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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#236663#7513. Palindromic Beadsalpha1022WA 159ms277884kbC++144.4kb2023-11-04 09:39:472023-11-04 09:39:47

Judging History

你现在查看的是最新测评结果

  • [2024-03-27 16:34:54]
  • hack成功,自动添加数据
  • (/hack/584)
  • [2024-03-27 16:18:45]
  • hack成功,自动添加数据
  • (/hack/583)
  • [2023-11-04 09:39:47]
  • 评测
  • 测评结果:WA
  • 用时:159ms
  • 内存:277884kb
  • [2023-11-04 09:39:47]
  • 提交

answer

#include <bits/stdc++.h>

using namespace std;

const int inf = 0x3f3f3f3f;

const int N = 2e5;
const int LG = 20;

int n;
int a[N + 5];
pair<int, int> pos[N + 5];
vector<int> e[N + 5];
int fa[N + 5], anc[N + 5][LG], dep[N + 5], siz[N + 5], id[N + 5];
int f[N + 5];
void dfs1(int u) {
  static int tot = 0;
  id[u] = ++tot, siz[u] = 1, anc[u][0] = fa[u];
  for (int k = 1; k < LG; ++k) anc[u][k] = anc[anc[u][k - 1]][k - 1];
  for (int v: e[u])
    if (v != fa[u])
      fa[v] = u, dep[v] = dep[u] + 1, dfs1(v), siz[u] += siz[v];
}
int query(int u, int v) {
  for (int k = LG - 1; k >= 0; --k)
    if (dep[anc[u][k]] > dep[v]) u = anc[u][k];
  return u;
}
struct SegmentTree {
  #define ls (u << 1)
  #define rs (ls | 1)
  int seg[N * 4 + 5];
  void build(int u, int tl, int tr) {
    seg[u] = -inf;
    if (tl == tr) return ;
    int mid = (tl + tr) >> 1;
    build(ls, tl, mid), build(rs, mid + 1, tr);
  }
  void pushUp(int u) { seg[u] = max(seg[ls], seg[rs]); }
  void insert(int x, int k, int u, int tl, int tr) {
    if (tl == tr) { seg[u] = k; return ; }
    int mid = (tl + tr) >> 1;
    if (x <= mid) insert(x, k, ls, tl, mid);
    else insert(x, k, rs, mid + 1, tr);
    pushUp(u);
  }
  int query(int l, int u, int tl, int tr) {
    if (l <= tl) return seg[u];
    int mid = (tl + tr) >> 1;
    int ret = query(l, rs, mid + 1, tr);
    if (l <= mid) ret = max(ret, query(l, ls, tl, mid));
    return ret;
  }
  #undef ls
  #undef rs
} seg;

struct TreeOfTree {
  struct segnode { int val = -inf, ls, rs; } seg[N * 100 + 5];
  void update(int l, int r, int k, int &u, int tl, int tr) {
    if (l > r) return ;
    static int tot = 0;
    if (!u) u = ++tot;
    if (l <= tl && tr <= r) { seg[u].val = max(seg[u].val, k); return ; }
    int mid = (tl + tr) >> 1;
    if (l <= mid) update(l, r, k, seg[u].ls, tl, mid);
    if (r > mid) update(l, r, k, seg[u].rs, mid + 1, tr);
  }
  int query(int x, int u, int tl, int tr) {
    if (tl == tr) return seg[u].val;
    int mid = (tl + tr) >> 1;
    return max(seg[u].val, x <= mid ? query(x, seg[u].ls, tl, mid) : query(x, seg[u].rs, mid + 1, tr));
  }
  #define ls (u << 1)
  #define rs (ls | 1)
  int rt[N * 4 + 5];
  void update(int l, int r, int x, int y, int k, int u, int tl, int tr) {
    if (l > r || x > y) return ;
    if (l <= tl && tr <= r) { update(x, y, k, rt[u], 1, n); return ; }
    int mid = (tl + tr) >> 1;
    if (l <= mid) update(l, r, x, y, k, ls, tl, mid);
    if (r > mid) update(l, r, x, y, k, rs, mid + 1, tr);
  }
  int query(int x, int y, int u, int tl, int tr) {
    if (tl == tr) return query(y, rt[u], 1, n);
    int mid = (tl + tr) >> 1;
    return x <= mid ? query(x, y, ls, tl, mid) : query(x, y, rs, mid + 1, tr);
  }
  #undef ls
  #undef rs
} tree;

int up[N + 5];
void dfs2(int u) {
  if (up[u]) {
    f[a[u]] = 2 + (dep[up[u]] < dep[u] - 1);
    seg.insert(dep[up[u]], f[a[u]] = max(f[a[u]], seg.query(dep[up[u]], 1, 0, n - 1) + 2), 1, 0, n - 1);
    int v = query(u, up[u]);
    tree.update(1, id[v] - 1, id[u], id[u] + siz[u] - 1, f[a[u]], 1, 1, n), tree.update(id[u], id[u] + siz[u] - 1, id[v] + siz[v], f[a[u]], n, 1, 1, n);
  }
  for (int v: e[u])
    if (v != fa[u])
      dfs2(v);
  if (up[u]) seg.insert(dep[up[u]], -inf, 1, 0, n - 1);
}

int main() {
  scanf("%d", &n);
  for (int i = 1; i <= n; ++i) pos[i] = {n + 1, n + 1};
  for (int i = 1; i <= n; ++i) {
    int x; scanf("%d", &x), a[i] = x;
    if (pos[x].first <= n) pos[x].second = i;
    else pos[x].first = i;
  }
  for (int i = 2; i <= n; ++i) { int u, v; scanf("%d%d", &u, &v), e[u].push_back(v), e[v].push_back(u); }
  dfs1(1), id[n + 1] = n + 1;
  for (int i = 1; i <= n; ++i) {
    auto &[u, v] = pos[i];
    if (id[u] < id[v]) swap(u, v);
  }
  sort(pos + 1, pos + n + 1, [](pair<int, int> x, pair<int, int> y) { return id[x.first] < id[y.first]; });
  for (int i = 1; i <= n; ++i) {
    auto [u, v] = pos[i];
    if (v > n) continue;
    if (id[u] >= id[v] && id[u] < id[v] + siz[v]) a[u] = i, up[u] = v;
  }
  seg.build(1, 0, n - 1), dfs2(1);
  for (int i = 1; i <= n; ++i) {
    auto [u, v] = pos[i];
    if (v > n) continue;
    if (u > n) { f[i] = 1; continue; }
    if (id[u] >= id[v] && id[u] < id[v] + siz[v]) continue;
    tree.update(id[v], id[v] + siz[v] - 1, id[u], id[u] + siz[u] - 1, f[i] = max(3, tree.query(id[v], id[u], 1, 1, n) + 2), 1, 1, n);
  }
  printf("%d\n", *max_element(f + 1, f + n + 1));
}

详细

Test #1:

score: 100
Accepted
time: 11ms
memory: 253608kb

input:

4
1 1 2 2
1 2
2 3
2 4

output:

3

result:

ok single line: '3'

Test #2:

score: 0
Accepted
time: 8ms
memory: 253560kb

input:

5
1 3 2 2 1
1 2
2 3
3 4
4 5

output:

4

result:

ok single line: '4'

Test #3:

score: 0
Accepted
time: 7ms
memory: 252688kb

input:

6
1 1 2 2 3 3
1 2
2 3
3 4
4 5
5 6

output:

2

result:

ok single line: '2'

Test #4:

score: 0
Accepted
time: 3ms
memory: 253416kb

input:

6
1 2 3 4 5 6
1 2
2 3
3 4
4 5
5 6

output:

1

result:

ok single line: '1'

Test #5:

score: 0
Accepted
time: 7ms
memory: 253612kb

input:

2000
845 1171 345 282 1181 625 754 289 681 493 423 840 1494 318 266 1267 967 379 135 14 39 191 60 972 116 1216 1205 19 194 185 1360 861 379 430 1262 1151 756 65 389 488 277 53 1283 1438 101 1465 195 714 737 980 80 298 961 1326 163 1163 1317 1152 992 35 334 802 1502 486 710 234 555 88 1278 146 46 696...

output:

5

result:

ok single line: '5'

Test #6:

score: 0
Accepted
time: 153ms
memory: 277652kb

input:

200000
48015 47923 20609 71806 43752 68214 95683 89449 25809 58110 19878 52931 7845 45206 86245 82945 62977 37876 12456 105915 10509 92943 66950 88545 26442 26545 42278 66977 3970 9631 21524 43638 7979 58240 25719 56260 276 89721 9553 16550 52161 30307 82748 108443 36676 48581 59069 57412 62453 7965...

output:

5

result:

ok single line: '5'

Test #7:

score: -100
Wrong Answer
time: 159ms
memory: 277884kb

input:

200000
13011 51198 65374 107045 66506 14385 35784 94265 71449 41817 24646 60714 53382 68358 9354 840 3139 71282 72215 69550 2121 41498 13675 76444 67690 40513 56439 12832 51976 35333 47208 59602 98993 9383 77866 10464 41517 89125 58804 91741 66160 74208 70991 63865 84870 14282 2441 78046 73372 36311...

output:

5

result:

wrong answer 1st lines differ - expected: '7', found: '5'