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IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#245347#6309. AqreDoqeRE 4ms50504kbC++142.4kb2023-11-09 20:52:462023-11-09 20:52:47

Judging History

你现在查看的是最新测评结果

  • [2023-11-09 20:52:47]
  • 评测
  • 测评结果:RE
  • 用时:4ms
  • 内存:50504kb
  • [2023-11-09 20:52:46]
  • 提交

answer


#include<bits/stdc++.h>
using namespace std;
const int N=1e6+100;
vector<int>G[N],K[N];
const int A[4][4]=
{
    {1,1,1,0},
    {1,1,0,1},
    {0,1,1,1},
    {1,0,1,1}
},B[4][4]=
{
    {1,1,1,0},
    {1,0,1,1},
    {1,1,1,0},
    {0,1,0,0}
};
void solve(int n,int m)
{
    // cerr<<"SOLVE : "<<n<<","<<m<<endl;
    if(n==1)
    {
        cout<<min(m,3)<<"\n";
        for(int i=1;i<=3&&i<=m;++i)cout<<"1";
        for(int i=4;i<=m;++i)cout<<"0";
        cout<<"\n";
        return;
    }
    if(m==1)
    {
        cout<<min(n,3)<<"\n";
        for(int i=1;i<=3&&i<=n;++i)cout<<"1\n";
        for(int i=4;i<=n;++i)cout<<"0\n";
        return;
    }
    if(n<=3&&m<=3)
    {
        cout<<n*m<<"\n";
        for(int i=1;i<=n;++i,cout<<"\n")
            for(int j=1;j<=m;++j)
                cout<<"1";
        return;
    }
    for(int i=0;i<n+10;++i)
        G[i].resize(m+10);
    for(int i=0;i<n+10;++i)
        K[i].resize(m+10);
    int dx=0,dy=0;
    if(n%4==0)++dx;
    if(m%4==0)++dy;
    if(n==2)
    {
        dx=1,dy=1;
    }
    else if(m==2)
    {
        dx=2,dy=1;
    }
    if(n==3||m==3)
        for(int i=0;i<n+4;i+=4)
            for(int j=0;j<m+4;j+=4)
                for(int x=0;x<4;++x)
                    for(int y=0;y<4;++y)
                        G[i+x][j+y]=B[x][y];
    else
    {
        for(int i=0;i<n+4;i+=4)
            for(int j=0;j<m+4;j+=4)
                for(int x=0;x<4;++x)
                    for(int y=0;y<4;++y)
                        G[i+x][j+y]=A[x][y],
                        K[j+x][i+y]=A[x][y];
        int c1=0,c2=0;
        for(int i=0;i<n;++i)
            for(int j=0;j<m;++j)
                c1+=G[i+dx][j+dy],c2+=K[j+dy][i+dx];
        if(c2>c1)
        {
            for(int i=0;i<n;++i)
                for(int j=0;j<m;++j)
                    G[i+dx][j+dy]=K[j+dy][i+dx];
        }
    }
    // if(n==2)++dx;
    // if(m==2)++dy;
    int cnt=0;
    for(int i=0;i<n;++i)
        for(int j=0;j<m;++j)
            cnt+=G[i+dx][j+dy];
    cout<<cnt<<"\n";
    for(int i=0;i<n;++i,cout<<"\n")
        for(int j=0;j<m;++j)
            cout<<G[i+dx][j+dy];
    for(int i=0;i<n+10;++i)G[i].clear(),K[i].clear();
}
int main()
{
    ios::sync_with_stdio(false);
    cin.tie(nullptr),cout.tie(nullptr);
    int T;
    cin>>T;
    while(T--)
    {
        int n,m;
        cin>>n>>m;
        solve(n,m);
        cout<<flush;
    }

}

Details

Tip: Click on the bar to expand more detailed information

Test #1:

score: 100
Accepted
time: 4ms
memory: 50504kb

input:

3
2 2
3 4
3 8

output:

4
11
11
9
1101
0111
1101
18
11011101
01110111
11011101

result:

ok ok (3 test cases)

Test #2:

score: -100
Runtime Error

input:

361
2 2
2 3
2 4
2 5
2 6
2 7
2 8
2 9
2 10
2 11
2 12
2 13
2 14
2 15
2 16
2 17
2 18
2 19
2 20
3 2
3 3
3 4
3 5
3 6
3 7
3 8
3 9
3 10
3 11
3 12
3 13
3 14
3 15
3 16
3 17
3 18
3 19
3 20
4 2
4 3
4 4
4 5
4 6
4 7
4 8
4 9
4 10
4 11
4 12
4 13
4 14
4 15
4 16
4 17
4 18
4 19
4 20
5 2
5 3
5 4
5 5
5 6
5 7
5 8
5 9
5 1...

output:

4
11
11
6
111
111
6
1011
1110
8
10111
11101
9
101110
111011
11
1011101
1110111
12
10111011
11101110

result: