QOJ.ac

QOJ

ID题目提交者结果用时内存语言文件大小提交时间测评时间
#245424#6439. Cloud Retainer's GamezbhruaruaAC ✓997ms35176kbC++202.4kb2023-11-09 21:48:052023-11-09 21:48:07

Judging History

你现在查看的是最新测评结果

  • [2023-11-09 21:48:07]
  • 评测
  • 测评结果:AC
  • 用时:997ms
  • 内存:35176kb
  • [2023-11-09 21:48:05]
  • 提交

answer

#include<cstdio>
#include<cstdlib>
#include<cstring>
#include<cmath>
#include<iostream>
#include<iomanip>
#include<algorithm>
#include<vector>
#include<map>
#include<queue>
#include<bitset>
#include<set> 
#define ll long long
#define lowbit(x) x&(-x)
#define mp make_pair
#define rep(i,x,n) for(int i=x;i<=n;i++)
#define per(i,n,x) for(int i=n;i>=x;i--)
#define forE(i,x) for(int i=head[x];i;i=nxt[i])
#define pii pair<int,int>
#define fi first
#define se second
using namespace std;
const int maxn=1e6+5;
const int mod=998244353;
const int INF=1e9;
inline int read()
{
	int x=0,f=1;char c=getchar();
	while(c<'0'||c>'9')
	{
		if(c=='-') f=-1;
		c=getchar();
	}
	while(c>='0'&&c<='9')
	{
		x=x*10+(c-'0');
		c=getchar();
	}
	return x*f;
}
int T;
struct node{
    ll x,y,t;
}a[maxn];
map<ll,int> p[2];
signed main()
{
	T=read();
	while(T--)
	{
        p[0].clear(),p[1].clear();
        ll H=read();
        int n=read(),tot=0;
        rep(i,1,n) a[++tot]={read(),read(),0};
        int m=read();
        rep(i,1,m) a[++tot]={read(),read(),1};
        sort(a+1,a+tot+1,[&](node u,node v)->bool {return u.x<v.x;});
        int ans=1;
        p[0][0] = 1;
        p[1][0] = 1;
        rep(i,1,tot)
        {
            ll x=a[i].x,y=a[i].y,t=a[i].t;
            int up = p[0][(x-y)%(2*H)];
            int down = p[1][(x+y)%(2*H)];
            if(up==0) up=-INF;
            if(down==0) down=-INF;
            ans=max(ans,max(up,down)+(t==1));
            if(t==1) 
            {
                p[0][(x-y)%(2*H)] = max(p[0][(x-y)%(2*H)],up+1);
                int topx=H-y+x,topy=H;
                p[1][(topx+topy)%(2*H)] = max(p[1][(topx+topy)%(2*H)],up+1);
                p[1][(x+y)%(2*H)] = max(p[1][(x+y)%(2*H)],down+1);
                int lowx=x+y,lowy=0;
                p[0][(lowx-lowy)%(2*H)] = max(p[0][(lowx-lowy)%(2*H)],down+1);
            }
            else
            {
                int v=max(up,down);
                p[0][(x-y)%(2*H)] = max(p[0][(x-y)%(2*H)],v);
                int topx=H-y+x,topy=H;
                p[1][(topx+topy)%(2*H)] = max(p[1][(topx+topy)%(2*H)],v);
                p[1][(x+y)%(2*H)] = max(p[1][(x+y)%(2*H)],v);
                int lowx=x+y,lowy=0;
                p[0][(lowx-lowy)%(2*H)] = max(p[0][(lowx-lowy)%(2*H)],v);                
            }      
        }
        printf("%d\n",ans-1);
	}
}

詳細信息

Test #1:

score: 100
Accepted
time: 0ms
memory: 3808kb

input:

2
4
3
1 1
2 2
6 2
4
3 1
3 3
5 1
7 3
3
1
4 2
3
1 1
6 2
9 1

output:

3
3

result:

ok 2 number(s): "3 3"

Test #2:

score: 0
Accepted
time: 505ms
memory: 11252kb

input:

5503
10
19
2 4
2 8
8 3
8 4
8 7
2 7
2 6
1 5
3 2
6 4
2 1
4 5
2 5
7 1
4 7
5 7
2 2
8 6
8 1
12
5 1
4 8
5 2
6 1
3 6
1 1
1 7
7 2
5 6
6 8
1 2
3 5
10
5
9 5
10 7
6 6
5 7
1 3
9
6 8
8 8
6 4
2 9
5 4
4 2
10 9
2 3
2 1
7
1
4 3
14
4 6
6 1
2 1
7 6
2 3
4 4
5 3
6 5
1 4
3 4
3 2
6 2
8 6
8 2
6
6
5 2
5 1
3 1
2 3
7 4
5 5
3
...

output:

2
1
2
1
3
2
0
2
4
6
1
2
0
0
1
2
1
1
0
1
0
0
2
1
1
3
2
3
3
2
1
2
0
1
5
1
1
1
0
1
3
1
2
3
3
3
2
1
0
3
1
2
2
0
4
1
1
0
1
2
2
2
1
1
1
1
2
3
2
2
2
1
1
3
1
3
0
0
3
4
5
1
1
1
1
1
0
2
0
0
3
0
2
1
1
1
0
3
2
1
3
4
3
2
2
4
2
4
2
1
2
1
0
1
3
0
3
0
2
1
0
2
5
1
2
2
1
0
1
3
0
2
3
1
4
2
2
0
2
3
2
0
0
3
1
1
1
1
3
2
...

result:

ok 5503 numbers

Test #3:

score: 0
Accepted
time: 997ms
memory: 35176kb

input:

54
83
1995
54 14
42 63
23 55
46 52
94 71
16 18
51 54
62 47
90 38
42 50
82 20
8 28
52 64
49 19
56 5
10 74
99 30
90 42
48 2
11 78
4 38
78 77
26 26
47 12
82 60
41 17
87 2
37 16
51 15
32 63
88 82
76 33
44 10
94 28
31 5
30 80
29 19
35 70
88 78
39 69
40 5
84 52
87 59
54 36
34 76
88 42
42 37
79 70
27 77
19...

output:

47
32
32
32
38
32
39
33
39
40
36
32
36
32
46
30
35
41
40
36
108
90
98
81
166
115
106
170
148
113
198
72
57
202
337
153
186
978
87
886
151
489
111
112
90
154
174
188
266
59
10210
1041
87
981

result:

ok 54 numbers