg1[N],eg2[N],eg[N];
int head[N],vis[N],in[N];
vi vec1,vec2;
int fa[N];
int getfa(int x){return fa[x]==x?x:fa[x]=getfa(fa[x]);}
void merge(int x,int y){fa[getfa(x)]=getfa(y);}
void solve(){
	read(n,m);
	bas1[0]=bas2[0]=1;
	for(int i=1;i<=m;i++){
		bas1[i]=bas1[i-1]*base1%mod1;
		bas2[i]=bas2[i-1]*base2%mod2;
	}
	for(int i=1;i<=n;i++){
		cin>>a[i];
		a[i]=' '+a[i];
		sa1[i].resize(m+1);
		sa2[i].resize(m+1);
		for(int j=1;j<=m;j++){
			sa1[i][j]=(sa1[i][j-1]*base1+a[i][j])%mod1;
			sa2[i][j]=(sa2[i][j-1]*base2+a[i][j])%mod2;
		}
	}
	for(int i=1;i<=n;i++){
		cin>>b[i];
		b[i]=' '+b[i];
		sb1[i].resize(m+1);
		sb2[i].resize(m+1);
		for(int j=1;j<=m;j++){
			sb1[i][j]=(sb1[i][j-1]*base1+b[i][j])%mod1;
			sb2[i][j]=(sb2[i][j-1]*base2+b[i][j])%mod2;
		}
	}
	for(int i=1;i<=n;i++)p[i]=q[i]=1;
	sort(p+1,p+n+1,[&](int &x,int &y){return qrya(x,1,m)<qrya(y,1,m);});
	sort(q+1,q+n+1,[&](int &x,int &y){return qryb(x,1,m)<qryb(y,1,m);});
	int fl=1;
	for(int i=1;i<=n;i++)if(qrya(i,1,m)!=qryb(i,1,m)){fl=0;break;}
	if(fl){
		for(int i=1;i<=n;i++)cout<<p[i]<<' ';
		puts("");
		for(int i=1;i<=n;i++)cout<<q[i]<<' ';
		puts("");
		return ;
	}
	for(int d=1;d<m;d++){
		map<pll,int>v1,v2;
		int c1=0,c2=0;
		for(int i=1;i<=n;i++){
			auto l=qrya(i,1,d),r=qrya(i,d+1,m);
			if(!v1[l])v1[l]=++c1;
			if(!v2[r])v2[r]=++c2;
			eg1[v1[l]].pb(mp(v2[r],i));
		}
		for(int i=1;i<=n;i++){
			auto l=qryb(i,1,m-d),r=qryb(i,m-d+1,m);
			if(!v2[l])v2[l]=++c2;
			if(!v1[r])v1[r]=++c1;
			eg2[v2[l]].pb(mp(v1[r],i));
		}
		tot=c1+c2;
		for(int i=1;i<=tot;i++)fa[i]=i;
		for(int x=1;x<=c1;x++){
			for(auto v:eg1[x]){
				v.fi+=c1;
				eg[x].pb(v);
				merge(x,v.fi+c1);
			}
		}
		for(int x=1;x<=c2;x++){
			for(auto v:eg2[x]){
				v.se+=n;
				eg[x+c1].pb(v);
				merge(x+c1,v.fi);
			}
		}
		int lt=1;
		for(int i=2;i<=tot;i++)if(getfa(i)!=getfa(lt)){lt=0;break;}
		for(int i=1;i<=tot;i++)in[i]=0;
		for(int i=1;i<=tot;i++)
			for(auto j:eg[i])
				in[j.fi]++;
		for(int i=1;i<=tot;i++)
			if(in[i]!=(int)eg[i].size())
				lt=0;
		if(!lt)continue;
		for(int i=1;i<=tot;i++)head[i]=0;
		for(int i=1;i<=2*n;i++)vis[i]=0;
		vi().swap(vec1);
		vi().swap(vec2);
		function<void(int)>dfs=[&](int x){
			for(int &i=head[x];i<(int)eg[x].size();i++){
			int v=eg[x][i].fi,id=eg[x][i].se;
				if(!vis[id]){
					vis[id]=1;
					dfs(v);
					if(id<=n)vec1.pb(id);
					else vec2.pb(id-n);
				}
			}
		};
		dfs(1);
		reverse(vec1.begin(),vec1.end());
		reverse(vec2.begin(),vec2.end());
		for(auto i:vec1)cout<<i<<' ';
		puts("");
		for(auto i:vec2)cout<<i<<' ';
		puts("");
		return ;
	}
	puts("-1");
}
signed main(){
	#ifdef do_while_true
//		assert(freopen("data.in","r",stdin));
//		assert(freopen("data.out","w",stdout));
	#endif
	int T;read(T);
	while(T--)solve();
    #ifdef do_while_true
//		cerr<<'\n'<<"Time:"<<1.0*clock()/CLOCKS_PER_SEC*1000<<" ms"<<'\n';
	#endif
	return 0;
}

詳細信息

Test #1:

score: 100
Accepted
time: 75ms
memory: 470452kb

input:

2
3 3
abc
ghi
def
bcd
efg
hia
1 3
abc
def

output:

1 3 2 
1 2 3 
-1

result:

ok 2 cases (2 test cases)

Test #2:

score: 0
Accepted
time: 608ms
memory: 466356kb

input:

1000000
1 1
b
b
1 1
a
b
1 1
b
a
1 1
a
a
1 1
b
b
1 1
a
b
1 1
b
a
1 1
a
a
1 1
b
b
1 1
a
b
1 1
b
a
1 1
a
a
1 1
b
b
1 1
a
b
1 1
b
a
1 1
a
a
1 1
b
b
1 1
a
b
1 1
b
a
1 1
a
a
1 1
b
b
1 1
a
b
1 1
b
a
1 1
a
a
1 1
b
b
1 1
a
b
1 1
b
a
1 1
a
a
1 1
b
b
1 1
a
b
1 1
b
a
1 1
a
a
1 1
b
b
1 1
a
b
1 1
b
a
1 1
a
a
1 1
...

output:

1 
1 
-1
-1
1 
1 
1 
1 
-1
-1
1 
1 
1 
1 
-1
-1
1 
1 
1 
1 
-1
-1
1 
1 
1 
1 
-1
-1
1 
1 
1 
1 
-1
-1
1 
1 
1 
1 
-1
-1
1 
1 
1 
1 
-1
-1
1 
1 
1 
1 
-1
-1
1 
1 
1 
1 
-1
-1
1 
1 
1 
1 
-1
-1
1 
1 
1 
1 
-1
-1
1 
1 
1 
1 
-1
-1
1 
1 
1 
1 
-1
-1
1 
1 
1 
1 
-1
-1
1 
1 
1 
1 
-1
-1
1 
1 
1 
1 
-1
-1
...

result:

ok 1000000 cases (1000000 test cases)

Test #3:

score: -100
Time Limit Exceeded

input:

500000
1 2
dd
ba
1 2
cd
ba
1 2
bd
ba
1 2
ad
ba
1 2
dc
ba
1 2
cc
ba
1 2
bc
ba
1 2
ac
ba
1 2
db
ba
1 2
cb
ba
1 2
bb
ba
1 2
ab
ba
1 2
da
ba
1 2
ca
ba
1 2
ba
ba
1 2
aa
ba
1 2
dd
aa
1 2
cd
aa
1 2
bd
aa
1 2
ad
aa
1 2
dc
aa
1 2
cc
aa
1 2
bc
aa
1 2
ac
aa
1 2
db
aa
1 2
cb
aa
1 2
bb
aa
1 2
ab
aa
1 2
da
aa
1 2...

output:

-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
1 
1 
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
1 
1 
1 
1 
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
1 
1 
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
1 
1 
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
1 
1 
-1
-1
-1
-1
-1
-1
-1
-1
-1
-1
...

result: