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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#245775#7688. Alea Iacta EstzhoukangyangWA 6ms3712kbC++112.2kb2023-11-10 12:00:212023-11-10 12:00:21

Judging History

你现在查看的是最新测评结果

  • [2023-11-10 12:00:21]
  • 评测
  • 测评结果:WA
  • 用时:6ms
  • 内存:3712kb
  • [2023-11-10 12:00:21]
  • 提交

answer

#include<bits/stdc++.h>
#define L(i, j, k) for(int i = (j); i <= (k); ++i)
#define R(i, j, k) for(int i = (j); i >= (k); --i)
#define ll long long
#define vi vector <int>
#define sz(a) ((int) (a).size())
#define me(f, x) memset(f, x, sizeof(f))
#define uint unsigned int
#define ull unsigned long long 
#define i128 __int128
using namespace std;
const int N = 1 << 21;
const ll mod = (ll) 998244353 * 1019260817, base = 19491001;

int n, m;

pair < vi, vi > DV(int x, int y) {
	vi ls, rs;
	L(i, 0, x - 1) 
		ls.emplace_back(i * y);
	L(i, 0, y - 1) 
		rs.emplace_back(i);
	return make_pair(ls, rs);
}

vi Mul(vi a, vi b) {
	vi c;
	for(auto&u : a) 
		for(auto&v : b)
			c.emplace_back(u + v);
	sort(c.begin(), c.end());
	return c; 
}
void Main() {
	cin >> n >> m;
	if(n > m) swap(n, m);
	ll mul = (ll) n * m;
	ll ptl = 0, ptr = 0;
	ll A = -1, B = -1, C = -1, D = -1;
	R(i, sqrt(mul), 1) 
		if(mul % i == 0) {
			ptl = i, ptr = mul / i;
			if(ptl != n) {
				L(a, 1, ptl) 
					if(ptl % a == 0 && n % a == 0) {
						ll b = n / a;
						if(ptl % a == 0) {
							ll c = ptl / a;
							if(m % c == 0) {
								A = a;
								B = b;
								C = c;
								D = m / c;
							}
						}
					}	
			} else {
				L(a, 2, n) 
					if(n % a == 0) {
						ll b = n / a;
						if(m % b == 0) {
							ll d = m / b;	
							if(a == 1 || b == 1 || d == 1) {
								continue;
							}
							A = a;
							B = b;
							C = b;
							D = d;
						}
					}	
			
			}
			
			if(A != -1) break;
		}
	auto p1 = DV(A, B);
	auto p2 = DV(C, D);
	ll qwq = (ll)sz(p1.first) * sz(p2.first) + (ll) sz(p1.second) * sz(p2.second);
	if(qwq > n * 2 + m) {
		cout << n * 2 << ' ';
		L(i, 1, n) 
			cout << i << ' ' << i << ' ';
		cout << '\n';
		cout << m << ' ';
		L(i, 1, m) {
			cout << i << ' ';
		}
		cout << '\n';
		return ;
	}
	auto T1 = Mul(p1.first, p2.first);
	auto T2 = Mul(p1.second, p2.second);
	cout << sz(T1) << ' ';
	for(auto&x : T1) 
		cout << x + 1 << ' ';
	cout << '\n';
	cout << sz(T2) << ' ';
	for(auto&x : T2) 
		cout << x + 1 << ' ';
	cout << '\n' << '\n';
}
int main () {
	ios :: sync_with_stdio(false);
	cin.tie(0); cout.tie(0);
	int t; cin >> t; while(t--) Main();
	return 0;
}

詳細信息

Test #1:

score: 100
Accepted
time: 1ms
memory: 3392kb

input:

3
2 8
1 9
2 9

output:

4 1 2 5 6 
4 1 2 3 4 

3 1 4 7 
3 1 2 3 

3 1 4 7 
6 1 2 2 3 3 4 


result:

ok Correct. (3 test cases)

Test #2:

score: 0
Accepted
time: 6ms
memory: 3712kb

input:

1
40013 40013

output:

80026 1 1 2 2 3 3 4 4 5 5 6 6 7 7 8 8 9 9 10 10 11 11 12 12 13 13 14 14 15 15 16 16 17 17 18 18 19 19 20 20 21 21 22 22 23 23 24 24 25 25 26 26 27 27 28 28 29 29 30 30 31 31 32 32 33 33 34 34 35 35 36 36 37 37 38 38 39 39 40 40 41 41 42 42 43 43 44 44 45 45 46 46 47 47 48 48 49 49 50 50 51 51 52 52 ...

result:

ok Correct. (1 test case)

Test #3:

score: -100
Wrong Answer
time: 1ms
memory: 3460kb

input:

1
40013 1

output:

0 
0 


result:

wrong answer Integer parameter [name=n1] equals to 0, violates the range [1, 40015] (test case 1)