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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#240972 | #7110. Kuririn MIRACLE | pandapythoner | WA | 374ms | 4000kb | C++23 | 5.0kb | 2023-11-05 21:30:10 | 2023-11-05 21:30:11 |
Judging History
answer
#include <bits/stdc++.h>
using namespace std;
#define ll long long
#define flt double
#define all(a) a.begin(), a.end()
#define rall(a) a.rbegin(), a.rend()
using ld = long double;
struct vec {
ld x, y;
vec(ld x, ld y) : x(x), y(y){};
ld operator%(const vec &o) const {
return x * o.y - y * o.x;
}
};
ld v, r, d;
const int n = 15;
vector<ld> fct;
void build_fct() {
fct.resize(n + 1);
fct[0] = 1;
for (int i = 1; i <= n; i += 1) {
fct[i] = fct[i - 1] * i;
}
}
vector<ld> mul(const vector<ld> &a, const vector<ld> &b) {
vector<ld> c(n, 0);
for (int i = 0; i < n; i += 1) {
for (int j = 0; j < n; j += 1) {
if (i + j >= n) {
break;
}
c[i + j] += a[i] * b[j];
}
}
return c;
}
vector<ld> operator*(const vector<ld> &a, const vector<ld> &b) {
return mul(a, b);
}
vector<ld> operator+(const vector<ld> &a, const vector<ld> &b) {
vector<ld> c(n);
for (int i = 0; i < n; i += 1) {
c[i] = a[i] + b[i];
}
return c;
}
vector<ld> operator*(ld x, const vector<ld> &a) {
vector<ld> c(n);
for (int i = 0; i < n; i += 1) {
c[i] = x * a[i];
}
return c;
}
vector<ld> operator-(const vector<ld> &a, const vector<ld> &b) {
vector<ld> c(n);
for (int i = 0; i < n; i += 1) {
c[i] = a[i] - b[i];
}
return c;
}
vector<ld> get_rev(const vector<ld> &a) {
vector<ld> b(n);
b[0] = 1 / a[0];
for (int i = 1; i < n; i += 1) {
ld cur_sm = 0;
for (int j = 0; j < i; j += 1) {
cur_sm += a[i - j] * b[j];
}
b[i] = -cur_sm / a[0];
}
return b;
}
vector<ld> operator/(const vector<ld> &a, const vector<ld> &b) {
auto rvb = get_rev(b);
return a * rvb;
}
vector<ld> deriv(const vector<ld> &a) {
vector<ld> c(n);
c[n - 1] = 0;
for (int i = 1; i < n; i += 1) {
c[i - 1] = a[i] * i;
}
return c;
}
vector<ld> integr(const vector<ld> &a) {
vector<ld> c(n);
c[0] = 0;
for (int i = 0; i + 1 < n; i += 1) {
c[i + 1] = a[i] / ((ld)(i) + 1);
}
return c;
}
vector<ld> log(const vector<ld> &a) {
ll t = a[0];
auto c = integr(deriv(a) / a);
c[0] = log(t);
return c;
}
vector<ld> exp(const vector<ld> &a) {
vector<ld> rs(n, 0);
vector<ld> apw(n, 0);
apw[0] = 1;
for (int i = 0; i < n; i += 1) {
rs = rs + (1 / fct[i]) * apw;
apw = apw * a;
}
return rs;
}
void print(const vector<ld> &a) {
for (auto x : a) {
cerr << x << " ";
}
cerr << "\n";
}
vector<ld> sinx() {
vector<ld> a(n);
for (int i = 1; i < n; i += 2) {
if (((i - 1) / 2) % 2 == 0) {
a[i] = 1 / fct[i];
} else {
a[i] = -1 / fct[i];
}
}
return a;
}
ld get_val(vector<ld> &a, ld x) {
ld pw = 1;
ld rs = 0;
for (int i = 0; i < n; i += 1) {
rs += a[i] * pw;
pw *= x;
}
return rs;
}
vector<ld> sqrt(const vector<ld> &a) {
auto b = 0.5 * log(a);
return exp(b);
}
vector<ld> gnrt;
ld f(ld a) {
ld sn = sin(a);
return sqrtl(3 + sn * sn) + sn;
}
ld integral_a(ld a) {
static const int N = 1e5;
ld res = 0;
for (int i = 1; i < N; ++i) {
ld l = (i - 1) * a / N;
ld r = i * a / N;
res += f(l) + f(r) + 4 * f((l + r) / 2);
}
return res * a / 6 / N;
}
ld time_a(ld a) {
ld cnst = 2 * r / 3 / v;
// return cnst * get_val(gnrt, a);
return cnst * integral_a(a);
}
int32_t main() {
build_fct();
if (1) {
vector<ld> sn = sinx();
cout << get_val(sn, 2) << " " << sin(2) << "\n";
}
auto sn = sinx();
auto sn2 = sn * sn;
vector<ld> three(n, 0);
three[0] = 3;
auto a = sqrt(three + sn2) + sn;
gnrt = integr(a);
if (1) {
ios::sync_with_stdio(0);
cin.tie(0);
cout.tie(0);
}
#ifdef LOCAL
freopen("../input.txt", "r", stdin);
freopen("../output.txt", "w", stdout);
#endif
int tt;
cin >> tt;
cout << fixed << setprecision(20);
while (tt--) {
cin >> v >> r >> d;
ld lo = 0, hi = M_PI;
static const int kek = 50;
for (int _ = 0; _ < kek; ++_) {
ld a = (lo + hi) / 2;
ld t = time_a(a);
ld sn = sin(a), cs = cos(a);
ld u = v * (sqrtl(sn * sn + 3) - sn);
vec cur(v + u * sn, u * cs);
vec dir(d - 2 * r - v * t + 2 * r * cs, -2 * r * sn);
if (dir % cur > 0) {
lo = a;
} else {
hi = a;
}
}
ld t = time_a(hi);
ld sn = sin(hi), cs = cos(hi);
ld x = d - 2 * r - v * t + 2 * r * cs, y = -2 * r * sn;
ld ans = t + sqrtl((x * x + y * y)) / (2 * v);
ans = min(ans, d / v);
cout << ans << '\n';
}
return 0;
}
詳細信息
Test #1:
score: 0
Wrong Answer
time: 374ms
memory: 4000kb
input:
1 2.00 3 30.0
output:
0.909297 0.909297 8.31054539457454717697
result:
wrong answer 1st numbers differ - expected: '8.3105799', found: '0.9092970', error = '0.8905856'