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QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#233784 | #6633. Exam Requirements | ugly2333 | ML | 35ms | 345824kb | C++20 | 2.3kb | 2023-10-31 22:57:45 | 2023-10-31 22:57:46 |
Judging History
answer
//Δ_C
#include<bits/stdc++.h>
using namespace std;
typedef long long LL;
typedef double DB;
const int N = 222222;
const int W = N<<5;
int n,m,w,a[N],b[N],p[N],e[N];
vector<int> v[W],r[W];
void ins(int x,int y){
v[x].push_back(y);//cout<<x<<' '<<y<<endl;
r[y].push_back(x);
}
bool cmpa(int i,int j){
return a[i]<a[j]||(a[i]==a[j]&&i<j);
}
bool cmpb(int i,int j){
return b[i]<b[j];
}
vector<int> c;
int sz,t[1<<19];
void build(int k=1,int l=0,int r=sz){
t[k]=++w;
if(l==r){
if(c[l]<=n)
ins(t[k],c[l]);
return;
}
int h=l+r>>1;
build(k<<1,l,h);
build(k<<1|1,h+1,r);
ins(t[k],t[k<<1]);
ins(t[k],t[k<<1|1]);
}
void query(int L,int R,int X,int k=1,int l=0,int r=sz){
if(L>R)
return;
if(L<=l&&r<=R){
ins(X,t[k]);
return;
}
int h=l+r>>1;
if(L<=h)
query(L,R,X,k<<1,l,h);
if(h<R)
query(L,R,X,k<<1|1,h+1,r);
}
void solve(int l,int r){
if(l==r)
return;
int h=l+r>>1,i,j,x;
solve(l,h);
solve(h+1,r);
c.clear();
for(i=l;i<=h;i++)
c.push_back(p[i]),e[p[i]]=i;
sz=c.size()-1;
build();
for(i=l,j=h+1;i<=h||j<=r;){
if(i<=h&&(j>r||b[p[i]]<b[p[j]])){
i++;
}
else{
if(p[j]>n){
x=e[p[j]-n];
if(x&&x>=i){
query(i-l,x-l-1,p[j]);
query(x-l+1,h-l,p[j]);
}
else
query(i-l,h-l,p[j]);
}
j++;
}
}
for(i=l;i<=h;i++)
e[p[i]]=0;
sort(p+l,p+r+1,cmpb);
}
int tt,d[W],f[W];
void dfsr(int u){
if(f[u])
return;
f[u]=1;
int i,x;
for(i=0;i<r[u].size();i++){
x=r[u][i];
dfsr(x);
}
d[++tt]=u;
}
void dfsv(int u,int ff){
if(f[u])
return;
f[u]=ff;
int i,x;
for(i=0;i<v[u].size();i++){
x=v[u][i];
dfsv(x,ff);
}
}
int main(){
int T,i,x,y;
scanf("%d",&T);
while(T--){
scanf("%d%d",&n,&m);
for(i=1;i<=n;i++){
scanf("%d%d",a+i,b+i);
a[n+i]=b[i],b[n+i]=a[i];
}
for(i=1;i<=m;i++){
scanf("%d%d",&x,&y);
ins(x,n+y);
ins(y,n+x);
}
for(i=1;i<=n*2;i++)
p[i]=i;
sort(p+1,p+n*2+1,cmpa);
w=n*2;
solve(1,n*2);
tt=0;
for(i=1;i<=w;i++)
dfsr(i);
for(i=1;i<=w;i++)
f[i]=0;
for(i=w;i>=1;i--)
dfsv(d[i],d[i]);
x=1;
for(i=1;i<=n;i++)
if(f[i]==f[n+i])
x=0;
if(x)
printf("YES\n");
else
printf("NO\n");
for(i=1;i<=w;i++)
v[i].clear(),r[i].clear(),d[i]=0,f[i]=0;
}
return 0;
}
详细
Test #1:
score: 100
Accepted
time: 35ms
memory: 345824kb
input:
2 3 1 1 5 2 7 10 11 2 1 3 3 1 5 2 7 5 7 1 2 2 3 3 1
output:
YES NO
result:
ok 2 lines
Test #2:
score: -100
Memory Limit Exceeded
input:
1 100000 100000 15084647 15220430 217541056 217598054 222963701 223110976 71224450 71340221 320463268 320631387 334861459 334924668 328950591 329083669 178996498 178996584 428529461 428605033 405428435 405504132 197936687 197947412 9058562 9190197 169407597 169474101 297518153 297590927 31471874 316...
output:
NO