QOJ.ac
QOJ
ID | Problem | Submitter | Result | Time | Memory | Language | File size | Submit time | Judge time |
---|---|---|---|---|---|---|---|---|---|
#236093 | #6705. Median | stcmuyi# | AC ✓ | 5ms | 3720kb | C++20 | 2.3kb | 2023-11-03 16:21:07 | 2023-11-03 16:21:08 |
Judging History
answer
#include <bits/stdc++.h>
#define IOS ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);
#define i64 long long
#define endl '\n'
#define lb(x) ((x) & (-x))
using namespace std;
const i64 mod = 1e15+7;
const int maxn = 1e3+10;
signed main()
{
IOS;
int t; cin >> t;
while(t--)
{
int n,m; cin >> n >> m;
vector<int> deg(n+1);
vector<vector<int>> l(n+1),r(n+1);
for(int i = 1; i <= m; ++i)
{
int x,y; cin >> x >> y;
l[x].push_back(y);
deg[y]++;
r[y].push_back(x);
}
queue<int> q;
for(int i = 1; i <= n; ++i) if(deg[i] == 0) q.push(i);
int ans = 0;
while(q.size())
{
int x = q.front();
q.pop();
ans++;
for(auto it : l[x])
{
deg[it]--;
if(deg[it] == 0) q.push(it);
}
}
if(ans != n)
{
for(int i = 0; i < n; ++i) cout << 0;
cout << endl;
}
else
{
vector<int> lcnt(n+1),rcnt(n+1);
vector<int> vis(n+1);
auto dfsl = [&](auto self,int x) -> void
{
if(vis[x]) return;
vis[x] = 1;
for(int &u : l[x]) self(self,u);
};
auto dfsr = [&](auto self,int x) -> void
{
if(vis[x]) return;
vis[x] = 1;
for(int &u : r[x]) self(self,u);
};
for(int i = 1; i <= n; ++i)
{
fill(vis.begin(),vis.end(),0);
dfsl(dfsl,i);
for(int j = 1; j <= n; ++j) lcnt[i] += vis[j];
lcnt[i]--;
}
for(int i = 1; i <= n; ++i)
{
fill(vis.begin(),vis.end(),0);
dfsr(dfsr,i);
for(int j = 1; j <= n; ++j) rcnt[i] += vis[j];
rcnt[i]--;
}
for(int i = 1; i <= n; ++i)
{
if(lcnt[i] <= n/2 && rcnt[i] <= n/2) cout << 1;
else cout << 0;
}
cout << endl;
}
}
return 0;
}
这程序好像有点Bug,我给组数据试试?
Details
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Test #1:
score: 100
Accepted
time: 0ms
memory: 3616kb
input:
2 5 4 1 2 3 2 2 4 2 5 3 2 1 1 2 3
output:
01000 000
result:
ok 2 lines
Test #2:
score: 0
Accepted
time: 5ms
memory: 3720kb
input:
66 13 2 9 13 7 11 11 19 9 1 8 1 5 1 2 8 4 2 2 1 5 2 6 3 3 11 3 2 4 6 6 10 9 8 3 5 1 7 5 8 3 9 4 9 6 7 3 1 2 3 11 6 9 4 1 6 5 2 1 5 4 6 8 4 15 15 10 6 15 8 7 6 11 1 5 2 3 4 11 13 4 6 10 12 10 13 1 6 15 2 5 12 13 14 5 3 15 86 14 12 8 1 14 9 8 15 5 10 1 9 11 2 6 2 7 10 10 13 14 5 4 13 5 8 4 10 13 9 6 9...
output:
1111111111111 01001000111 111 11111111111 111111111111111 001001000000000 00100 01100 1111111 1000000000000 111101101 111111111 000011111011101 010111111 001100000 0100001001101 1111111111111 001000010000000 10010111011 001000000000100 11111111111 00100000011 11111 01000000110 11101110111 00000 1111...
result:
ok 66 lines