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ID题目提交者结果用时内存语言文件大小提交时间测评时间
#236587#7521. Find the GapDawn_SdyWA 2ms3856kbC++141.9kb2023-11-04 08:32:262023-11-04 08:32:26

Judging History

你现在查看的是最新测评结果

  • [2023-11-04 08:32:26]
  • 评测
  • 测评结果:WA
  • 用时:2ms
  • 内存:3856kb
  • [2023-11-04 08:32:26]
  • 提交

answer

#include<bits/stdc++.h>
#define int long long
#define For(i, a, b) for (register int i = (a); i <= (b); ++i)
#define Rof(i, a, b) for (register int i = (a); i >= (b); --i)
#define For_Edge(i, x) for(register int i = head[x]; i; i = edge[i].nex)
#define fi first
#define se second
using namespace std;
inline int read() {
    int x = 0;
    char c = getchar();
    bool f = 0;
    while(!isdigit(c)) f |= (c == '-'), c = getchar();
    while(isdigit(c)) x = (x * 10) + (c ^ 48), c = getchar();
    return f ? -x : x;
}
inline void Checkmin(int &x, int y) { x = x < y ? x : y; }
inline void Checkmax(int &x, int y) { x = x > y ? x : y; }
const int maxn = 55;
const double INF = 1e18 + 7.0;
int n;
double Answer;
struct node {
    int x, y, z;
}Point[maxn];
inline node operator - (node x, node y) { return (node){x.x - y.x, x.y - y.y, x.z - y.z}; }
inline int operator ^ (node x, node y) { return x.x * y.x + x.y * y.y + x.z * y.z; }
inline node operator * (node x, node y) { return (node){x.y * y.z - x.z * y.y, x.z * y.x - x.x * y.z, x.x * y.y - x.y * y.x}; }
inline void Init() {
    n = read();
    For(i, 1, n) Point[i].x = read(), Point[i].y = read(), Point[i].z = read();
}
inline void Calc(node P) {
    if(!(P ^ P)) return ;
    int minn = INF, maxx = -INF;
    For(i, 1, n) Checkmin(minn, P ^ Point[i]), Checkmax(maxx, P ^ Point[i]);
    Answer = fmin(Answer, 1.0 * (maxx - minn) / sqrt(1.0 * (P ^ P)));
}
inline void Solve() {
    Answer = INF;
    For(i, 1, n) {
        For(j, i + 1, n) {
            For(i2, i, n) {
                For(j2, i2 + 1, n) {
                    node P1 = Point[j] - Point[i], P2 = Point[j2] - Point[i2], P = P1 * P2;
                    Calc(P);
                }
            }
        }
    }
    if(Answer >= INF) printf("-1\n");
    else printf("%0.12lf\n", Answer);
}
signed main() {
//    freopen("J.in", "r", stdin);
//    freopen("J.out", "w", stdout);
    Init(), Solve();
    return 0;
}

詳細信息

Test #1:

score: 100
Accepted
time: 0ms
memory: 3728kb

input:

8
1 1 1
1 1 2
1 2 1
1 2 2
2 1 1
2 1 2
2 2 1
2 2 2

output:

1.000000000000

result:

ok found '1.000000000', expected '1.000000000', error '0.000000000'

Test #2:

score: 0
Accepted
time: 0ms
memory: 3856kb

input:

5
1 1 1
1 2 1
1 1 2
1 2 2
2 1 1

output:

0.707106781187

result:

ok found '0.707106781', expected '0.707106781', error '0.000000000'

Test #3:

score: -100
Wrong Answer
time: 2ms
memory: 3624kb

input:

50
973 1799 4431
1036 1888 4509
1099 1977 4587
1162 2066 4665
1225 2155 4743
1288 2244 4821
1351 2333 4899
1414 2422 4977
1540 2600 5133
1603 2689 5211
1666 2778 5289
1729 2867 5367
1792 2956 5445
1855 3045 5523
1918 3134 5601
1981 3223 5679
2044 3312 5757
2107 3401 5835
2170 3490 5913
2296 3668 606...

output:

-1

result:

wrong answer 1st numbers differ - expected: '0.0000000', found: '-1.0000000', error = '1.0000000'