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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#240723#6352. SPPPSPSS.jzh#WA 0ms3560kbC++206.1kb2023-11-05 17:57:592023-11-05 17:58:00

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你现在查看的是最新测评结果

  • [2023-11-05 17:58:00]
  • 评测
  • 测评结果:WA
  • 用时:0ms
  • 内存:3560kb
  • [2023-11-05 17:57:59]
  • 提交

answer

#include <bits/stdc++.h>

using namespace std;

typedef long long ll;
const int N = 1e6 + 5;
int n;
int a[N];
char SP[N];


void fun() {

    int m = (n+1)/2;
    vector<int> L, R;
    string tmpans1, tmpans;
    string ans1, ans2;
    int mnt = 1e9;

    if (n%2 == 1) {
        // check P at m
        L.clear();
        R.clear();
        for (int i=1; i<=m; i++) if (a[i] > m) L.push_back(a[i]);
        for (int i=m+1; i<=n; i++) if (a[i] < m) R.push_back(a[i]);
        sort(L.begin(), L.end());
        sort(R.rbegin(), R.rend());
        tmpans1 = tmpans = "";
        for (int t=m-1, f=0; t>=1; t--, f^=1) {
            tmpans1 += "S";
        }
        for (int t=m, f=0, pl=L.size(), pr=R.size(); t<=n && (pl>0 || pr>0); t++, f^=1) {
            if (f == 0) {   // P
                tmpans+="P";
                int d = t-m;
                pr -= d;
            }
            else {          // S
                tmpans += "S";
                int d = t - (n - m);
                pl -= d;
            }
            if (pl<=0 && pr<=0) {
                if (t < mnt) {
                    mnt = t;
                    ans1 = tmpans1;
                    ans2 = tmpans;
                }
                break;
            }
        }


        // check S at m
        L.clear();
        R.clear();
        for (int i=1; i<m; i++) if (a[i] > m) L.push_back(a[i]);
        for (int i=m; i<=n; i++) if (a[i] < m) R.push_back(a[i]);
        sort(L.begin(), L.end());
        sort(R.rbegin(), R.rend());
        tmpans1 = tmpans = "";
        for (int t=m-1, f=0; t>=1; t--, f^=1) {
            tmpans1 += "P";
        }
        for (int t=m, f=0, pl=L.size(), pr=R.size(); t<=n && (pl>0 || pr>0); t++, f^=1) {
            if (f == 0) {   // S
                tmpans+="S";
                int d = t-m;
                pl -= d;
            }
            else {          // P
                tmpans += "P";
                int d = t-(n-m);
                pr -= d;
            }
            if (pl<=0 && pr<=0) {
                if (t < mnt) {
                    mnt = t;
                    ans1 = tmpans1;
                    ans2 = tmpans;
                }
                break;
            }
        }
    }
    else {

        // check P at m
        L.clear();
        R.clear();
        for (int i=1; i<=m; i++) if (a[i] > m) L.push_back(a[i]);
        for (int i=m+1; i<=n; i++) if (a[i] <= m) R.push_back(a[i]);
        sort(L.begin(), L.end());
        sort(R.rbegin(), R.rend());
        tmpans1 = tmpans = "";
        for (int t=m-1, f=0; t>=1; t--, f^=1) {
            tmpans1 += "S";
        }
        for (int t=m, f=0, pl=L.size(), pr=R.size(); t<=n && (pl>0 || pr>0); t++, f^=1) {
            if (f == 0) {   // P
                tmpans+="P";
                int d = t-m;
                pr -= d;
            }
            else {          // S
                tmpans += "S";
                int d = t - (n - m);
                pl -= d;
            }
            cout <<t <<" " << pl <<" " << pr <<endl;
            if (pl<=0 || pr<=0) {
                if (t < mnt) {
                    mnt = t;
                    ans1 = tmpans1;
                    ans2 = tmpans;
                }
                break;
            }
        }


        // check S at m
        L.clear();
        R.clear();
        for (int i=1; i<=m; i++) if (a[i] > m) L.push_back(a[i]);
        for (int i=m+1; i<=n; i++) if (a[i] <= m) R.push_back(a[i]);
        sort(L.begin(), L.end());
        sort(R.rbegin(), R.rend());
        tmpans1 = tmpans = "";
        for (int t=m-1, f=0; t>=1; t--, f^=1) {
            tmpans1 += "P";
        }
        //cout <<L.size() <<" " <<R.size() <<endl;
        for (int t=m, f=0, pl=L.size(), pr=R.size(); t<=n && (pl>0 || pr>0); t++, f^=1) {
            if (f == 0) {   // S
                tmpans+="S";
                int d = t-m;
                pl -= d;
            }
            else {          // P
                tmpans += "P";
                int d = t-(n-m);
                pr -= d;
            }
            if (pl<=0 || pr<=0) {
                if (t < mnt) {
                    mnt = t;
                    ans1 = tmpans1;
                    ans2 = tmpans;
                }
                break;
            }
        }
    }

    cout <<ans1  <<ans2 <<".\n";

}


int main() {
    ios::sync_with_stdio(false);
    cin >> n;
    for (int i = 1; i <= n; i++) {
        cin >> a[i];
    }
    int cntl = 0, cntr = 0;
    for (int i = 1; i <= (n / 2); i++) {
        cntl += (a[i] > (n + 1) / 2);
    }
    for (int i = ((n+1) / 2)+1; i <= n; i++) {
        cntr += (a[i] < (n + 1) / 2);
    }

    //assert(cntl == cntr);
    if (cntl == 0 && cntr == 0) {
        int max_l = 0, max_r = 0;
        for (int i = 1; i <= n; i++) {
            if (a[i] != i) {
                if (a[i] <= (n+1)/2 && i<=(n+1)/2) max_l = max(max_l, a[i]);
                if (a[i] >= (n+1)/2 && i>=(n+1)/2) max_r = max(max_r, n - a[i] + 1);
            }
        }
        if (max_l == 0 && max_r == 0) {
            cout << ".";
            return 0;
        }
        if (max_l == max_r) {
            max_l++;
        }
        int ans = max(max_l, max_r);
        if (max_l > max_r) {
            SP[ans] = 'P';
        } else {
            SP[ans] = 'S';
        }
        for (int i = 1; i <= ans - 1; i++) {
            SP[i] = (max_l > max_r ? 'S' : 'P');
        }
        for (int i = 1; i <= ans; i++) {
            cout << SP[i];
        }
        cout << ".\n";
        return 0;
    } else {

        fun();
        return 0;

        // not divide
        int last = (n + 1) / 2;
        string part2 = "";
        int cur = (a[(n + 1) / 2] <= (n + 1) / 2);
        int cover = 1 + n % 2;
        while (cntl > 0 || cntr > 0) {
            if (cur == 0) {
                cntl -= cover;
                part2 += 'S';
            } else {
                cntr -= cover;
                part2 += 'P';
            }
            cur ^= 1;
            cover++;
        }




    }

    return 0;
}

详细

Test #1:

score: 100
Accepted
time: 0ms
memory: 3560kb

input:

3
1 2 3

output:

.

result:

ok OK 0 operations

Test #2:

score: -100
Wrong Answer
time: 0ms
memory: 3552kb

input:

2
2 1

output:

1 1 1
2 0 1
PS.

result:

wrong answer Token "1" doesn't correspond to pattern "[PS]{0,1000001}."