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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#246387 | #7104. Halting Problem | ucup-team2190# | ML | 1ms | 3512kb | C++20 | 2.5kb | 2023-11-10 19:40:34 | 2023-11-10 19:40:35 |
Judging History
answer
#include <bits/stdc++.h>
#pragma GCC optimize("O3")
using namespace std;
#define int long long
#define endl "\n"
#ifdef LOCAL_SYS
#include "debug.h"
#else
#define dbg(...)
#endif
void solve(){
int n;
cin >> n;
map<string, int> mp;
mp["add"] = 1, mp["beq"] = 2, mp["bne"] = 3, mp["blt"] = 4, mp["bgt"] = 5;
vector<vector<int>> v(n, vector<int> (3));
for(int i = 0;i < n;i++){
string s;
cin >> s;
v[i][0] = mp[s];
if(v[i][0] == 1){
cin >> v[i][1];
}
else{
cin >> v[i][1] >> v[i][2];
v[i][2]--;
}
}
const int MOD = 256;
vector<vector<int>> dp(n+5, vector<int> (260, 0));
function <int(int,int)> f = [&](int ind, int val){
if(ind == n) return 0ll;
if(dp[ind][val] == 1) return 1ll; // loop
dp[ind][val] = 1;
if(v[ind][0] == 1){
return f(ind+1, (val + v[ind][1])%MOD);
}
else{
int cur = v[ind][0], idx = v[ind][2], c = v[ind][1];
if(cur == 2 && c == val){
return f(idx, val);
}
else if(cur == 2){
return f(ind+1, val);
}
if(cur == 3 && c != val){
return f(idx, val);
}
else if(cur == 3){
return f(ind+1, val);
}
if(cur == 4 && c > val){
return f(idx, val);
}
else if(cur == 4){
return f(ind+1, val);
}
if(cur == 5 && c < val){
return f(idx, val);
}
else if(cur == 5){
return f(ind+1, val);
}
}
return 0ll;
};
int x = f(0, 0);
cout << ( x ? "No" : "Yes") << endl;
}
signed main(){
ios_base::sync_with_stdio(0);
cin.tie(0);
#ifdef LOCAL_SYS
freopen("error.txt", "w", stderr);
auto start = chrono::high_resolution_clock::now();
cerr << fixed << setprecision(4);
#endif
int t = 1;
cin >> t;
for(int i = 1;i <= t;i++){
solve();
}
#ifdef LOCAL_SYS
auto stop = chrono::high_resolution_clock::now();
auto duration = chrono::duration_cast<chrono::nanoseconds> (stop - start);
cerr << endl << "Time: " << ((long double)duration.count())/((long double)1e9) << "s " << endl;
#endif
return 0;
}
详细
Test #1:
score: 100
Accepted
time: 1ms
memory: 3512kb
input:
4 2 add 1 blt 5 1 3 add 252 add 1 bgt 252 2 2 add 2 bne 7 1 3 add 1 bne 252 1 beq 252 1
output:
Yes Yes No No
result:
ok 4 lines
Test #2:
score: -100
Memory Limit Exceeded
input:
1117 8 bgt 51 8 add 75 add 115 bne 40 3 beq 213 6 bgt 210 4 blt 228 7 bgt 60 2 6 bne 130 3 add 33 bne 74 4 blt 73 6 blt 63 5 bne 138 2 6 beq 131 2 bgt 90 3 add 127 bgt 195 1 blt 244 6 bne 20 3 3 add 53 bne 122 1 blt 251 2 9 add 102 add 161 bne 26 2 blt 5 8 beq 76 3 add 119 bgt 196 3 bne 239 8 blt 15...