QOJ.ac
QOJ
ID | 题目 | 提交者 | 结果 | 用时 | 内存 | 语言 | 文件大小 | 提交时间 | 测评时间 |
---|---|---|---|---|---|---|---|---|---|
#230224 | #7640. Colorful Cycles | ucup-team052# | WA | 53ms | 40468kb | C++14 | 2.9kb | 2023-10-28 17:55:07 | 2023-10-28 17:55:07 |
Judging History
answer
#include<bits/stdc++.h>
#ifdef xay5421
#define D(...) fprintf(stderr,__VA_ARGS__)
#define DD(...) D(#__VA_ARGS__ "="),debug_helper::debug(__VA_ARGS__),D("\n")
#include"/home/xay5421/debug.hpp"
#else
#define D(...) ((void)0)
#define DD(...) ((void)0)
#endif
#define pb push_back
#define eb emplace_back
#define SZ(x) ((int)(x).size())
#define each(x,v) for(auto&x:v)
#define rep(i,a,b) for(int i=(a);i<=(b);++i)
#define per(i,a,b) for(int i=(a);i>=(b);--i)
template<class T>void rd(T&x){int f=0,c;while(!isdigit(c=getchar()))f^=!(c^45);x=(c&15);while(isdigit(c=getchar()))x=x*10+(c&15);if(f)x=-x;}
template<class T>void pt(T x,int c=-1){if(x<0)putchar('-'),x=-x;if(x>9)pt(x/10);putchar(x%10+48);if(c!=-1)putchar(c);}
using namespace std;
using LL=long long;
using ULL=unsigned long long;
const int N=1000005;
int T,n,m,eu[N],ev[N],ew[N];
int last[N],fa[N];
int find(int u){return u==fa[u]?u:fa[u]=find(fa[u]);}
vector<pair<int,int> >e[N];
int dfn[N],low[N],idx,st[N],top;
vector<pair<vector<int>,int> >vvs;
bool vis[N];
void tarjan(int u){
dfn[u]=low[u]=++idx;
st[++top]=u;
for(auto&[v,w]:e[u]){
if(!dfn[v]){
tarjan(v);
low[u]=min(low[u],low[v]);
if(low[v]>=dfn[u]){
vector<int>vs;
do{
vs.pb(st[top]);
}while(st[top--]!=v);
vvs.eb(vs,u);
}
}else{
low[u]=min(low[u],dfn[v]);
}
}
}
int main(){
#ifdef xay5421
freopen("a.in","r",stdin);
#endif
rd(T);
while(T--){
rd(n),rd(m);
rep(i,1,n)last[i]=-1,fa[i]=i;
vvs.clear();
rep(i,1,m){
int u,v,w;
rd(u),rd(v),rd(w);
e[u].eb(v,w);
e[v].eb(u,w);
eu[i]=u,ev[i]=v,ew[i]=w;
if(last[u]==-1){
last[u]=w;
}else if(last[u]!=w){
last[u]=0;
}
if(last[v]==-1){
last[v]=w;
}else if(last[v]!=w){
last[v]=0;
}
}
rep(u,1,n){
if(last[u]>0){
for(auto&[v,w]:e[u]){
fa[find(u)]=find(v);
}
}
}
rep(i,1,n)e[i].clear();
rep(i,1,m){
eu[i]=find(eu[i]);
ev[i]=find(ev[i]);
e[eu[i]].eb(ev[i],ew[i]);
e[ev[i]].eb(eu[i],ew[i]);
}
top=0;
rep(i,1,n)if(!dfn[i]){
tarjan(i);
}
bool ok=0;
for(auto &[vs,u]:vvs){
vis[u]=1;
last[u]=-1;
fa[u]=u;
for(auto &v:vs){
vis[v]=1;
last[v]=-1;
fa[v]=v;
}
auto push=[&](int x,int y){
if(last[x]==-1)last[x]=y;
if(last[x]!=y)last[x]=0;
};
for(auto &v:vs){
for(auto &[v_,w]:e[v]){
if(vis[v_]){
push(v,w);
push(v_,w);
}
}
}
for(auto &v:vs){
for(auto &[v_,w]:e[v]){
if(last[v]>0){
fa[find(v)]=find(v_);
}
if(last[u]>0&&v_==u){
fa[find(v)]=find(v_);
}
}
}
int tot=find(u)==u;
for(auto &v:vs){
tot+=find(v)==v;
}
if(tot>2){
ok=1;
}
vis[u]=0;
for(auto &v:vs){
vis[v]=0;
}
}
if(ok)puts("Yes");else puts("No");
}
return 0;
}
详细
Test #1:
score: 100
Accepted
time: 2ms
memory: 40468kb
input:
2 3 3 1 2 3 2 3 1 1 3 2 5 6 1 2 1 2 3 1 1 3 2 3 4 3 3 5 3 4 5 3
output:
Yes No
result:
ok 2 token(s): yes count is 1, no count is 1
Test #2:
score: -100
Wrong Answer
time: 53ms
memory: 36396kb
input:
100000 7 10 7 2 2 6 4 2 6 1 2 7 1 3 3 4 1 6 7 1 2 6 3 3 1 2 5 3 1 2 1 1 7 10 5 7 3 7 1 1 4 6 3 6 3 1 3 4 3 4 2 2 3 2 3 1 3 3 3 7 1 1 4 2 7 10 5 6 3 3 5 2 7 2 3 7 3 3 1 2 2 4 3 2 7 4 2 6 1 2 2 6 1 7 5 2 7 10 7 1 3 7 5 3 6 4 1 7 6 1 1 4 1 3 4 2 2 7 2 1 3 1 3 5 3 5 1 3 7 10 6 7 2 3 4 3 1 4 2 5 3 2 7 4 ...
output:
Yes No No No No No No No No No No No No No No No No No No No No No No No No No No No No No No No No No No No No No No No No No No No No No No No No No No No No No No No No No No No No No No No No No No No No No No No No No No No No No No No No No No No No No No No No No No No No No No No No No No No...
result:
wrong answer expected YES, found NO [2nd token]