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IDProblemSubmitterResultTimeMemoryLanguageFile sizeSubmit timeJudge time
#236094#6398. Puzzle: TapaTimMCBen#RE 1ms3524kbC++204.8kb2023-11-03 16:21:432023-11-03 16:21:43

Judging History

你现在查看的是最新测评结果

  • [2023-11-03 16:21:43]
  • 评测
  • 测评结果:RE
  • 用时:1ms
  • 内存:3524kb
  • [2023-11-03 16:21:43]
  • 提交

answer

#include<bits/stdc++.h>
using namespace std;
const int N = 55;
char a[N][N];
char b[N][N];
struct node{
    int to;
};
struct eg{
    int x,y;
};
map<int,eg>mp;
vector<node>e[N];

int main()
{
    int n,m;
    cin>>n>>m;
    int fg=0;
    for(int i=1;i<=2*n-1;i++)
    {
        for(int j=1;j<=2*m-1;j++)
        {
            cin>>a[i][j];
            b[i][j]=a[i][j];
            if(a[i][j]=='.')
            {
                a[i][j]='#';
            }
            if(a[i][j]=='7')
            {
                fg=1;
            }
            if(isdigit(a[i][j])&&a[i][j]>='4')
            {
                a[i][j]-=2;
            }
        }
    }
    if(fg)
    {
        cout<<"NO"<<endl;
        return 0;
    }
/*     for(int i=1;i<=2*n-1;i++)
    {
        for(int j=1;j<=2*m-1;j++)
        {
            cout<<a[i][j];
            b[i][j]=a[i][j];
        }
        cout<<endl;
    } */
    int prev=0;
    int cnt=0;
    for(int i=1;i<=2*m-1;i++)
    {
        if(!isdigit(a[1][i]))
        {
            continue;
        }
        if(prev==0)
        {
            cnt++;
            prev=cnt;
            mp[cnt]={1,i};
        }else
        {
            ++cnt;
            //中间的可以用 []/2
            e[cnt].push_back({prev});
            mp[cnt]={1,i};
            prev=cnt;
        }
    }
    for(int i=2;i<=2*n-1;i++)
    {
        if(!isdigit(a[i][2*m-1]))
        {
            continue;
        }

        ++cnt;
        //中间的可以用 []/2
        e[cnt].push_back({prev});
        mp[cnt]={i,2*m-1};
        prev=cnt;
    }
    for(int i=2*m-2;i>=1;i--)
    {
        if(!isdigit(a[2*n-1][i]))
        {
            continue;
        }
        ++cnt;
        //中间的可以用 []/2
        e[cnt].push_back({prev});
        mp[cnt]={2*n-1,i};
        prev=cnt;
    }
    for(int i=2*n-2;i>=1;i--)
    {
        if(!isdigit(a[i][1]))
        {
            continue;
        }
        ++cnt;

        if(i==1)
        {
            e[1].push_back({prev});
            cnt--;
            break;
        }
        //中间的可以用 []/2
        e[cnt].push_back({prev});
        mp[cnt]={i,1};
        prev=cnt;
    }

/*     for(int i=1;i<=cnt;i++)
    {
        cout<<i<<" "<<mp[i].x<<" "<<mp[i].y<<endl;
        int last=e[i][0].to;
        cout<<e[i][0].to<<"-"<<(mp[i].x+mp[last].x)/2<<" "<<(mp[i].y+mp[last].y)/2<<endl;
    } */

    int st=0;
    for(int i=1;i<=cnt;i++)
    {
        //得到3然后往下一个走
        if(a[mp[i].x][mp[i].y]=='3')
        {
            st=i;
            break;
        }
    }

    if(st==0)
    {
        int f=0;
        for(int i=1;i<=cnt;i++)
        {
            int last=e[i][0].to;
            int xx=(mp[i].x+mp[last].x)/2;
            int yy=(mp[i].y+mp[last].y)/2;
            if(f)
            {
                a[xx][yy]='.';
            }else
            {
                a[xx][yy]='#';
            }
            f^=1;
        }
        cout<<"YES"<<endl;
        for(int i=1;i<=2*n-1;i++)
        {
            for(int j=1;j<=(2*m-1);j++)
            {
                if(isdigit(a[i][j]))
                {
                    cout<<b[i][j];
                }else
                {
                    cout<<a[i][j];
                }   
            }
            cout<<endl;
        }
    }else
    {
        int f=0;
        int fg=0;
        for(int i=st;((i+cnt-1-1)%cnt+1)!=st;i=(i+cnt-1-1)%cnt+1)
        {
            //对象
            int last=e[i][0].to;
            int xx=(mp[i].x+mp[last].x)/2;
            int yy=(mp[i].y+mp[last].y)/2;
            //若f=1 用#
            if(a[mp[last].x][mp[last].y]=='2')
            {
                //2
                if(f)
                {
                    a[xx][yy]='.';
                }else
                {
                    a[xx][yy]='#';
                }  
                f^=1;              
            }else
            {
                if(f)
                {
                    //不行!
                    fg=1;
                    break;
                }else
                {
                    a[xx][yy]='#';
                    //并且f要保持不变
                }   
            }
        }
        if(fg)
        {
            cout<<"NO"<<endl;
            return 0;
        }
        cout<<"YES"<<endl;
        for(int i=1;i<=2*n-1;i++)
        {
            for(int j=1;j<=(2*m-1);j++)
            {
                if(isdigit(a[i][j]))
                {
                    cout<<b[i][j];
                }else
                {
                    cout<<a[i][j];
                }   
            }
            cout<<endl;
        }
    }
}
/*
3 3
2.4.2
.....
4.8.4
.....
2.4.2
*/

Details

Tip: Click on the bar to expand more detailed information

Test #1:

score: 100
Accepted
time: 0ms
memory: 3336kb

input:

3 3
2.4.3
.....
5.8.5
.....
3.5.3

output:

YES
2.4#3
#####
5#8#5
#####
3#5#3

result:

ok Correct.

Test #2:

score: 0
Accepted
time: 0ms
memory: 3408kb

input:

3 3
3.4.3
.....
5.7.5
.....
3.5.3

output:

NO

result:

ok Correct.

Test #3:

score: 0
Accepted
time: 1ms
memory: 3524kb

input:

2 2
2.2
...
2.2

output:

YES
2.2
###
2.2

result:

ok Correct.

Test #4:

score: -100
Runtime Error

input:

2 50
2.4.4.4.4.5.5.5.5.5.5.5.5.4.5.5.4.4.5.5.5.5.4.5.5.5.5.5.4.4.5.4.5.5.5.5.5.5.5.5.5.5.5.4.4.5.5.4.5.3
...................................................................................................
2.5.5.4.4.5.5.5.4.4.5.5.5.4.5.5.5.5.5.5.5.5.4.4.4.5.5.5.5.5.5.4.4.4.5.5.5.5.5.5.5.4.4.5.5.5.5.4...

output:


result: