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QOJ
| ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
|---|---|---|---|---|---|---|---|---|---|
| #233738 | #6632. Minimize Median | ugly2333 | WA | 75ms | 5980kb | C++20 | 712b | 2023-10-31 21:55:29 | 2023-10-31 21:55:29 |
Judging History
answer
//Δ_B
#include<bits/stdc++.h>
using namespace std;
typedef long long LL;
typedef double DB;
const int N = 1111111;
const int inf = 1e9+N;
int n,m,k,a[N],c[N];
int main(){
int T,i,j,l,r,h,x;
scanf("%d",&T);
while(T--){
scanf("%d%d%d",&n,&m,&k);
for(i=1;i<=n;i++)
scanf("%d",a+i);
sort(a+1,a+n+1);
n=n/2+1;
for(i=1;i<=m;i++)
scanf("%d",c+i);
c[1]=0;
m++;
c[m]=inf;
for(i=1;i<=m;i++)
for(j=1;i*j<m+i;j++)
c[min(i*j,m)]=min(c[min(i*j,m)],c[i]+c[j]);
l=0,r=m;
while(l<r){
h=l+r>>1;
x=k;
for(i=1;i<=n;i++)
if(x>=0)
x-=c[(a[i]+1+h)/(h+1)];
if(x>=0)
r=h;
else
l=h+1;
}
printf("%d\n",l);
}
return 0;
}
詳細信息
Test #1:
score: 100
Accepted
time: 0ms
memory: 5980kb
input:
3 3 5 0 2 5 2 3 2 4 6 13 3 5 3 2 5 3 3 2 4 6 13 3 5 6 2 5 2 3 2 4 6 13
output:
2 2 1
result:
ok 3 number(s): "2 2 1"
Test #2:
score: -100
Wrong Answer
time: 75ms
memory: 5848kb
input:
100000 5 10 5 3 7 1 10 10 11 6 11 6 1 8 9 1 3 1 5 6 51 2 2 2 5 1 42 61 26 59 100 54 5 10 76 7 5 8 4 7 97 4 44 83 61 45 24 88 44 44 5 8 90 1 1 5 1 3 35 15 53 97 71 83 26 7 5 3 52 1 1 3 1 1 22 6 93 5 6 28 6 6 1 3 1 9 31 2 19 10 27 5 8 31 3 6 2 1 2 32 29 13 7 57 34 9 5 5 6 75 3 3 4 5 4 40 56 38 60 17 3...
output:
7 2 2 0 0 3 2 3 3 4 2 4 2 2 3 1 4 4 2 2 3 2 0 3 2 1 2 3 3 5 6 0 3 6 3 2 2 1 1 3 6 5 2 0 3 4 1 1 2 0 2 4 0 8 6 4 0 4 5 1 1 5 1 4 1 4 3 7 1 2 6 4 1 1 1 1 2 1 0 4 7 4 4 8 3 2 1 2 2 1 4 3 1 4 4 1 5 2 4 0 2 2 2 1 2 2 0 2 1 1 1 0 1 0 4 2 2 4 4 1 4 1 2 1 2 4 2 6 3 3 2 6 7 2 4 1 3 1 1 1 2 1 7 1 1 2 3 2 3 5 ...
result:
wrong answer 1st numbers differ - expected: '0', found: '7'