QOJ.ac

QOJ

IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#240393#6434. Paimon SortingsfjhAC ✓266ms10200kbC++141.2kb2023-11-05 15:09:082023-11-05 15:09:09

Judging History

你现在查看的是最新测评结果

  • [2023-11-05 15:09:09]
  • 评测
  • 测评结果:AC
  • 用时:266ms
  • 内存:10200kb
  • [2023-11-05 15:09:08]
  • 提交

answer

#include<bits/stdc++.h> 
using namespace std;
#define fer(i,a,b) for(int i=a;i<=b;i++)
#define fdr(i,a,b) for(int i=a;i>=b;i--)
#define int long long
#define xx first
#define yy second
#define pb push_back
#define ps push
#define db double
#define P pair<int,int>
#define endl '\n'
#define ll long long
const int N=2e5+10;
const int mod=1e9+7;
priority_queue<int,vector<int>,greater<int>> pq;

int n;
int c[N];
int lowbit(int x){return x&(-x);}
int getsum(int x){int ans=0;while(x>0){ans+=c[x];x-=lowbit(x);}return ans;}
void add(int x,int k){while(x<=n){c[x]+=k;x+=lowbit(x);}}

int a[N];

void solve(){
	cin>>n;
	fer(i,1,n) cin>>a[i],c[i]=0;
	int ans=0;
	int mx=a[1];
	int pos=0;
	map<int,int> mp;
	fer(i,1,n){
		int preup=getsum(mx);
		int prelow=getsum(a[i]);
		int upnum=preup-prelow;
		if(a[i]>mx){
			if(mp[mx]>=2) ans+=i-pos;
			ans+=2;
			mx=a[i];
		}		
		else if(a[i]<=mx){
			ans+=upnum;
			if(a[i]==mx&&mp[mx]==1) pos=i;
		}
		mp[a[i]]++;
		if(mp[a[i]]==1) add(a[i],1);
		cout<<ans<<" \n"[i==n];
	}
}

signed main()
{
	ios::sync_with_stdio(0);cin.tie(0),cout.tie(0);
	int t;
	cin>>t;
	while(t--){
		solve(); 
	} 
}





















Details

Tip: Click on the bar to expand more detailed information

Test #1:

score: 100
Accepted
time: 0ms
memory: 3528kb

input:

3
5
2 3 2 1 5
3
1 2 3
1
1

output:

0 2 3 5 7
0 2 4
0

result:

ok 3 lines

Test #2:

score: 0
Accepted
time: 266ms
memory: 10200kb

input:

6107
19
10 13 8 8 11 18 12 9 15 19 6 13 11 11 17 9 14 2 18
12
1 8 10 2 10 2 6 1 5 9 5 7
16
14 4 2 15 12 14 10 3 2 9 15 4 12 9 5 15
10
3 2 5 6 7 8 6 1 6 4
18
6 5 12 12 11 2 10 10 5 10 13 15 13 10 17 7 11 2
1
1
2
1 1
3
2 1 2
17
11 15 3 10 7 15 15 10 5 17 3 3 14 13 11 11 2
3
2 2 3
7
6 1 7 5 3 5 1
7
2 1...

output:

0 2 4 6 7 9 11 16 17 19 28 31 36 41 43 51 55 67 68
0 2 4 6 6 8 10 14 17 18 22 25
0 1 3 5 7 8 11 16 22 26 26 31 33 37 42 42
0 1 3 5 7 9 11 17 19 23
0 1 3 3 4 8 10 12 16 18 27 29 30 34 36 42 46 55
0
0 0
0 1 1
0 2 4 6 9 9 9 11 15 21 27 33 35 38 42 46 55
0 0 3
0 1 3 5 8 10 14
0 1 3 4 6 9 9
0 1 1 3 7 11 ...

result:

ok 6107 lines